Explanation If a lens is used as a magnifying glass, the object is placed between the focus and the optic centre and the image is formed at the near point N of the eye, which is 25 cm for a normal eye. For a relaxed eye, the object distance may be taken equal to that of the focal length of the lens f e . The magnification m e of the eyepiece is given by the expression, m e = N f e The length L of a telescope is the sum of the focal lengths of the objective f o and the eye piece f e . L = f o + f e The focal length of the objective can be calculated using the above expression and the magnificationM of the telescope is given by the ratio of the focal lengths of the objective and the eye piece. M = − f o f e Given: The maximum length of the telescope L = 50 cm Magnification of the eyepiece M = + 5 × Near point of the eye N = 25 cm Formula: m e = N f e L = f o + f e M = −

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ISBN: 9780321625922

Author: Douglas C. Giancoli

Publisher: Addison-Wesley

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Chapter 25, Problem 40P

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The maximum achievable angular magnification for a telescope designed to be hand held.

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Chapter 25, Problem 39P

Chapter 25, Problem 41P

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Physics: Principles with Applications

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