Concept explainers
To find: all real zeros of the function.
The three zeros of the function are −8,−3,3 .
Given information:
The function h(x)=x3+8x2−9x−72 .
Formula used:
The Rational Zero Theorem:
If f(x)=anxn+⋯+a1x+a0 consists of integer coefficients, then the shape of each rational zero of f is as follows:
pq= factor of constant term a0 factor of leading coefficient an
Calculation:
Consider the function
h(x)=x3+8x2−9x−72 .
Then
Factors of constant term 72 :
p=1,2,3,4,6,8,9,12,18,24,36,72
Leading coefficient factors 1 :
q=1
All possible combinations of ±pq .
Some or none may be zeros of the function.
Simplify and eliminate duplicate entries.
±pq=±(1,2,3,4,6,8,9,12,18,24,36,72)
Test the possible rational zeros.
I poly horner scheme [x=1]{x3+8x2−9x−72}
\ polyhornerscheme [x=2]{x3+8x2−9x−72}
I polyhornerscheme [x=3][x3+8x2−9x−72}
3 is a zero, so (x−3) is a factor.
Using the results of the division.
h(x)=x3+8x2−9x−72=(x−3)(x2+11x+24) and factor the remaining part
h(x)=(x−3)(x+3)(x+8)x=−8,−3,3
Chapter 2 Solutions
Holt Mcdougal Larson Algebra 2: Student Edition 2012
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