PROBLEMS For problems 13 − 18 , use Gauss-Jordan elimination to determine the solution set to the given system. 2 x 1 − x 2 + 3 x 3 + x 4 − x 5 = 11 , x 1 − 3 x 2 − 2 x 3 − x 4 − 2 x 5 = 2 , 3 x 1 + x 2 − 2 x 3 − x 4 + x 5 = − 2 , x 1 + 2 x 2 + x 3 + 2 x 4 + 3 x 5 = − 3 , 5 x 1 − 3 x 2 − 3 x 3 + x 4 + 2 x 5 = 2.
PROBLEMS For problems 13 − 18 , use Gauss-Jordan elimination to determine the solution set to the given system. 2 x 1 − x 2 + 3 x 3 + x 4 − x 5 = 11 , x 1 − 3 x 2 − 2 x 3 − x 4 − 2 x 5 = 2 , 3 x 1 + x 2 − 2 x 3 − x 4 + x 5 = − 2 , x 1 + 2 x 2 + x 3 + 2 x 4 + 3 x 5 = − 3 , 5 x 1 − 3 x 2 − 3 x 3 + x 4 + 2 x 5 = 2.
Solution Summary: The author explains the Gauss-Jordan elimination solution for the system l2.
For problems
13
−
18
, use Gauss-Jordan elimination to determine the solution set to the given system.
2
x
1
−
x
2
+
3
x
3
+
x
4
−
x
5
=
11
,
x
1
−
3
x
2
−
2
x
3
−
x
4
−
2
x
5
=
2
,
3
x
1
+
x
2
−
2
x
3
−
x
4
+
x
5
=
−
2
,
x
1
+
2
x
2
+
x
3
+
2
x
4
+
3
x
5
=
−
3
,
5
x
1
−
3
x
2
−
3
x
3
+
x
4
+
2
x
5
=
2.
I want to learn this topic l dont know anything about it
Solve the linear system of equations attached using Gaussian elimination (not Gauss-Jordan) and back subsitution.
Remember that:
A matrix is in row echelon form if
Any row that consists only of zeros is at the bottom of the matrix.
The first non-zero entry in each other row is 1. This entry is called aleading 1.
The leading 1 of each row, after the first row, lies to the right of the leading 1 of the previous row.
Chapter 2 Solutions
Differential Equations And Linear Algebra, Books A La Carte Edition (4th Edition)
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