Organic Chemistry
3rd Edition
ISBN: 9781119316152
Author: Klein, David R.
Publisher: WILEY
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Chapter 25.4, Problem 29CC
(a)
Interpretation Introduction
Interpretation:
In Bacitracin A, the amino acid residues and the configuration of the same along with non-amino acid residue need to be identified.
Concept introduction:
The amino acid residue is in a given compound is identified by finding the peptide bond. Then assigning the side chain for the corresponding amino acid residue. If the configuration of the amino acid residue is “L-amino acid” means it is naturally occurring and if it is a “D-amino acid” it is enantiomer of “L-amino acid”
To identify: the amino acid residue in Bacitracin A that are naturally occurring.
(b)
Interpretation Introduction
Interpretation:
In Bacitracin A, the amino acid residues and the configuration of the same along with non-amino acid residue need to be identified.
Concept introduction:
The amino acid residue is in a given compound is identified by finding the peptide bond. Then assigning the side chain for the corresponding amino acid residue. If the configuration of the amino acid residue is “L-amino acid” means it is naturally occurring and if it is a “D-amino acid” it is enantiomer of “L-amino acid”
To identify: the amino acid residue in Bacitracin A that are D-amino acids.
(c)
Interpretation Introduction
Interpretation:
In Bacitracin A, the amino acid residues and the configuration of the same along with non-amino acid residue need to be identified.
Concept introduction:
The amino acid residue is in a given compound is identified by finding the peptide bond. Then assigning the side chain for the corresponding amino acid residue. If the configuration of the amino acid residue is “L-amino acid” means it is naturally occurring and if it is a “D-amino acid” it is enantiomer of “L-amino acid”
To identify: the amino acid residue in Bacitracin A that are not naturally occurring and its enantiomer also.
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Chapter 25 Solutions
Organic Chemistry
Ch. 25.2 - Prob. 1CCCh. 25.2 - Prob. 2CCCh. 25.2 - Prob. 3CCCh. 25.2 - Prob. 1LTSCh. 25.2 - Prob. 4PTSCh. 25.2 - Prob. 5ATSCh. 25.2 - Prob. 6ATSCh. 25.2 - Prob. 7CCCh. 25.2 - Prob. 8CCCh. 25.2 - Prob. 9CC
Ch. 25.2 - Prob. 10CCCh. 25.3 - Prob. 11CCCh. 25.3 - Prob. 12CCCh. 25.3 - Prob. 13CCCh. 25.3 - Prob. 2LTSCh. 25.3 - Prob. 14PTSCh. 25.3 - Prob. 15ATSCh. 25.3 - Prob. 16ATSCh. 25.3 - Prob. 17CCCh. 25.3 - Prob. 18CCCh. 25.3 - Prob. 19CCCh. 25.3 - Prob. 20CCCh. 25.4 - Prob. 3LTSCh. 25.4 - Prob. 21PTSCh. 25.4 - Prob. 22ATSCh. 25.4 - Prob. 23ATSCh. 25.4 - Prob. 24ATSCh. 25.4 - Prob. 25CCCh. 25.4 - Prob. 26CCCh. 25.4 - Prob. 27CCCh. 25.4 - Prob. 28CCCh. 25.4 - Prob. 29CCCh. 25.5 - Prob. 30CCCh. 25.5 - Prob. 4LTSCh. 25.5 - Prob. 31PTSCh. 25.5 - Prob. 32ATSCh. 25.5 - Prob. 33ATSCh. 25.6 - Prob. 5LTSCh. 25.6 - Prob. 34PTSCh. 25.6 - Prob. 35ATSCh. 25.6 - Prob. 36ATSCh. 25.6 - Prob. 6LTSCh. 25.6 - Prob. 37PTSCh. 25.6 - Prob. 38ATSCh. 25.7 - Prob. 39CCCh. 25 - Prob. 40PPCh. 25 - Prob. 41PPCh. 25 - Prob. 42PPCh. 25 - Prob. 43PPCh. 25 - Prob. 44PPCh. 25 - Prob. 45PPCh. 25 - Prob. 46PPCh. 25 - Prob. 47PPCh. 25 - Prob. 48PPCh. 25 - Prob. 49PPCh. 25 - Prob. 50PPCh. 25 - Prob. 51PPCh. 25 - Prob. 52PPCh. 25 - Prob. 53PPCh. 25 - Prob. 54PPCh. 25 - Prob. 55PPCh. 25 - Prob. 56PPCh. 25 - Prob. 57PPCh. 25 - Prob. 58PPCh. 25 - Prob. 59PPCh. 25 - Prob. 60PPCh. 25 - Prob. 61PPCh. 25 - Prob. 62PPCh. 25 - Prob. 63PPCh. 25 - Prob. 64PPCh. 25 - Prob. 65PPCh. 25 - Prob. 66PPCh. 25 - Prob. 67PPCh. 25 - Prob. 68PPCh. 25 - Prob. 69PPCh. 25 - Prob. 70PPCh. 25 - Prob. 71PPCh. 25 - Prob. 72PPCh. 25 - Prob. 73PPCh. 25 - Prob. 74PPCh. 25 - Prob. 75PPCh. 25 - Prob. 76PPCh. 25 - Prob. 77PPCh. 25 - Prob. 78PPCh. 25 - Prob. 79PPCh. 25 - Prob. 80PPCh. 25 - Prob. 81PPCh. 25 - Prob. 82PPCh. 25 - Prob. 83PPCh. 25 - Prob. 84IPCh. 25 - Prob. 85IPCh. 25 - Prob. 86IPCh. 25 - Prob. 87IPCh. 25 - Prob. 88IPCh. 25 - Prob. 89IPCh. 25 - Prob. 90CPCh. 25 - We saw in Section 25.6 that DCC can be used to...Ch. 25 - Prob. 92CP
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