Physics (5th Edition)
5th Edition
ISBN: 9780321976444
Author: James S. Walker
Publisher: PEARSON
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Textbook Question
Chapter 2.6, Problem 6EYU
A submerged alligator swims directly toward two unsuspecting ducks. The equation of motion of the alligator is xa = (0.25 m/s2) t2, the equation of motion of duck 1 is xd1 = 3 m − (1.5 m/s)t, and the equation of motion of duck 2 is xd2 = 3 m + (1 m/s) t. Which duck does the alligator encounter first?
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Four capacitors are connected as shown in the figure below. (Let C = 12.0 μF.)
a
C
3.00 με
Hh.
6.00 με
20.0 με
HE
(a) Find the equivalent capacitance between points a and b.
5.92
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(b) Calculate the charge on each capacitor, taking AV ab = 16.0 V.
20.0 uF capacitor 94.7
6.00 uF capacitor 67.6
32.14
3.00 µF capacitor
capacitor C
☑
με
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The 3 µF and 12.0 uF capacitors are in series and that combination is in parallel with the 6 μF capacitor. What quantity is the same for capacitors in parallel? μC
32.14
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You are correct that the charge on this capacitor will be the same as the charge on the 3 μF capacitor. μC
In the pivot assignment, we observed waves moving on a string stretched by hanging
weights. We noticed that certain frequencies produced standing waves. One such
situation is shown below:
0 ст
Direct Measurement
©2015 Peter Bohacek I.
20
0 cm 10
20
30
40
50
60
70
80
90
100
Which Harmonic is this?
Do NOT include units!
What is the wavelength of this wave in cm with only no decimal places?
If the speed of this wave is 2500 cm/s, what is the frequency of this harmonic (in Hz, with
NO decimal places)?
Four capacitors are connected as shown in the figure below. (Let C = 12.0 µF.)
A circuit consists of four capacitors. It begins at point a before the wire splits in two directions. On the upper split, there is a capacitor C followed by a 3.00 µF capacitor. On the lower split, there is a 6.00 µF capacitor. The two splits reconnect and are followed by a 20.0 µF capacitor, which is then followed by point b.
(a) Find the equivalent capacitance between points a and b. µF(b) Calculate the charge on each capacitor, taking ΔVab = 16.0 V.
20.0 µF capacitor
µC
6.00 µF capacitor
µC
3.00 µF capacitor
µC
capacitor C
µC
Chapter 2 Solutions
Physics (5th Edition)
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