(a)
Interpretation:
Polycarbophil is a dietary fiber supplement. It is the calcium salt of a
Concept introduction:
Polycarbophil is synthesized from copolymerization of acrylic acid and divinyl glycol. A molecule of divinylglycol is incorporated in a poly(acrylic acid) structure which leads to forming the radical and due to which, the second growth of the poly(acrylic acid) takes place which results in the formation of the
(b)
Interpretation:
Polycarbophil is a dietary fiber supplement. It is thecalcium salt of a copolymer of acrylic acid and divinylglycol, a cross-linking agent. In the stomach, the calcium ions exchange for protons and, in the higher pH of the intestine, the polymer absorbs
Concept introduction:
Polycarbophil is synthesized from copolymerization of acrylic acid and divinyl glycol. A molecule of divinylglycol is incorporated in a poly(acrylic acid) structure which leads to forming the radical, and due to which, the second growth of the poly(acrylic acid) takes place which results in the formation of the cross-linked polymer. The cross-linked polymer is water-insoluble.
(c)
Interpretation:
It is to be explained why polycarbophil effective at providing bulk in the intestine and what will occur on a molecular level to polycarbophil.
Concept introduction:
Polycarbophil is synthesized from copolymerization of acrylic acid and divinyl glycol. A molecule of divinylglycol is incorporated in a poly(acrylic acid) structure which leads to forming the radical, and due to which, the second growth of the poly(acrylic acid) takes place which results in the formation of the cross-linked polymer. The cross-linked polymer is water-insoluble. In
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Chapter 26 Solutions
Organic Chemistry: Principles And Mechanisms
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- Can you draw this using Lewis dot structures and full structures in the same way they are so that I can better visualize them and then determine resonance?arrow_forwardSynthesize the following compound from cyclohexanol, ethanol, and any other needed reagentsarrow_forwardFor a titration of 20.00 mL of 0.0500 M H2SO4 with 0.100 M KOH, calculate the pH at each of the following volume of KOH used in the titration: 1) before the titration begin; 2) 10.00 mL; 3) 20.00 mL; 4) 30.00 mL. Ka2 = 1.20×10-2 for H2SO4.arrow_forward
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