Chapter 24.6, Problem 24.7AFP

Interpretation Introduction

Interpretation:

Binding energy per nucleon of ${}^{\text{58}}\text{Ni}$ has to be calculated and compared with the value of binding energy per nucleon of ${}^{\text{56}}\text{Fe}$.

Concept Introduction:

Nuclear reaction: A nuclear reaction in which a lighter nucleus fuses together into new stable nuclei or a heavier nucleus split into stable daughter nuclei with the release of large amount of energy.

Nuclear binding energy: It is the energy that requires for the breaking one mole of nuclei of an element to its individual nucleons.

  $\text{Nucleus + nuclear binding energy }\underset{}{\to }\text{ nucleons}$

It can be calculated using the given formula,

  $\text{Binding energy = }\Delta \text{m}\left(\text{in amu}\right)\times \frac{\text{931}\text{.5 MeV}}{1\text{ amu}}$

Binding Energy per Nucleon can be determined as follows:

  $\text{Binding energy per nucleon = }\frac{\text{Binding energy}}{\text{No}\text{. of nucleons}}$