(a) Explanation Given data: Diameter of the solenoid is 2.0 cm. Diameter of the loop is 6.0 cm. Magnetic field inside the solenoid is 0.2 T. Angle of the loop is perpendicular to the solenoid. Formula used: Write the expression for magnetic flux through coil. Φ = B A cos θ (1) Here, Φ is the magnetic flux, A is the area, and θ is the angle between the plane of area to the magnetic field. Write the expression for area of circle. A = π r 2 (2) Here, A is the area of the circle and r is the radius. Explanation: Solenoid have a constant magnetic field with equal value at every point inside and zero outside. So, the flux in the loop can only occur inside the solenoid as the electric field inside is not zero. The flux inside the loop is equal to that inside solenoid, since the area of the loop is completely inside the solenoid. For loop, Φ loop = B loop A loop cos θ (3) For Solenoid, Φ sol = B sol A sol cos θ (4) Equating equation (3) and (4), Φ = B sol A sol cos θ (5) Area of the solenoid is calculated as follows. Substitute 0.01 m for r in equation (2), A sol = π ( 0 (b) To determine The magnetic flux through the loop.

3rd Edition

ISBN: 9780321989246

Author: Knight

Publisher: PEARSON CO

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Chapter 25, Problem 11P

(a)

To determine

The magnetic flux through the loop.

(b)

To determine

The magnetic flux through the loop.

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Chapter 25, Problem 10P

Chapter 25, Problem 12P

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