COLLEGE PHYSICS LL W/ 6 MONTH ACCESS
COLLEGE PHYSICS LL W/ 6 MONTH ACCESS
2nd Edition
ISBN: 9781319414597
Author: Freedman
Publisher: MAC HIGHER
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Chapter 26, Problem 100QAP
To determine

(a)

The shortest and longest wavelengths of the Brackett series

Expert Solution
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Answer to Problem 100QAP

The shortest and longest wavelengths of the Brackett series are 1459.85 nm and 4050.22 nm respectively.

Explanation of Solution

Given:

For Brackett series nf= 4

Formula used:

Rydberg formula is given as

  1λ=1.09737×107(1nf21ni2) meter1

Calculation:

For the shortest wavelength of the Brackett series nf= 4 and ni=  (continuum)

Putting these values in Eq. (1.1) we get

  1λ=1.09737×107(1 4 2 1 2 ) meter1=0.0685×107 meter1or, λ = 14.5985×10-7 meter = 1459.85 nm

This emission is in the infrared range.

For the longest wavelength nf= 4 and ni= 5, so using Eq. 1.1 we get

  1λ=1.09737×107(1 4 2 1 5 2 ) meter1=0.02469×107 meter1orλ = 40.5022×107 meter= 4050.22 nm

This emission is also in the infrared range.

Conclusion:

Therefore, the shortest and longest wavelengths of the Brackett series are 1459.85 nm and 4050.22 nm respectively. The emission lines are in the infrared range.

To determine

(b)

The shortest and longest wavelengths of the Pfund series

Expert Solution
Check Mark

Answer to Problem 100QAP

Therefore, the shortest and longest wavelengths of the Pfund series are 2283.10 nm and 7457.12 nm respectively.

Explanation of Solution

Given:

For Pfund series nf= 5

Calculation:

For the shortest wavelength of the Pfund series nf= 5 and ni=  (continuum)

Putting these values in Eq. (1.1) we get

  1λ=1.09737×107(1 5 2 1 2 ) meter1=0.0438×107 meter1or, λ = 22.8310×10-7 meter = 2283.10 nm

This emission is in the infrared range.

For the longest wavelength nf= 5 and ni= 6, so using Eq. 1.1 we get

  1λ=1.09737×107(1 5 2 1 6 2 ) meter1=0.01341×107 meter1orλ = 74.5712×107 meter= 7457.12 nm

This emission is also in the infrared range.

Conclusion:

Therefore, the shortest and longest wavelengths of the Pfund series are 2283.10 nm and 7457.12 nm respectively. The emission lines are in the infrared range.

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Chapter 26 Solutions

COLLEGE PHYSICS LL W/ 6 MONTH ACCESS

Ch. 26 - Prob. 11QAPCh. 26 - Prob. 12QAPCh. 26 - Prob. 13QAPCh. 26 - Prob. 14QAPCh. 26 - Prob. 15QAPCh. 26 - Prob. 16QAPCh. 26 - Prob. 17QAPCh. 26 - Prob. 18QAPCh. 26 - Prob. 19QAPCh. 26 - Prob. 20QAPCh. 26 - Prob. 21QAPCh. 26 - Prob. 22QAPCh. 26 - Prob. 23QAPCh. 26 - Prob. 24QAPCh. 26 - Prob. 25QAPCh. 26 - Prob. 26QAPCh. 26 - Prob. 27QAPCh. 26 - Prob. 28QAPCh. 26 - Prob. 29QAPCh. 26 - Prob. 30QAPCh. 26 - Prob. 31QAPCh. 26 - Prob. 32QAPCh. 26 - Prob. 33QAPCh. 26 - Prob. 34QAPCh. 26 - Prob. 35QAPCh. 26 - Prob. 36QAPCh. 26 - Prob. 37QAPCh. 26 - Prob. 38QAPCh. 26 - Prob. 39QAPCh. 26 - Prob. 40QAPCh. 26 - Prob. 41QAPCh. 26 - Prob. 42QAPCh. 26 - Prob. 43QAPCh. 26 - Prob. 44QAPCh. 26 - Prob. 45QAPCh. 26 - Prob. 46QAPCh. 26 - Prob. 47QAPCh. 26 - Prob. 48QAPCh. 26 - Prob. 49QAPCh. 26 - Prob. 50QAPCh. 26 - Prob. 51QAPCh. 26 - Prob. 52QAPCh. 26 - Prob. 53QAPCh. 26 - Prob. 54QAPCh. 26 - Prob. 55QAPCh. 26 - Prob. 56QAPCh. 26 - Prob. 57QAPCh. 26 - Prob. 58QAPCh. 26 - Prob. 59QAPCh. 26 - Prob. 60QAPCh. 26 - Prob. 61QAPCh. 26 - Prob. 62QAPCh. 26 - Prob. 63QAPCh. 26 - Prob. 64QAPCh. 26 - Prob. 65QAPCh. 26 - Prob. 66QAPCh. 26 - Prob. 67QAPCh. 26 - Prob. 68QAPCh. 26 - Prob. 69QAPCh. 26 - Prob. 70QAPCh. 26 - Prob. 71QAPCh. 26 - Prob. 72QAPCh. 26 - Prob. 73QAPCh. 26 - Prob. 74QAPCh. 26 - Prob. 75QAPCh. 26 - Prob. 76QAPCh. 26 - Prob. 77QAPCh. 26 - Prob. 78QAPCh. 26 - Prob. 79QAPCh. 26 - Prob. 80QAPCh. 26 - Prob. 81QAPCh. 26 - Prob. 82QAPCh. 26 - Prob. 83QAPCh. 26 - Prob. 84QAPCh. 26 - Prob. 85QAPCh. 26 - Prob. 86QAPCh. 26 - Prob. 87QAPCh. 26 - Prob. 88QAPCh. 26 - Prob. 89QAPCh. 26 - Prob. 90QAPCh. 26 - Prob. 91QAPCh. 26 - Prob. 92QAPCh. 26 - Prob. 93QAPCh. 26 - Prob. 94QAPCh. 26 - Prob. 95QAPCh. 26 - Prob. 96QAPCh. 26 - Prob. 97QAPCh. 26 - Prob. 98QAPCh. 26 - Prob. 99QAPCh. 26 - Prob. 100QAPCh. 26 - Prob. 101QAPCh. 26 - Prob. 102QAPCh. 26 - Prob. 103QAPCh. 26 - Prob. 104QAP
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