Explanation Given data: Wavelength of the radiation is 680 nm. Formula used: Write the expression for energy of the photon. E photon = h f (1) Here, E photon is the energy of the photon, h is the plank’s constant with value 6.63 × 10 − 34 J ⋅ s , and f is the frequency. Write the expression for frequency. f = c λ (2) Here, c is the speed of light with value 3 × 10 8 m s , and λ is the wavelength. Write the expression for energy. E = P t (3) Here, E is the energy, P is the power dissipated, and t is the time period. Write the expression fo rnumber of photons. N = Total energy Energy of each photon (4) Here, N is the number of photons. Explanation: Substitute 3 × 10 8 m s for c and 680 × 10 − 9 m for λ in equation (2), f = 3 × 10 8 m s 68010 − 9 m = 4.412 × 10 14 Hz Substitute 4.412 × 10 14 Hz for f and 6.63 × 10 − 34 J ⋅ s for h in equation (1), E photon = ( 6

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ISBN: 8220106755235

Author: Field

Publisher: PEARSON

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Nature of light

Light is transverse and electromagnetic radiation that exhibits the properties of a wave as well as a particle. For this reason, light is said to have a “dual nature.”

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Chapter 25, Problem 47P

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The number of photons per second.

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Chapter 25, Problem 45P

Chapter 25, Problem 48P

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Chapter 25 Solutions