Chapter 2.5, Problem 2QE

Explanation of Solution

The communication rate required between the disk drive and disk controller:

• It is given that, $3000$ revolutions in a minute and each track contains $16$ sector and each sector has $1024$ bytes.

The number of revolution in each second,

$\begin{array}{c}N=\frac{3000}{60}\\ =50\end{array}$

Here, $N$ is the number of the revolution per second.

The number of the revolution per second is $50$, that means $800$ sectors will pass under the read/write head in a second. Each sector has $1024$ bytes.

As 1 bit has 0.125 Byte.

Therefore, 1024 bytes has $\frac{1024}{0.125}$ bits per second