Physics Laboratory Manual
4th Edition
ISBN: 9781133950639
Author: David Loyd
Publisher: Cengage Learning
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Textbook Question
Chapter 26, Problem 1PLA
Electric field lines are drawn (a) from positive charges to negative charges; (b) from negative charges to positive charges; (c) from the largest charge to the smallest charge; (d) from the smallest charge to the largest charge.
Expert Solution & Answer
To determine
The direction of electric field lines.
Answer to Problem 1PLA
Option (a) from positive charges to negative charges.
Explanation of Solution
Electric field lines are an imaginary lines that always starts from the positive charge and end at the negative charge. And the number of electric field lines is directly proportional to the total number of charge.
Conclusion:
- (a) The electric field lines always starts from positive charges and end at negative charges. Thus, option (a) is correct.
- (b) The electric field lines always starts from positive charges and end at negative charges. Thus, option (b) is incorrect.
- (c) The direction of electric field lines does not depend on the size of the charge. Thus, option (c) is incorrect.
- (d) The direction of electric field lines does not depend on the size of the charge. Thus, option (d) is incorrect.
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Students have asked these similar questions
(a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence of a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are
A = 2.20 pC, B = 7.50 pC,
and
C = −4.40 pC.
Given these charges, what would the magnitude and direction of the electric field be at cell A? (1 pC = 1 ✕ 10−12 C.)
magnitude
direction
Two point charges are placed on the x axis as shown in (Figure 1). The first charge. q₁ =
8.00 nC, is placed a distance 16.0 m from the origin along the positive x axis; the second
charge. q2 = 6.00 nC, is placed a distance 9.00 m from the origin along the negative x
axis.
Figure
6 of
9₂-6nC
(-9 m.0m)
0 (0 m, 0 m)
→
₁8 nC
(+ 16 m, 0 m)
Part A
Find the x-component of the electric field at the origin, point O.
Express your answer in newtons per coulomb to three significant figures, keeping in mind that an x component that points to the right is positive.
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Part B
Now, assume that charge q2 is negative; 92 = -6 nC, as shown in (Figure 2). What is the x-component of the net electric field at the origin, point O?
Express your answer in newtons per coulomb to three significant figures, keeping in mind that an x component that points to the right is…
Two pairs of charges are shown in (Figure 1).
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At which point or points is the electric field zero in (Figure 1)(a)?
Enter the number or numbers of the points, separated by commas if there are more than one. Enter 0 if there are no points where the field is zero.
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Part B
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At which point or points is the electric field zero in (Figure 1)(b)?
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Chapter 26 Solutions
Physics Laboratory Manual
Ch. 26 - Electric field lines are drawn (a) from positive...Ch. 26 - The points where the potential is the same (in...Ch. 26 - The points where the potential is the same (in...Ch. 26 - The relationship between the direction of the...Ch. 26 - Why are the measured equipotentials lines instead...Ch. 26 - If two electrodes have a source of potential...Ch. 26 - Why is it important to center the electrodes on...Ch. 26 - In the performance of this laboratory, what is the...Ch. 26 - On what basis are you to decide how many points to...
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Electric Fields: Crash Course Physics #26; Author: CrashCourse;https://www.youtube.com/watch?v=mdulzEfQXDE;License: Standard YouTube License, CC-BY