Explanation Given data : Consider that the power and diameter of the beam are 1 mW and 1 mm respectively. Explanation: Consider the following expression, which relates the electric and magnetic field amplitudes. E 0 = c B 0 (1) Here, c is the velocity of light in vacuum, which is generally 3 × 10 8 m s . Consider the following expression that relates the intensity of microwaves with oscillating electric field amplitude. I = c ε 0 E 0 2 2 (2) Here, ε 0 is permittivity of free space, which is generally known as 8.85 × 10 − 12 C 2 N ⋅ m 2 Re-arrange equation (2). E 0 2 = 2 I c ε 0 Take square root on both sides of the equation. E 0 = ( 2 I c ε 0 ) 1 2 (3) Consider the following expression that relates the intensity of microwaves with power and area of cross-section of the beam. I = P A (4) Here, A is cross-sectional area of the beam, which is generally π r 2 for circular beam. Substitute equation (4) in (3), E 0 = ( 2 P A c ε 0 ) 1 2 = ( 2 P A c ε 0 ) 1 2 Substitute π r 2 for A , E 0 = ( 2 P π r 2 c ε 0 ) 1 2 Here, r is the radius of the beam, which is equal to half value of diameter ( d ) of the beam. Therefore, d 2 = 1 mm 2 = 0.5 mm . Substitute 1 mW for P , 0.5 mm for r , 3 × 10 8 m s for c , and 8.85 × 10 − 12 C 2 N ⋅ m 2 for ε 0 in equation (3), E 0 = ( 2 ( 1 mW ) π ( 0.5 mm ) 2 ( 3 × 10 8 m s ) ( 8

College Physics: A Strategic Approach Plus Mastering Physics with Pearson eText -- Access Card Package (4th Edition) (What's New in Astronomy & Physics)

4th Edition

ISBN: 9780134641492

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Chapter 25, Problem 29P

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To find: The amplitudes of oscillating electric and magnetic fields in the laser beam.

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Chapter 25, Problem 28P

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Chapter 25 Solutions

College Physics: A Strategic Approach Plus Mastering Physics with Pearson eText -- Access Card Package (4th Edition) (What's New in Astronomy & Physics)

Ch. 25 - Prob. 1CQ Ch. 25 - Prob. 2CQ Ch. 25 - Prob. 3CQ Ch. 25 - Prob. 4CQ Ch. 25 - Prob. 5CQ Ch. 25 - Prob. 6CQ Ch. 25 - The power lines that run through your neighborhood...Ch. 25 - The magnetic flux passing through a coil of wire...Ch. 25 - There is a counterclockwise induced current in the...Ch. 25 - Prob. 10CQ

Ch. 25 - The conducting loop in Figure Q25.11 is moving...Ch. 25 - Figure Q25.12 shows two concentric, conducting...Ch. 25 - Figure Q25.13 shows conducting loops next to each...Ch. 25 - Prob. 15CQ Ch. 25 - Prob. 16CQ Ch. 25 - Prob. 17CQ Ch. 25 - A metal wire is resting on a U-shaped conducting...Ch. 25 - Prob. 19CQ Ch. 25 - Prob. 20CQ Ch. 25 - Prob. 21CQ Ch. 25 - Prob. 22CQ Ch. 25 - Prob. 23CQ Ch. 25 - Prob. 24CQ Ch. 25 - Arc welding uses electric current to make an...Ch. 25 - A circular loop of wire has an area of 0.30 m2. It...Ch. 25 - In Figure Q25.27, a square loop is rotating in the...Ch. 25 - A diamond-shaped loop of wire is pulled at a...Ch. 25 - Figure Q25.29 shows a triangular loop of wire in a...Ch. 25 - A device called a flip coil can be used to measure...Ch. 25 - The electromagnetic waves that carry FM radio...Ch. 25 - The beam from a laser is focused with a lens,...Ch. 25 - A spacecraft in orbit around the moon measures its...Ch. 25 - A 6.0 mW vertically polarized laser beam passes...Ch. 25 - Prob. 36MCQ Ch. 25 - Prob. 1P Ch. 25 - Prob. 2P Ch. 25 - A l0-cm-long wire is pulled along a U-shaped...Ch. 25 - Figure P25.4 shows a 15-cm-long metal rod pulled...Ch. 25 - Prob. 5P Ch. 25 - In the rainy season, the Amazon flows fast and...Ch. 25 - A delivery truck with 2.8-m-high aluminum sides is...Ch. 25 - Prob. 8P Ch. 25 - Prob. 9P Ch. 25 - Prob. 10P Ch. 25 - Prob. 11P Ch. 25 - Prob. 12P Ch. 25 - Prob. 13P Ch. 25 - A magnet and a coil are oriented as shown in...Ch. 25 - A 1000-turn coil of wire 2.0 cm in diameter is in...Ch. 25 - Figure P25.I6 shows a 100-turn coil of wire of...Ch. 25 - Figure P25.17 shows a 10-cm-diameter loop in three...Ch. 25 - Prob. 18P Ch. 25 - Prob. 19P Ch. 25 - Prob. 20P Ch. 25 - Prob. 21P Ch. 25 - Prob. 22P Ch. 25 - Prob. 23P Ch. 25 - Prob. 24P Ch. 25 - Prob. 25P Ch. 25 - Prob. 26P Ch. 25 - A microwave oven operates at 2.4 GHz with an...Ch. 25 - The maximum allowed leakage of microwave radiation...Ch. 25 - Prob. 29P Ch. 25 - Prob. 30P Ch. 25 - At what distance from a 10 mW point source of...Ch. 25 - Prob. 32P Ch. 25 - A radio antenna broadcasts a 1.0 MHz radio wave...Ch. 25 - Prob. 34P Ch. 25 - The intensity of a polarized electromagnetic wave...Ch. 25 - Prob. 36P Ch. 25 - Prob. 37P Ch. 25 - Prob. 39P Ch. 25 - Prob. 40P Ch. 25 - Prob. 41P Ch. 25 - Prob. 42P Ch. 25 - One recent study has shown that x rays with a...Ch. 25 - Prob. 44P Ch. 25 - Prob. 45P Ch. 25 - Prob. 47P Ch. 25 - Prob. 48P Ch. 25 - Prob. 49P Ch. 25 - A particular species of copepod, a small marine...Ch. 25 - Prob. 51P Ch. 25 - Prob. 52P Ch. 25 - Prob. 53P Ch. 25 - Prob. 54P Ch. 25 - Prob. 55P Ch. 25 - A python can detect thermal radiation with...Ch. 25 - If astronomers look toward any point in outer...Ch. 25 - Prob. 58GP Ch. 25 - People immersed in strong unchanging magnetic...Ch. 25 - Prob. 60GP Ch. 25 - Prob. 61GP Ch. 25 - Prob. 62GP Ch. 25 - A 20-cm-long, zero-resistance wire is pulled...Ch. 25 - A TMS (transeranial magnetic stimulation) device...Ch. 25 - The 10-cm-wide, zero-resistance wire shown in...Ch. 25 - Experiments to study vision often need to track...Ch. 25 - A LASIK vision correction system uses a laser that...Ch. 25 - A new cordless phone emits 4.0 mW at 5.8 GHz. The...Ch. 25 - In reading the instruction manual that came with...Ch. 25 - Unpolarized light passes through a vertical...Ch. 25 - Prob. 72GP Ch. 25 - Prob. 73GP Ch. 25 - Prob. 74GP Ch. 25 - What is the wavelength of 27 MHz radio waves? A....Ch. 25 - If the frequency of the radio waves is increased,...Ch. 25 - Prob. 77MSPP Ch. 25 - The metal detector will not detect insulators...Ch. 25 - A metal detector can detect the presence of metal...Ch. 25 - Which of the following changes would not produce a...

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The amplitudes of oscillating electric and magnetic fields in the laser beam.

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To find: The amplitudes of oscillating electric and magnetic fields in the laser beam.

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Chapter 25 Solutions