Explanation Let x is the side of rectangular corral and y is the length of rectangular corral. Obtain the perimeter of the rectangular corral as follows. P = 2 ( x + y ) Substituting, P = 2400 in P = 2 ( x + y ) . P = 2 ( x + y ) 2400 = 2 ( x + y ) x + y = 1200 y = 1200 − x It is known that the area of rectangular corral is A = x * y . Substitute, y = 1200 − x in A = x * y as shown below. A = x * y = x ( 1200 − x ) Now, differentiate A with respect to x as follows. A = x ( 1200 − x ) d R d x = ( 1200 − x ) + x ( − 1 ) d R d x = 1200 − 2 x In order to obtain the maxima and minima substitute d A d x = 0 . 1200 − 2 x = 0 2 x = 1200 x = 1200 2 x = 600 Differentiate d A d x with respect to x as shown below

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ISBN: 9780134437705

Author: Washington

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Chapter 24.7, Problem 1E

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The maximum possible area of rectangular corral.

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Chapter 24.7, Problem 2PE

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