PHYSICS:F/SCI.+ENGRS.(LL)-W/SINGLE CARD
10th Edition
ISBN: 9781337888547
Author: SERWAY
Publisher: CENGAGE L
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Chapter 26, Problem 15P
To determine
The electrical conductivity of the earth’s atmosphere.
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(2. m)-¹
Chapter 26 Solutions
PHYSICS:F/SCI.+ENGRS.(LL)-W/SINGLE CARD
Ch. 26.1 - Consider positive and negative charges of equal...Ch. 26.2 - Prob. 26.2QQCh. 26.2 - Prob. 26.3QQCh. 26.4 - When does an incandescent lightbulb carry more...Ch. 26 - Prob. 1PCh. 26 - A small sphere that carries a charge q is whirled...Ch. 26 - In the Bohr model of the hydrogen atom (which will...Ch. 26 - Prob. 4PCh. 26 - Prob. 5PCh. 26 - Figure P26.6 represents a section of a conductor...
Ch. 26 - The quantity of charge q (in coulombs) that has...Ch. 26 - A Van de Graaff generator (see Problem 24)...Ch. 26 - An electric current in a conductor varies with...Ch. 26 - Prob. 10PCh. 26 - An electric heater carries a current of 13.5 A...Ch. 26 - You are working at a company that manufactures...Ch. 26 - Prob. 13PCh. 26 - Prob. 14PCh. 26 - Prob. 15PCh. 26 - Prob. 16PCh. 26 - Prob. 17PCh. 26 - Prob. 18PCh. 26 - An aluminum wire with a diameter of 0.100 mm has a...Ch. 26 - Plethysmographs are devices used for measuring...Ch. 26 - At what temperature will aluminum have a...Ch. 26 - You are working in a laboratory that studies the...Ch. 26 - Assume that global lightning on the Earth...Ch. 26 - The Van de Graaff generator, diagrammed in Figure...Ch. 26 - A 100-W lightbulb connected to a 120-V source...Ch. 26 - The potential difference across a resting neuron...Ch. 26 - The cost of energy delivered to residences by...Ch. 26 - Residential building codes typically require the...Ch. 26 - Assuming the cost of energy from the electric...Ch. 26 - An 11.0-W energy-efficient fluorescent lightbulb...Ch. 26 - A 500-W heating coil designed to operate from 110...Ch. 26 - Why is the following situation impossible? A...Ch. 26 - Make an order-of-magnitude estimate of the cost of...Ch. 26 - Lightbulb A is marked 25 W 120 V, and lightbulb B...Ch. 26 - One wire in a high-voltage transmission line...Ch. 26 - You are working with an oceanographer who is...Ch. 26 - A charge Q is placed on a capacitor of capacitance...Ch. 26 - An experiment is conducted to measure the...Ch. 26 - Prob. 39APCh. 26 - Prob. 40APCh. 26 - Review. An office worker uses an immersion heater...Ch. 26 - The strain in a wire can be monitored and computed...Ch. 26 - A close analogy exists between the flow of energy...Ch. 26 - The dielectric material between the plates of a...Ch. 26 - Review. A parallel-plate capacitor consists of...Ch. 26 - Prob. 46APCh. 26 - Why is the following situation impossible? An...Ch. 26 - Prob. 48CPCh. 26 - A spherical shell with inner radius ra and outer...Ch. 26 - Material with uniform resistivity is formed into...
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- An aluminum wire 1.628 mm in diameter (14-gauge) carries a current of 3.00 amps, (a) What is the absolute value of the charge density in the wire? (b) What is the drift velocity of the electrons? (c) What would be the drift velocity if the same gauge copper were used instead of aluminum? The density of copper is 8.96 g/cm3 and thedensity of aluminum is 2.70 g/cm3. The molar mass ofaluminum is 26.98 g/mol and the molar mass of copper is 63.5 g/mol. Assume each atom of metal contributes one free electron.arrow_forwardTaking R = 1.00 k and = 250 V in Figure P21.49, determine the direction and magnitude of the current in the horizontal wire between a and e. Figure P21.49arrow_forwardThe earth’s surface has a negative surface charge density of 10-9 C m-2. The potential difference of 400 kV between the top of the atmosphere and the surface results (due to the low conductivity of the lower atmosphere) in a current of only 1800 A over the entire globe. If there were no mechanism of sustaining atmospheric electric field, how much time (roughly) would be required to neutralise the earth’s surface? (This never happens in practice because there is a mechanism to replenish electric charges, namely the continual thunderstorms and lightning in different parts of the globe). (Radius of earth = 6.37 × 106 m.)arrow_forward
- Silver wire has a cross-sectional area A = 2.0 mm2. A total of 9.4 x 10 electrons pass through the wire in 3.0 s. The conduction electron density in silver is 5.8 x 1028 electrons/m. What is the drift velocity of these electrons?arrow_forwardSuppose that there is a wire. It is made out of material that has a the following information: temperature coefficient = 0.005/°C cross sectional area = 4.51x10-6 m² length: 1.00 m free electron density = 8.49 x 1028 electrons/m³ The wire is at temperature 20°C and it carries a current of 5 A when connected to a 35 V battery. Find the (1) drift speed of the electrons and (2) resistivity at 50°C.arrow_forwardGr 11 level No calculusarrow_forward
- Suppose that there is a wire. It is made out of material that has a the following information: temperature coefficient=0.005/°C cross sectional area: 4.51x10-6 m² length: 1.00 m fee electron density of 8.49 x 1028 electrons/m³ The wire is at temperature 20°C and it carries a current of 5 A when connected to a 35 V battery. Find the (1) drift speed of the electrons and (2) resistivity at 50°C.arrow_forwardA conductor has a cross-sectional area of 2.3x106 m² and the number of free electrons per unit volume is 8.5 X1028 electron/m³. When the current is 7.1 A, find the drift speed (in mm/s) of the electrons. Use the charge of the electron to be 1.6×1019 c.arrow_forwardAn aluminum "12 gauge" wire has a diameter d of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The electric field in the wire changes with time as E(t)=0.0004t2−0.0001t+0.0004 newtons per coulomb, where time is measured in seconds. Find the charge Q passing through a cross-section of the conductor between time 0 seconds and time 5 seconds. Express your answer in coulombs to two significant figures.arrow_forward
- A typical lightning bolt may last for 0.197s and transfer 1.19 ✕ 1020 electrons. Calculate the average current (in A) in the lightning bolt.arrow_forwardA conductor has a cross- sectional area of 2.3x 10 6 m2 and the number of free electrons per unit volume is 8.5 x 1028 electron/m³. When the current is 14.4 A, find the drift speed (in mm/s) of the electrons. Use the charge of the electron to be 1.6x 1019 C.arrow_forwardCurrent and Resistance Problem 18: Consider two wires made of different materials. Wire A has a conductivity of 1.9 × 107 Ω-1m-1, and wire B has a conductivity of 8.5 × 107 Ω-1m-1. Part (a) Wire A has a circular cross-section with radius 2.74 mm. If there is an electric field of 0.059 V/m inside it, how much current, in amperes, is flowing through it? Part (b) Wire B has a square 2.74 mm × 2.74 mm cross-section. If wire B has the same electric field as Wire A did in part (a), what current, in amperes, would be passing through it?arrow_forward
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