Chapter 26, Problem 1CQ

l. FIGURE Q26.1 shows the x-component of $\stackrel{\to }{E}$ as a function of x. Draw a graph of V versus x in this same region of space. Let V = 0 V at x = 0 m and include an appropriate vertical scale.

To determine

Graph of v versus $x$ in this same region of space.

Answer to Problem 1CQ

Solution: The graph of V versus $x$ is as follows

Figure.2

Explanation of Solution

Given:

$\overrightarrow{E}=100\frac{\text{V}}{\text{m}}$

Let $v=o\left(v\right)$ at $x=oM.$ and include on appropriate vertical scale.

The graph of electric field strength

Figure.1

Formula used:

Sine $\overrightarrow{E}=\frac{-\Delta v}{x}$

Calculation:

So, $\begin{array}{c}\Delta v=-\overrightarrow{E}.x\\ =-100x\text{ V}\end{array}$

$V_2-V_0=-100\left(2\right)=-200$

Negative sign shoes that V decrees with increasing value of $x.$

So graph of V source be

Figure.2

Conclusion:

Potential decreases with increasing.