Chapter 25, Problem 25.1P

Interpretation Introduction

(a)

Interpretation:

Appropriate curved arrows and products for the homolysis of the $\text{C-C}$ bond in ethane are to be drawn.

Concept introduction:

The breaking of a covalent bond, whereby the electrons making up that bond are distributed equally to the atoms which are disconnected, is known as the homolytic bond dissociation or homolysis. In homolysis, generally radicals are formed. In homolysis, a covalent bond is broken down equally and each atom acquires a single electron, which is called a radical, and a single barbed arrow () is used to represent the movement of a single electron in a homolysis process.

Answer to Problem 25.1P

Appropriate curved arrow for the homolysis of the $\text{C-C}$ bond in ethane:

The product for the homolysis of the $\text{C-C}$ bond in ethane:

Explanation of Solution

The homolysis of the $\text{C-C}$ bond in ethane is given below:

A single barbed arrow () is used to represent the movement of a single electron in a homolysis process. In homolysis, a covalent bond is broken down equally and each atom acquires a single electron, which is called a radical. Thus, the product of the homolysis of the $\text{C-C}$ bond in ethane:

Conclusion

Appropriate curved arrows and products for the homolysis of the $\text{C-C}$ bond in ethane are drawn.

Interpretation Introduction

(b)

Interpretation:

Appropriate curved arrows and products for the homolysis of the $\text{C-H}$ bond in ethane are to be drawn.

Concept introduction:

The breaking of a covalent bond, whereby the electrons making up that bond are distributed equally to the atoms which are disconnected, is known as the homolytic bond dissociation or homolysis. In homolysis, generally radicals are formed. In homolysis, a covalent bond is broken down equally and each atom acquires a single electron, which is called a radical, and a single barbed arrow () is used to represent the movement of a single electron in a homolysis process.

Answer to Problem 25.1P

Appropriate curve arrow for the homolysis of the $\text{C-H}$ bond in ethane:

The product for the homolysis of the $\text{C-H}$ bond in ethane:

Explanation of Solution

The homolysis of the $\text{C-H}$ bond in ethane is given below:

A single barbed arrow () is used to represent the movement of a single electron in a homolysis process. In homolysis, a covalent bond is broken down equally and each atom acquires a single electron, which is called a radical. Thus the product of the homolysis of the $\text{C-H}$ bond in ethane:

Conclusion

Appropriate curved arrows and products for the homolysis of a $\text{C-H}$ bond in ethane are drawn.

Interpretation Introduction

(c)

Interpretation:

Appropriate curved arrows and products for the homolysis of the $\text{C-Br}$ bond in $\text{2-bromopropane}$ are to be drawn.

Concept introduction:

The breaking of a covalent bond, whereby the electrons making up that bond are distributed equally to the atoms which are disconnected, is known as the homolytic bond dissociation or homolysis. In homolysis, generally radicals are formed. In homolysis, a covalent bond is broken down equally and each atom acquires a single electron, which is called a radical, and a single barbed arrow () is used to represent the movement of a single electron in a homolysis process.

Answer to Problem 25.1P

The appropriate curve arrow for the homolysis of t the $\text{C-Br}$ bond in $\text{2-bromopropane}$:

The product for the homolysis of the $\text{C-Br}$ bond in $\text{2-bromopropane}$:

Explanation of Solution

The homolysis of the $\text{C-Br}$ bond in $\text{2-bromopropane}$ is given below:

A single barbed arrow () is used to represent the movement of a single electron in a homolysis process. In homolysis, a covalent bond is broken down equally and each atom acquires a single electron, which is called a radical. Thus the product of the homolysis of the $\text{C-Br}$ bond in $\text{2-bromopropane}$:

Conclusion

Appropriate curved arrows and products for the homolysis of the $\text{C-Br}$ bond in $\text{2-bromopropane}$ are drawn.

Interpretation Introduction

(d)

Interpretation:

Appropriate curved arrows and products for the homolysis of the $\text{C-H}$ bond in benzene are to be drawn.

Concept introduction:

The breaking of a covalent bond, whereby the electrons making up that bond are distributed equally to the atoms which are disconnected, is known as the homolytic bond dissociation or homolysis. In homolysis, generally radicals are formed. In homolysis, a covalent bond is broken down equally and each atom acquires a single electron, which is called a radical, and a single barbed arrow () is used to represent the movement of a single electron in a homolysis process.

Answer to Problem 25.1P

The appropriate curve arrow for the homolysis of the $\text{C-H}$ bond in benzene:

The product for the homolysis of the $\text{C-H}$ bond in benzene:

Explanation of Solution

The homolysis of the $\text{C-H}$ bond in benzene is given below:

A single barbed arrow () is used to represent the movement of a single electron in a homolysis process. In homolysis, a covalent bond is broken down equally and each atom acquires a single electron, which is called a radical. Thus the product of the homolysis of the $\text{C-H}$ bond in benzene:

Conclusion

Appropriate curved arrows and products for the homolysis of a $\text{C-H}$ bond in benzene are drawn.