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Electric Motor Control
10th Edition
ISBN: 9781133702818
Author: Herman
Publisher: CENGAGE L
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Textbook Question
Chapter 26, Problem 4SQ
How may additional steps of acceleration be added?
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Chapter 26 Solutions
Electric Motor Control
Ch. 26 - What is the purpose of inserting resistance in the...Ch. 26 - Why is the power not interrupted when the motor...Ch. 26 - If the starter is to function properly and a...Ch. 26 - How may additional steps of acceleration be added?Ch. 26 - What is meant by the low or poor starting economy...Ch. 26 - Prob. 6SQ
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- A.With the aid of a diagram, describe fringing, and explain the impact that it has on the relevant magnetic circuit parameter. B. A coil of 1500 turns give rise to a magnetic flux of 2.5 mWb when carrying a certain current. If this current is reversed in 0.2 s, what is the average value of the e.m.f. induced in the coil? C.Define Mutual Inductance.Two coils are connected in series and their total inductance is measured as 0.12 H, and when the connection to one coil is reversed, the total inductance is measured as 0.04 H. If the coefficient of coupling is 0.8, determine:The self-inductance of each coil, and the mutual inductance between the coils.arrow_forwardcomparing Lenz's law and the left hand generator rule, which of these is the more important fundamental principle?arrow_forwardExample: Electric Field and Potential Inside a Charged Sphere Problem: A sphere of radius R = 0.2 m is uniformly charged with a total charge Q = 5 μC. The sphere is made of a dielectric material with relative permittivity € = 4. Calculate: 1. The electric field intensity E(r) inside and outside the sphere. 2. The electric potential (r) at any point inside the sphere. Solution: Step 1: Given Data Radius of the sphere: R = 0.2m, Total charge: Q-5 μC=5× 10° C. Step 2: Electric Field Inside the Sphere (< Using Gauss's Law:arrow_forwardplease remember to draw the circuitsarrow_forwardA balanced three-phase, A - connected induction motor consumes 3246 W when the l voltage is 208 V, and the line current is 10.6 A. Calculate: i. The motor's winding resistance. ii. The motor's winding reactance. 12 marrow_forwarda) An iron ring, having a mean circumference of 250 mm and a cross-sectional area of 400 mm², is wound with a coil of 70 turns. Using the following data, calculate the current required to set up a flux of 510µWb in the ring. H (A/m) 350 600 1250 B (T) 1.0 1.2 1.4 b) Calculate also: i. The inductance of the coil at the current obtained in Question 2 (a) above. ii. The self-induced e.m.f. if this current is switched off in 0.005 s. Assume that there is no residual flux.arrow_forwardA balanced three-phase, 1351-V, 60-Hz, A-connected source feeds a balanced Y- connected load with a per-phase impedance of 360 + j150 Q as shown in Figure 1. Calculate: i. The readings on each of the wattmeters ii. The power factor of the load using the wattmeter readings. NOTE: i. ii. Let VAN be the reference phasor, and the phase sequence be ABC anticlockwise. Assume the voltage-drop on the conductors between the source and the load to be zero volts. V b V₁ W 000 000 ; A 360 + j150 360 + j150 4 b 0000 000 B 360 + j150 C W₂ Figure 1arrow_forwarda) Three 30 2 resistors are arranged as shown in Figure 1 below. They are connected to a 480 V three-phase supply. The phase sequence is RYB anticlockwise. Calculate: i. The total power drawn by the circuit using the phase parameters. ii. The power read by each wattmeter. b) If Za, one of the 30 2 resistors, is now removed from the circuit, calculate: R- i. The line currents: IR, Iv, and la ii. The power read by each wattmeter. iii. The total power drawn by the two resistors. W₁ Be- W2 www 'R 22 12 B Figure 1arrow_forwardA certain magnetic circuit may be regarded as consisting of three parts, A, B and C in series, each one of which has a uniform cross-sectional area. Part A has a length of 300 mm and a cross- sectional area of 450 mm². Part B has a length of 120 mm and a cross-sectional area of 300 mm². Part C is an airgap 1.0 mm in length and of cross-sectional area 350 mm². The flux in the airgap is 0.35 mWb. Neglect magnetic leakage and fringing. The magnetic characteristic for parts A and B is given by: H (A/m) 400 560 800 1280 1800 B (T) 0.7 0.85 1.0 1.15 1.25 Calculate: i. The reluctance of each part, that is, of Part A, Part B, and Part C ii. The total reluctance of the magnetic circuit. iii. The total m.m.f.arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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