Chapter 25, Problem 16A

To determine

(A)

The dimension of A in inches.

Answer to Problem 16A

The dimension of A in inches is $2.756\text{in}$.

Explanation of Solution

Given information:

The schematic diagram of the system is shown below.

Figure-(1)

Write the expression for the dimension in inches.

  $L_{\text{in}}=\left({\text{L}}_{\text{mm}}\right)\left(\frac{1\text{in}}{25.4\text{mm}}\right)$ ...... (I)

Here, the dimension in inches is $L_{\text{in}}$ and the dimension in millimetres is $L_{\text{mm}}$.

Calculation:

Substitute $70.00\text{mm}$ for $L_{\text{mm}}$ in Equation (I).

  $\begin{array}{c}{L}_{\text{in}}=\left(70.00\text{mm}\right)\left(\frac{1\text{in}}{25.4\text{mm}}\right)\\ =2.7559\text{in}\\ \approx \text{2}\text{.756}\text{in}\end{array}$

Conclusion:

The dimension of A in inches is $2.756\text{in}$.

To determine

(B)

The dimension of B in inches.

Answer to Problem 16A

The dimension of B in inches is $1.959\text{in}$.

Explanation of Solution

Substitute $49.78\text{mm}$ for $L_{\text{mm}}$ in Equation (I).

  $\begin{array}{c}{L}_{\text{in}}=\left(49.78\text{mm}\right)\left(\frac{1\text{in}}{25.4\text{mm}}\right)\\ =1.9586\text{in}\\ \approx \text{1}\text{.959}\text{in}\end{array}$

Conclusion:

The dimension of B in inches is $1.959\text{in}$.

To determine

(C)

The dimension of C in inches.

Answer to Problem 16A

The dimension of C in inches is $0.325\text{in}$.

Explanation of Solution

Substitute $8.25\text{mm}$ for $L_{\text{mm}}$ in Equation (I).

  $\begin{array}{c}{L}_{\text{in}}=\left(8.25\text{mm}\right)\left(\frac{1\text{in}}{25.4\text{mm}}\right)\\ =0.3248\text{in}\\ \approx \text{0}\text{.325}\text{in}\end{array}$

Conclusion:

The dimension of C in inches is $0.325\text{in}$.

To determine

(D)

The dimension of D in inches.

Answer to Problem 16A

The dimension of D in inches is $0.236\text{in}$.

Explanation of Solution

Substitute $6.00\text{mm}$ for $L_{\text{mm}}$ in Equation (I).

  $\begin{array}{c}{L}_{\text{in}}=\left(6.00\text{mm}\right)\left(\frac{1\text{in}}{25.4\text{mm}}\right)\\ =0.2362\text{in}\\ \approx \text{0}\text{.236}\text{in}\end{array}$

Conclusion:

The dimension of D in inches is $0.236\text{in}$.

To determine

(E)

The dimension of E in inches.

Answer to Problem 16A

The dimension of E in inches is $0.823\text{in}$.

Explanation of Solution

Substitute $20.90\text{mm}$ for $L_{\text{mm}}$ in Equation (I).

  $\begin{array}{c}{L}_{\text{in}}=\left(20.90\text{mm}\right)\left(\frac{1\text{in}}{25.4\text{mm}}\right)\\ =0.8228\text{in}\\ \approx \text{0}\text{.823}\text{in}\end{array}$

Conclusion:

The dimension of E in inches is $0.823\text{in}$.

To determine

(F)

The dimension of F in inches.

Answer to Problem 16A

The dimension of F in inches is $0.138\text{in}$.

Explanation of Solution

Substitute $3.50\text{mm}$ for $L_{\text{mm}}$ in Equation (I).

  $\begin{array}{c}{L}_{\text{in}}=\left(3.50\text{mm}\right)\left(\frac{1\text{in}}{25.4\text{mm}}\right)\\ =0.1377\text{in}\\ \approx \text{0}\text{.138}\text{in}\end{array}$

Conclusion:

The dimension of F in inches is $0.138\text{in}$.

To determine

(G)

The dimension of G in inches.

Answer to Problem 16A

The dimension of G in inches is $0.561\text{in}$.

Explanation of Solution

Substitute $14.25\text{mm}$ for $L_{\text{mm}}$ in Equation (I).

  $\begin{array}{c}{L}_{\text{in}}=\left(14.25\text{mm}\right)\left(\frac{1\text{in}}{25.4\text{mm}}\right)\\ =0.5610\text{in}\\ \approx \text{0}\text{.561}\text{in}\end{array}$

Conclusion:

The dimension of G in inches is $0.561\text{in}$.

To determine

(H)

The dimension of H in inches.

Answer to Problem 16A

The dimension of H in inches is $0.236\text{in}$.

Explanation of Solution

Substitute $6.00\text{mm}$ for $L_{\text{mm}}$ in Equation (I).

  $\begin{array}{c}{L}_{\text{in}}=\left(6.00\text{mm}\right)\left(\frac{1\text{in}}{25.4\text{mm}}\right)\\ =0.2362\text{in}\\ \approx \text{0}\text{.236}\text{in}\end{array}$

Conclusion:

The dimension of H in inches is $0.236\text{in}$.

To determine

(I)

The dimension of I in inches.

Answer to Problem 16A

The dimension of I in inches is $1.126\text{in}$.

Explanation of Solution

Substitute $28.60\text{mm}$ for $L_{\text{mm}}$ in Equation (I).

  $\begin{array}{c}{L}_{\text{in}}=\left(28.60\text{mm}\right)\left(\frac{1\text{in}}{25.4\text{mm}}\right)\\ =1.1259\text{in}\\ \approx \text{1}\text{.126}\text{in}\end{array}$

Conclusion:

The dimension of I in inches is $1.126\text{in}$.

To determine

(J)

The dimension of J in inches.

Answer to Problem 16A

The dimension of J in inches is $0.630\text{in}$.

Explanation of Solution

Substitute $16.00\text{mm}$ for $L_{\text{mm}}$ in Equation (I).

  $\begin{array}{c}{L}_{\text{in}}=\left(16.00\text{mm}\right)\left(\frac{1\text{in}}{25.4\text{mm}}\right)\\ =0.6299\text{in}\\ \approx \text{0}\text{.630}\text{in}\end{array}$

Conclusion:

The dimension of J in inches is $0.630\text{in}$.

To determine

(K)

The dimension of K in inches.

Answer to Problem 16A

The dimension of K in inches is $0.232\text{in}$.

Explanation of Solution

Substitute $5.88\text{mm}$ for $L_{\text{mm}}$ in Equation (I).

  $\begin{array}{c}{L}_{\text{in}}=\left(5.88\text{mm}\right)\left(\frac{1\text{in}}{25.4\text{mm}}\right)\\ =0.23149\text{in}\\ \approx \text{0}\text{.232}\text{in}\end{array}$

Conclusion:

The dimension of K in inches is $0.232\text{in}$.

To determine

(L)

The dimension of L in inches.

Answer to Problem 16A

The dimension of L in inches is $0.363\text{in}$.

Explanation of Solution

Substitute $9.22\text{mm}$ for $L_{\text{mm}}$ in Equation (I).

  $\begin{array}{c}{L}_{\text{in}}=\left(9.22\text{mm}\right)\left(\frac{1\text{in}}{25.4\text{mm}}\right)\\ =0.3629\text{in}\\ \approx \text{0}\text{.363}\text{in}\end{array}$

Conclusion:

The dimension of L in inches is $0.363\text{in}$.