Explanation Given: A limit: lim θ → 0 sin ( 2 θ ) − 2 sin ( θ ) θ 2 . Calculation: Upon substituting sin ( 2 θ ) = 2 sin ( θ ) cos ( θ ) in our given function, we will get: lim x → 0 2 sin ( θ ) cos ( θ ) − 2 sin ( θ ) θ 2 Now, we can rewrite our given limit as: lim θ → 0 2 sin ( θ ) cos ( θ ) − 2 sin ( θ ) θ 2 = lim θ → 0 2 sin ( θ ) ( cos ( θ ) − 1 ) θ 2 = lim θ → 0 2 sin ( θ ) θ ⋅ ( cos ( θ

4th Edition

ISBN: 9781319309671

Author: Rogawski

Publisher: MAC HIGHER

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Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topic…

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Question

Chapter 2.6, Problem 49E

To determine

To evaluate:

The given limit using property sin(2θ)=2sin(θ)cos(θ).

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Chapter 2.6, Problem 48E

Chapter 2.6, Problem 50E

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Chapter 2 Solutions

CALCULUS: EARLY TRANS 4TH ED W/ ACCESS

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