INDUSTRIAL MOTOR CONTROL
7th Edition
ISBN: 9780357670590
Author: Herman
Publisher: CENGAGE L
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Question
Chapter 26, Problem 1RQ
To determine
The advantage of the point to point method of connecting the circuit components.
Expert Solution & Answer
Explanation of Solution
The point to point method is the method which is used to install the circuit components in the control circuit. The wire numbers are given in this method to the wires of the control circuit but not the load circuit. Where all the components are located in the motor circuit and are represented by the dashed lines.
The advantages of the point to point method is that this method is used to show the actual position of the wire of the component that reduces the wastage of the wire.
The component that are insider the control circuit and the outside the circuit can easily be distinguished.
Also, the point to point method show the designation of the wires and the tags.
In this method the troubleshooting and the servicing is easy as the wire numbers are given to the wire, also the components are easy to be identified as the wires are tagged and labelled.
Thus, the advantage of the point to point method is described.
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14) f(t)=1, 0
Find the solution of the following Differential Equations
Using Laplace Transforms
1) 4y+2y=0.
y(0)=2.
y'(0)=0.
2) y+w²y=0,
(0)=A,
y'(0)=B.
3) +2y-8y 0.
y(0)=1.
y'(0)-8.
4)-2-3y=0,
y(0)=1.
y'(0)=7.
5) y-ky'=0,
y(0)=2,
y'(0)=k.
6) y+ky'-2k²y=0,
y(0)=2,
y'(0) = 2k.
7) '+4y=0,
y(0)=2.8
8) y+y=17 sin(21),
y(0)=-1.
9) y-y-6y=0,
y(0)=6,
y'(0)=13.
10) y=0.
y(0)=4,
y' (0)=0.
11) -4y+4y-0,
y(0)=2.1.
y'(0)=3.9
12) y+2y'+2y=0,
y(0)=1,
y'(0)=-3.
13) +7y+12y=21e".
y(0)=3.5.
y'(0)=-10.
14) "+9y=10e".
y(0)=0,
y'(0)=0.
15) +3y+2.25y=91' +64.
y(0)=1.
y'(0) = 31.5
16)
-6y+5y-29 cos(2t).
y(0)=3.2,
y'(0)=6.2
17) y+2y+2y=0,
y(0)=0.
y'(0)=1.
18) y+2y+17y=0,
y(0)=0.
y'(0)=12.
19) y"-4y+5y=0,
y(0)=1,
y'(0)=2.
20) 9y-6y+y=0,
(0)-3,
y'(0)=1.
21) -2y+10y=0,
y(0)=3,
y'(0)=3.
22) 4y-4y+37y=0,
y(0)=3.
y'(0)=1.5
23) 4y-8y+5y=0,
y(0)=0,
y'(0)=1.
24)
++1.25y-0,
y(0)=1,
y'(0)=-0.5
25) y 2 cos(r).
y(0)=2.
y'(0) = 0.
26)
-4y+3y-0,
y(0)=3,
y(0) 7.
27) y+2y+y=e
y(0)=0.
y'(0)=0.
28) y+2y-3y=10sinh(27),
y(0)=0.
y'(0)=4.
29)…
Chapter 26 Solutions
INDUSTRIAL MOTOR CONTROL
Ch. 26 - Prob. 1RQCh. 26 - When connecting a control system, what should be...Ch. 26 - What should be done to each component to help...Ch. 26 - What is the disadvantage of wiring components to a...Ch. 26 - What is the main advantage of making connections...Ch. 26 - Refer to the circuit shown in Figure 26–1. Should...Ch. 26 - What does the dashed line between the two float...
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