EP PRE-ALGEBRA,COMMON CORE-1 YEAR CODE
12th Edition
ISBN: 9780547615011
Author: Larson
Publisher: HM HS
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Question
Chapter 2.6, Problem 39E
a.
To determine
An expression in terms of
a.
Expert Solution
Answer to Problem 39E
The amount of wheat that should be replaced by the horse’s owner is
The amount of wheat thatshould be replaced by the cow’s owner is
Explanation of Solution
Given:
A goat, a horse and a cow eats a farmer’s stalk of wheat.
The horse eats twice as many stalks as the goat.
The cow eats twice as many stalks as the horse.
The farmer demands
Consider
Calculation:
As per the given problem
Consider
The horse eats twice as many stalks as the goat. Therefore, in terms of
The cow eats twice as many stalks as the horse.Therefore, in terms of
Hence,
The horse’s owner has to replace
Conclusion:
The amount of wheat that should be replaced by the horse’s owner is
The amount of wheat that should be replaced by the cow’s owner is
b.
To determine
The value of
b.
Expert Solution
Answer to Problem 39E
The value of
Amount of wheat to be replaced by the goat’s owner =
Amount of wheat to be replaced by the horse’s owner =
Amount of wheat to be replaced by the cow’s owner =
Explanation of Solution
Given:
The goat’s owner has to replace
The cow’s owner has to replace
The total amount of wheat demanded by the farmer is
Concept used:
The sum of the amounts of wheat to be replaced by each animal’s owner is equal to the amount of wheat demanded by the farmer.
Calculation:
As per the given problem
Amount of wheat to be replaced by the goat’s owner =
Amount of wheat to be replaced by the horse’s owner =
Amount of wheat to be replaced by the cow’s owner =
The total amount of wheat demanded by the farmer =
The sum of the amounts of wheat to be replaced by each animal’s owner is equal to the amount of wheat demanded by the farmer.
Writing an equation using the above information,
Adding the like terms on the right hand side of the equation:
Dividing each side by
Therefore,
Hence,
The value of
Amount of wheat to be replaced by the goat’s owner =
Amount of wheat to be replaced by the horse’s owner =
Amount of wheat to be replaced by the cow’s owner =
Rounding off the answers to the nearest tenth of a tou,
Amount of wheat to be replaced by the goat’s owner =
Amount of wheat to be replaced by the horse’s owner =
Amount of wheat to be replaced by the cow’s owner =
Conclusion:
The value of
Amount of wheat to be replaced by the goat’s owner =
Amount of wheat to be replaced by the horse’s owner =
Amount of wheat to be replaced by the cow’s owner =
Chapter 2 Solutions
EP PRE-ALGEBRA,COMMON CORE-1 YEAR CODE
Ch. 2.1 - Prob. 1PSQCh. 2.1 - Prob. 2PSQCh. 2.1 - Prob. 3PSQCh. 2.1 - Prob. 4PSQCh. 2.1 - Prob. 5PSQCh. 2.1 - Prob. 6PSQCh. 2.1 - Prob. 7PSQCh. 2.1 - Prob. 8PSQCh. 2.1 - Prob. 9PSQCh. 2.1 - Prob. 10PSQ
Ch. 2.1 - Prob. 11PSQCh. 2.1 - Prob. 1CCh. 2.1 - Prob. 2CCh. 2.1 - Prob. 3CCh. 2.1 - Prob. 4CCh. 2.1 - Prob. 5CCh. 2.1 - Prob. 6CCh. 2.1 - Prob. 7CCh. 2.1 - Prob. 8CCh. 2.1 - Prob. 9CCh. 2.1 - Prob. 10CCh. 2.1 - Prob. 1ECh. 2.1 - Prob. 2ECh. 2.1 - Prob. 3ECh. 2.1 - Prob. 4ECh. 2.1 - Prob. 5ECh. 2.1 - Prob. 6ECh. 2.1 - Prob. 7ECh. 2.1 - Prob. 8ECh. 2.1 - Prob. 9ECh. 2.1 - Prob. 10ECh. 2.1 - Prob. 11ECh. 2.1 - Prob. 12ECh. 2.1 - Prob. 13ECh. 2.1 - Prob. 14ECh. 2.1 - Prob. 15ECh. 2.1 - Prob. 16ECh. 2.1 - Prob. 17ECh. 2.1 - Prob. 18ECh. 2.1 - Prob. 19ECh. 2.1 - Prob. 20ECh. 2.1 - Prob. 21ECh. 2.1 - Prob. 22ECh. 2.1 - Prob. 23ECh. 2.1 - Prob. 24ECh. 2.1 - Prob. 25ECh. 2.1 - Prob. 26ECh. 2.1 - Prob. 27ECh. 2.1 - Prob. 28ECh. 2.1 - Prob. 29ECh. 2.1 - Prob. 30ECh. 2.1 - Prob. 31ECh. 2.1 - Prob. 32ECh. 2.1 - Prob. 33ECh. 2.1 - Prob. 34ECh. 2.1 - Prob. 35ECh. 2.1 - Prob. 36ECh. 2.1 - Prob. 37ECh. 2.1 - Prob. 38ECh. 2.1 - Prob. 39ECh. 2.1 - Prob. 40ECh. 2.1 - Prob. 41ECh. 2.1 - Prob. 42ECh. 2.1 - Prob. 43ECh. 2.1 - Prob. 44ECh. 2.1 - Prob. 45ECh. 2.1 - Prob. 46ECh. 2.1 - Prob. 47ECh. 2.1 - Prob. 48ECh. 2.1 - Prob. 49ECh. 2.1 - Prob. 50ECh. 2.1 - Prob. 51ECh. 2.1 - Prob. 52ECh. 2.1 - Prob. 53ECh. 2.1 - Prob. 54ECh. 2.1 - Prob. 55ECh. 2.1 - Prob. 56ECh. 2.1 - Prob. 57ECh. 2.1 - Prob. 58ECh. 2.1 - Prob. 59ECh. 2.1 - Prob. 60ECh. 2.1 - Prob. 61ECh. 2.1 - Prob. 62ECh. 2.1 - Prob. 63ECh. 2.1 - Prob. 64ECh. 2.1 - Prob. 65ECh. 2.2 - Prob. 1CCh. 2.2 - Prob. 2CCh. 2.2 - Prob. 3CCh. 2.2 - Prob. 4CCh. 2.2 - Prob. 5CCh. 2.2 - Prob. 6CCh. 2.2 - Prob. 7CCh. 2.2 - Prob. 8CCh. 2.2 - Prob. 9CCh. 2.2 - Prob. 10CCh. 2.2 - Prob. 11CCh. 2.2 - Prob. 12CCh. 2.2 - Prob. 1ECh. 2.2 - Prob. 2ECh. 2.2 - Prob. 3ECh. 2.2 - Prob. 4ECh. 2.2 - Prob. 5ECh. 2.2 - Prob. 6ECh. 2.2 - Prob. 7ECh. 2.2 - Prob. 8ECh. 2.2 - Prob. 9ECh. 2.2 - Prob. 10ECh. 2.2 - Prob. 11ECh. 2.2 - Prob. 12ECh. 2.2 - Prob. 13ECh. 2.2 - Prob. 14ECh. 2.2 - Prob. 15ECh. 2.2 - Prob. 16ECh. 2.2 - Prob. 17ECh. 2.2 - Prob. 18ECh. 2.2 - Prob. 19ECh. 2.2 - 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