Chapter 26, Problem 76RPP

To determine

The option which is the closest to the distance of Earth from $3\text{C 273}$ quasar in terms of Earth-Sun distance, from the given options, when the quasar is receding from Earth at a speed of about $0.16\text{c}$ and emits the radiation with the power of $2\times {10}^{13}\text{ Suns}$, the distance between the Sun and Earth is $1.5\times {10}^{11}\text{ m}$, and the Sun emits the energy at a rate of $3.8\times {10}^{26}\text{ J/s}$ by converting $4.3\times {10}^9\text{ kg/s}$ of mass into light. The value of Hubble’s constant is $70.8\frac{\text{km/s}}{\text{Mpc}}$.

a. $\approx {\text{ 10}}^{\text{3}}\text{ Sun distances}$

b. $\approx {\text{ 10}}^6\text{ Sun distances}$

c. $\approx {\text{ 10}}^9\text{ Sun distances}$

d. $\approx {\text{ 10}}^{12}\text{ Sun distances}$

e. $\approx {\text{ 10}}^{14}\text{ Sun distances}$