Study Guide with Lab Manual for Jeffus' Welding: Principles and Applications, 8th
8th Edition
ISBN: 9781305494701
Author: Larry Jeffus
Publisher: Cengage Learning
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Chapter 25, Problem 16R
What is undercut?
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A flanged bolt coupling consists of two concentric rows of bolts. The inner row has 6 nos. of 16mm diameterbolts spaced evenly in a circle of 250mm in diameter. The outer row of has 10 nos. of 25 mm diameter bolts spaced evenly in a circle of 500mm in diameter. If the allowable shear stress on one bolt is 60 MPa, determine the torque capacity of the coupling. The Poisson’s ratio of the inner row of bolts is 0.2 while that of the outer row is 0.25 and the bolts are steel, E =200 GPa.
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10: The constant wall thickness of a steel tube with the cross sectionshown is 2 mm. If a 600-N-m torque is applied to the tube. Use G = 80 GPa forsteel.1. Find the shear stress (MPa) in the wall of the tube.2. Find the angle of twist, in degrees per meter of length.
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A torque wrench is used to tighten the pipe shown.Dimensions: S1 = 400 mm; S2 = 250 mm; S3 = 100 mmModulus of Rigidity G = 78 GPa1. The diameter of the solid pipe is 20 mm. How much is themaximum force P (N) that can be applied based on theallowable shear stress of 60 MPa?2. For a hollow pipe with 50 mm outside diameter and is 6 mmthick, compute for the maximum force P (kN) that can beapplied such that the angle of twist at A does not exceed 5degrees.3. The torque applied to tighten the hollow pipe is 200 N-m.Given: Pipe outside diameter = 50 mm Pipe thickness = 6 mmSolve for the resulting maximum shear stress (MPa) in the pipe.
Chapter 25 Solutions
Study Guide with Lab Manual for Jeffus' Welding: Principles and Applications, 8th
Ch. 25 - Why are all welds not inspected to the same level...Ch. 25 - Why is the strength of all production parts not...Ch. 25 - Why is it possible to do more than one...Ch. 25 - What is a discontinuity?Ch. 25 - What is a defect?Ch. 25 - What is tolerance?Ch. 25 - What are the 12 most common discontinuities?Ch. 25 - How can porosity form in a weld and not be seen by...Ch. 25 - What welding process can cause porosity to form?Ch. 25 - How is piping porosity formed?
Ch. 25 - What are inclusions, and how are they caused?Ch. 25 - When does inadequate joint penetration usually...Ch. 25 - How can a notch cause incomplete fusion?Ch. 25 - How can an arc strike appear on a guided-bend...Ch. 25 - What is overlap?Ch. 25 - What is undercut?Ch. 25 - What causes crater cracks?Ch. 25 - What is underfill?Ch. 25 - What is the difference between a lamination and a...Ch. 25 - How can stress be reduced through a plate's...Ch. 25 - What would be the tensile strength in pounds per...Ch. 25 - What would be the elongation for a specimen for...Ch. 25 - How are the results of a stress test reported?Ch. 25 - What would be the transverse shear strength per...Ch. 25 - What would be the longitudinal shearing strength...Ch. 25 - What are the three methods of destructive testing...Ch. 25 - How are the specimens bent for a guided-. root-,...Ch. 25 - How wide should a specimen be if the material...Ch. 25 - Why are guidelines drawn on the surface of a...Ch. 25 - What part of a fillet weld break test is examined?Ch. 25 - What can happen if acids are handled carelessly?Ch. 25 - What information about the weld does an impact...Ch. 25 - Which nondestructive test is most commonly used?Ch. 25 - List the five steps to be followed when using a...Ch. 25 - What properties must metal have before it can be...Ch. 25 - Why will some flaws appear larger on an X-ray than...Ch. 25 - How is the size of a flaw determined using...Ch. 25 - What is the major limitation of eddy current...Ch. 25 - What information does a hardness test reveal?Ch. 25 - Why is it important to select the correct welding...
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- Correct answer and complete fbd only. I will upvote. 6: The shaft carries a total torque T0 that is uniformly distributedover its length L. Determine the angle of twist (degrees) of the shaft in termsif T0 = 1.2 kN-m, L = 2 m, G = 80 GPa, and diameter = 120 mm.arrow_forward2. Calculate the force in all members of the trusses shown using the method of joints. A 5525 lb C 3500 lb BY 14'-0" D 10'- 0" 6250 lb 10'- 0" Earrow_forwardCorrect answer and complete fbd only. I will upvote. 8: The steel rod fits loosely inside the aluminum sleeve. Both components are attached to a rigid wall at A andjoined together by a pin at B. Because of a slight misalignmentof the pre-drilled holes, the torque T0 = 750 N-m was appliedto the steel rod before the pin could be inserted into theholes. Determine the torque (N-m) in each component afterT0 was removed. Use G = 80 GPa for steel and G = 28 GPa foraluminumarrow_forward
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- The solid compound shaft, made of threedifferent materials, carries the two torques shown. Theshear moduli are 28 GPa for aluminum, 83 GPa for steel,and 35 GPa for bronze.1. Calculate the maximum shear stress (MPa) in eachmaterial.2. Find the angle of rotation (degrees) of the free endof the shaft.arrow_forwardCorrect answer only please. I will upvote. The velocity of a particle moves along the x-axis and is given by the equation ds/dt = 40 - 3t^2 m/s. Calculate the acceleration at time t=2 s and t=4 s. Calculate also the total displacement at the given interval. Assume at t=0 s=5m.Write the solution using pen and draw the graph if needed.arrow_forwardI want the steps of operation of the circuit, clearly in detail. Please. LV1arrow_forward
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