Concept explainers
Explain how voltage is induced in a permanent magnet pickup coil as the reluctor approaches alignment with the pickup coil.
The way in which the voltage is induced in a permanent magnet pickup coil as the reluctor approaches alignment with the pickup coil.
Answer to Problem 1SA
As the reluctor approaches alignment with the pickup coil, its tooth gets aligned with the core of pickup coil and repels the magnetic field. Hence the magnetic field is forced to flow through the coil and pickup core. As the tooth passes the core, the magnetic field lines get expanded. This action is repeated every time the tooth passes through the core. The moving lines of magnetic force cut across the coil windings and induce a voltage signal.
Explanation of Solution
A permanent magnet pickup coil consists of a permanent magnet with fine wire wound around it. The reluctor is attached to a rotating shaft or cable and there are a number of teeth on it depending on the application. An air gap is maintained between the reluctor and the pickup coil.
As the reluctor rotates in front of the pickup coil, its tooth gets aligned with the core of pickup coil and repels the magnetic field. Hence, the magnetic field is forced to flow through the coil and pickup core.
As the tooth passes the core, the magnetic field lines get extended. This action is repeated every time the tooth passes through the core. The moving lines of magnetic force cut across the coil windings and induce a voltage signal.
Conclusion:
Thus, as the reluctor approaches alignment with the pickup coil, its tooth gets aligned with the core of pickup coil and repels the magnetic field. Hence the magnetic field is forced to flow through the coil and pickup core. As the tooth passes the core, the magnetic field lines are able to expand. This action is repeated every time the tooth passes through the core. The moving lines of magnetic force cut across the coil windings and induce a voltage signal.
Want to see more full solutions like this?
Chapter 26 Solutions
AUTOMOTIVE TECHNOLOGY TECH MANUAL
- The coefficient of friction between the part and the tool in cold working tends to be: lower higher no different relative to its value in hot workingarrow_forwardThe force F={25i−45j+15k}F={25i−45j+15k} lblb acts at the end A of the pipe assembly shown in (Figure 1). Determine the magnitude of the component F1 which acts along the member AB. Determine the magnitude of the component F2 which acts perpendicular to the AB.arrow_forwardHi can you please help me with the attached question?arrow_forward
- Please can you help me with the attached question?arrow_forwardPlease can you help me with the attached question?arrow_forward4. The rod ABCD is made of an aluminum for which E = 70 GPa. For the loading shown, determine the deflection of (a) point B, (b) point D. 1.75 m Area = 800 mm² 100 kN B 1.25 m с Area = 500 mm² 75 kN 1.5 m D 50 kNarrow_forward
- Automotive Technology: A Systems Approach (MindTa...Mechanical EngineeringISBN:9781133612315Author:Jack Erjavec, Rob ThompsonPublisher:Cengage LearningElectrical Transformers and Rotating MachinesMechanical EngineeringISBN:9781305494817Author:Stephen L. HermanPublisher:Cengage LearningRefrigeration and Air Conditioning Technology (Mi...Mechanical EngineeringISBN:9781305578296Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill JohnsonPublisher:Cengage Learning
- Understanding Motor ControlsMechanical EngineeringISBN:9781337798686Author:Stephen L. HermanPublisher:Delmar Cengage Learning