COLLEGE PHYSICS LL W/ 6 MONTH ACCESS
COLLEGE PHYSICS LL W/ 6 MONTH ACCESS
2nd Edition
ISBN: 9781319414597
Author: Freedman
Publisher: MAC HIGHER
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Chapter 25, Problem 65QAP
To determine

(a)

Einsteinian momentum of an electron travels at 0.444c?

Expert Solution
Check Mark

Answer to Problem 65QAP

Einsteinian momentum =1.35×1022kgm/s

Explanation of Solution

Calculation:

An electron (mass, m=9.11×1031kg ) travels at v = 0.444c. The magnitude of theEinsteinian momentum is p=γmv, where γ=11 v2 c2 , The total energy E of the electronis the sum of its Einsteinian kinetic energy Kand the energy not associated with its motion,i.e., its rest energy, E0. The rest energy is equal to E0=mc2, and its total energy is equal to E=γmc2.

Relativistic gamma:

  γ=11 v2 c2 =11 (0.444c)2 c2 =1.116

  p=γmv=1.116×9.11×1031×0.444×3×108=1.35×1022kgm/s

Conclusion:

Einsteinian momentum =1.35×1022kgm/s

To determine

(b)

Einsteinian kinetic energy of an electron travels at 0.444c?

Expert Solution
Check Mark

Answer to Problem 65QAP

Einsteinian kinetic energy =9.51×1015J

Explanation of Solution

Calculation:

  K+E0=EK=EE0=γmc2mc2=(γ1)mc2=(1.1161)×9.11×1031×(3×108)2=9.51×1015J

Einsteinian kinetic energy =9.51×1015J

Conclusion:

Einsteinian kinetic energy =9.51×1015J

To determine

(c)

Rest energy of an electron travels at 0.444c?

Expert Solution
Check Mark

Answer to Problem 65QAP

Rest energy =8.20×1014J

Explanation of Solution

Calculation:

  E0=mc2=9.11×1031×(3×108)2=8.20×1014J

Einsteinian kinetic energy =9.51×1015J

Conclusion:

Rest energy =8.20×1014J

To determine

(d)

The total energy of the electrontravels at 0.444c?

Expert Solution
Check Mark

Answer to Problem 65QAP

The total energy =9.15×1014J

Explanation of Solution

Calculation:

  E=γmc2=1.116×9.11×1031×(3×108)2=9.15×1014J

The total energy =9.15×1014J

Conclusion:

The total energy =9.15×1014J

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Chapter 25 Solutions

COLLEGE PHYSICS LL W/ 6 MONTH ACCESS

Ch. 25 - Prob. 11QAPCh. 25 - Prob. 12QAPCh. 25 - Prob. 13QAPCh. 25 - Prob. 14QAPCh. 25 - Prob. 15QAPCh. 25 - Prob. 16QAPCh. 25 - Prob. 17QAPCh. 25 - Prob. 18QAPCh. 25 - Prob. 19QAPCh. 25 - Prob. 20QAPCh. 25 - Prob. 21QAPCh. 25 - Prob. 22QAPCh. 25 - Prob. 23QAPCh. 25 - Prob. 24QAPCh. 25 - Prob. 25QAPCh. 25 - Prob. 26QAPCh. 25 - Prob. 27QAPCh. 25 - Prob. 28QAPCh. 25 - Prob. 29QAPCh. 25 - Prob. 30QAPCh. 25 - Prob. 31QAPCh. 25 - Prob. 32QAPCh. 25 - Prob. 33QAPCh. 25 - Prob. 34QAPCh. 25 - Prob. 35QAPCh. 25 - Prob. 36QAPCh. 25 - Prob. 37QAPCh. 25 - Prob. 38QAPCh. 25 - Prob. 39QAPCh. 25 - Prob. 40QAPCh. 25 - Prob. 41QAPCh. 25 - Prob. 42QAPCh. 25 - Prob. 43QAPCh. 25 - Prob. 44QAPCh. 25 - Prob. 45QAPCh. 25 - Prob. 46QAPCh. 25 - Prob. 47QAPCh. 25 - Prob. 48QAPCh. 25 - Prob. 49QAPCh. 25 - Prob. 50QAPCh. 25 - Prob. 51QAPCh. 25 - Prob. 52QAPCh. 25 - Prob. 53QAPCh. 25 - Prob. 54QAPCh. 25 - Prob. 55QAPCh. 25 - Prob. 56QAPCh. 25 - Prob. 57QAPCh. 25 - Prob. 58QAPCh. 25 - Prob. 59QAPCh. 25 - Prob. 60QAPCh. 25 - Prob. 61QAPCh. 25 - Prob. 62QAPCh. 25 - Prob. 63QAPCh. 25 - Prob. 64QAPCh. 25 - Prob. 65QAPCh. 25 - Prob. 66QAPCh. 25 - Prob. 67QAPCh. 25 - Prob. 68QAPCh. 25 - Prob. 69QAPCh. 25 - Prob. 70QAPCh. 25 - Prob. 71QAPCh. 25 - Prob. 72QAPCh. 25 - Prob. 73QAPCh. 25 - Prob. 74QAPCh. 25 - Prob. 75QAPCh. 25 - Prob. 76QAPCh. 25 - Prob. 77QAPCh. 25 - Prob. 78QAPCh. 25 - Prob. 79QAPCh. 25 - Prob. 80QAPCh. 25 - Prob. 81QAPCh. 25 - Prob. 82QAPCh. 25 - Prob. 83QAPCh. 25 - Prob. 84QAPCh. 25 - Prob. 85QAPCh. 25 - Prob. 86QAPCh. 25 - Prob. 87QAPCh. 25 - Prob. 88QAPCh. 25 - Prob. 89QAPCh. 25 - Prob. 90QAP
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