Principles of Physics: A Calculus-Based Text, Hybrid (with Enhanced WebAssign Printed Access Card)
Principles of Physics: A Calculus-Based Text, Hybrid (with Enhanced WebAssign Printed Access Card)
5th Edition
ISBN: 9781305586871
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 25, Problem 1OQ
To determine

The critical angle for total internal reflection of a light ray when incident on a liquid to glass surface.

Expert Solution & Answer
Check Mark

Answer to Problem 1OQ

Option (b).

Explanation of Solution

Write the expression for critical angle.

    θc=sin1(n2n1)        (I)

Here, θc is the critical angle, n2 is the refractive index of lighter medium 2, and n1 is the refractive index of the denser medium 1.

Given that the refractive index of carbon disulfide is n1=1.63, and the refractive index of crown glass is n2=1.52.

Conclusion:

Substitute 1.63 for n1, and 1.52 for n2 in equation (I), to find θc.

    θc=sin1(1.521.63)=68.8°

Since the critical angle of a light ray when incident on a liquid to glass surface is 68.8°. option (b) is correct.

The critical angle of a light ray when incident on a liquid to glass surface is 68.8°. Thus, option (a) is incorrect.

The critical angle of a light ray when incident on a liquid to glass surface is 68.8°. Thus, option (c) is incorrect.

The critical angle of a light ray when incident on a liquid to glass surface is 68.8°. Thus, option (d) is incorrect.

The critical angle of a light ray when incident on a liquid to glass surface is 68.8°. Thus, option (e) is incorrect.

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Chapter 25 Solutions

Principles of Physics: A Calculus-Based Text, Hybrid (with Enhanced WebAssign Printed Access Card)

Ch. 25 - Prob. 4OQCh. 25 - The index of refraction for water is about 43....Ch. 25 - Prob. 6OQCh. 25 - Light traveling in a medium of index of refraction...Ch. 25 - Prob. 8OQCh. 25 - The core of an optical fiber transmits light with...Ch. 25 - Prob. 10OQCh. 25 - A light ray travels from vacuum into a slab of...Ch. 25 - Prob. 12OQCh. 25 - Prob. 13OQCh. 25 - Prob. 14OQCh. 25 - Prob. 1CQCh. 25 - Prob. 2CQCh. 25 - Prob. 3CQCh. 25 - Prob. 4CQCh. 25 - Prob. 5CQCh. 25 - Prob. 6CQCh. 25 - Prob. 7CQCh. 25 - Prob. 8CQCh. 25 - Prob. 9CQCh. 25 - Prob. 10CQCh. 25 - Prob. 11CQCh. 25 - Prob. 12CQCh. 25 - Prob. 1PCh. 25 - Prob. 2PCh. 25 - Prob. 3PCh. 25 - Prob. 4PCh. 25 - Prob. 5PCh. 25 - Prob. 6PCh. 25 - Prob. 7PCh. 25 - An underwater scuba diver sees the Sun at an...Ch. 25 - Prob. 9PCh. 25 - Prob. 10PCh. 25 - A ray of light is incident on a flat surface of a...Ch. 25 - A laser beam is incident at an angle of 30.0 from...Ch. 25 - Prob. 13PCh. 25 - A light ray initially in water enters a...Ch. 25 - Find the speed of light in (a) flint glass, (b)...Ch. 25 - Prob. 16PCh. 25 - Prob. 17PCh. 25 - Prob. 18PCh. 25 - Unpolarized light in vacuum is incident onto a...Ch. 25 - Prob. 20PCh. 25 - Prob. 21PCh. 25 - Prob. 22PCh. 25 - Prob. 23PCh. 25 - Prob. 24PCh. 25 - 14. A ray of light strikes the midpoint of one...Ch. 25 - Prob. 26PCh. 25 - Prob. 27PCh. 25 - Prob. 28PCh. 25 - Prob. 29PCh. 25 - Prob. 30PCh. 25 - Prob. 31PCh. 25 - Around 1965, engineers at the Toro Company...Ch. 25 - Prob. 33PCh. 25 - Prob. 34PCh. 25 - Prob. 35PCh. 25 - Prob. 36PCh. 25 - Prob. 37PCh. 25 - Prob. 38PCh. 25 - Prob. 39PCh. 25 - Prob. 40PCh. 25 - Prob. 41PCh. 25 - Prob. 42PCh. 25 - A 4.00-m-long pole stands vertically in a...Ch. 25 - Prob. 44PCh. 25 - Prob. 45PCh. 25 - Prob. 46PCh. 25 - Prob. 47PCh. 25 - Prob. 48PCh. 25 - When light is incident normally on the interface...Ch. 25 - Prob. 50PCh. 25 - Prob. 51PCh. 25 - Prob. 52PCh. 25 - The light beam in Figure P25.53 strikes surface 2...Ch. 25 - Prob. 54PCh. 25 - Prob. 55PCh. 25 - Prob. 56PCh. 25 - Prob. 57PCh. 25 - Prob. 58PCh. 25 - Prob. 59PCh. 25 - Prob. 60PCh. 25 - Prob. 61PCh. 25 - Prob. 62P
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