Explanation Given data : Consider that the wavelength of photon is 1 nm. Explanation: Consider the expression for the energy of the photon. E = h f (1) Here, h is Planck's constant, which is generally known as 6.63 × 10 − 34 J ⋅ s . Write the expression for the frequency of the photon f . f = c λ (2) Here, λ is wavelength of photon, and c is the velocity of light in vacuum, which is generally 3 × 10 8 m s . Substitute equation (2) in (1), E = h ( c λ ) Substitute 6.63 × 10 − 34 J ⋅ s for h , 3 × 10 8 m s for c , and 1 nm for λ , E = ( 6.63 × 10 − 34 J ⋅ s ) ( 3 × 10 8 m s 1 nm ) = ( 6.63 × 10 − 34 J ⋅ s ) ( 3 × 10 8 m s 1 × 10 − 9 m ) = 1

College Physics: A Strategic Approach, Books a la Carte Edition (4th Edition)

4th Edition

ISBN: 9780134700502

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Nature of light

Light is transverse and electromagnetic radiation that exhibits the properties of a wave as well as a particle. For this reason, light is said to have a “dual nature.”

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Chapter 25, Problem 41P

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To find: The energy of x-ray photon.

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Chapter 25, Problem 40P

Chapter 25, Problem 42P

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Chapter 25 Solutions

College Physics: A Strategic Approach, Books a la Carte Edition (4th Edition)

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Chapter 25 Solutions