ORGANIC CHEMISTRY-STUD.SOLNS.MAN+SG(LL)
4th Edition
ISBN: 9781119659587
Author: Klein
Publisher: WILEY
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Question
Chapter 24.5, Problem 21CC
Interpretation Introduction
Interpretation:
The mechanism for the acid catalyzed cyclisation of D-fructose to β-D-fructofuranose should be drawn.
Concept introduction:
- Hemiacetal are formed for the compound having both hydroxyl group and
aldehyde group in acidic condition. - The –OH group of compound attacks the carbonyl group of the same compound, thereby a ring is formed by the carbon atoms and oxygen atom of –OH group with incorporating into the ring.
- Acid catalyzed reaction are followed by the deprotonation of Hydronium ion to water molecule and then protonation of this water molecule will return to Hydronium ion will take place.
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Students have asked these similar questions
Predict the organic products that form in the reaction below:
OH
H+
H+
+
☑
Y
Note: You may assume you have an excess of either reactant if the reaction requires more than one of those molecules to form the products.
In the drawing area below, draw the skeletal ("line") structures of the missing organic products X and Y. You may draw the structures in any arrangement that
you like, so long as they aren't touching.
Click and drag to start drawing a
structure.
✓
m
Determine the structures of the missing organic molecules in the following reaction:
+ H₂O
+H
H+
Y
Z
☑
☑
Note: Molecules that share the same letter have the exact same structure.
In the drawing area below, draw the skeletal ("line") structures of the missing organic molecules X, Y, and Z. You may draw the structures in any arrangement
that you like, so long as they aren't touching. Molecule X shows up in multiple steps, but you only have to draw its structure once.
Click and drag to start drawing a structure.
AP
+
Please help, this is all the calculations
i got!!! I will rate!!!Approx mass of
KMnO in vial: 3.464
4
Moss of beaker 3×~0. z Nax200:
= 29.9219
Massof weacerv after remosimgain
N2C2O4. Need to fill in all the
missing blanks.
ง
ง
Approx mass of KMnO4 in vials 3.464
Mass of beaker + 3x ~0-304: 29.9219
2~0.20
Miss of beaker + 2x-
29.7239
Mass of beaker + 1x~0.2g Naz (204
29-5249
Mass of beaver after removing as
qa Na₂ C₂O
T1
T2
T3
Final Buiet reading
Initial butet reading (int))
Hass of NaOr used for Titration
-reading (mL)
calculation Results:
8.5ml
17mL
27.4mL
Oml
Om
Oml
T1
T2
T3
Moles of No CO
Moles of KMO used
LOF KM. O used
Molenty of KMNO
Averagem Of KMOWL
Chapter 24 Solutions
ORGANIC CHEMISTRY-STUD.SOLNS.MAN+SG(LL)
Ch. 24.2 - Prob. 1CCCh. 24.2 - Prob. 2CCCh. 24.2 - Prob. 3CCCh. 24.2 - Prob. 4CCCh. 24.2 - Prob. 5CCCh. 24.2 - Prob. 6CCCh. 24.4 - Prob. 7CCCh. 24.4 - Prob. 8CCCh. 24.5 - Prob. 1LTSCh. 24.5 - Prob. 9PTS
Ch. 24.5 - Prob. 2LTSCh. 24.5 - Prob. 12PTSCh. 24.5 - Prob. 13PTSCh. 24.5 - Prob. 3LTSCh. 24.5 - Prob. 16PTSCh. 24.5 - Prob. 19CCCh. 24.5 - Prob. 20CCCh. 24.5 - Prob. 21CCCh. 24.5 - Prob. 22CCCh. 24.6 - Prob. 23CCCh. 24.6 - Prob. 24CCCh. 24.6 - Prob. 25CCCh. 24.6 - Prob. 26CCCh. 24.6 - Prob. 27CCCh. 24.6 - Prob. 28CCCh. 24.6 - Prob. 29CCCh. 24.6 - Prob. 30CCCh. 24.6 - Prob. 4LTSCh. 24.6 - Prob. 31PTSCh. 24.6 - Prob. 34CCCh. 24.6 - Prob. 35CCCh. 24.6 - Prob. 36CCCh. 24.6 - Prob. 37CCCh. 24.6 - Prob. 38CCCh. 24.7 - Prob. 5LTSCh. 24.7 - Prob. 39PTSCh. 24.7 - Prob. 41CCCh. 24 - Prob. 42PPCh. 24 - Prob. 43PPCh. 24 - Prob. 44PPCh. 24 - Prob. 45PPCh. 24 - Prob. 46PPCh. 24 - Prob. 47PPCh. 24 - Prob. 48PPCh. 24 - Prob. 49PPCh. 24 - Prob. 50PPCh. 24 - Prob. 51PPCh. 24 - Prob. 52PPCh. 24 - Prob. 53PPCh. 24 - Prob. 54PPCh. 24 - Prob. 55PPCh. 24 - Prob. 56PPCh. 24 - Prob. 57PPCh. 24 - Prob. 58PPCh. 24 - Prob. 59PPCh. 24 - Prob. 60PPCh. 24 - Prob. 61PPCh. 24 - Prob. 62PPCh. 24 - Prob. 63PPCh. 24 - Prob. 64PPCh. 24 - Prob. 65PPCh. 24 - Prob. 66PPCh. 24 - Prob. 67PPCh. 24 - Prob. 68PPCh. 24 - Prob. 69PPCh. 24 - Prob. 70PPCh. 24 - Prob. 71PPCh. 24 - Prob. 72PPCh. 24 - Prob. 73PPCh. 24 - Prob. 74PPCh. 24 - Prob. 75PPCh. 24 - Prob. 76PPCh. 24 - Prob. 77PPCh. 24 - Prob. 78PPCh. 24 - Prob. 79PPCh. 24 - Prob. 80PPCh. 24 - Prob. 86IPCh. 24 - Prob. 87IPCh. 24 - Prob. 88IPCh. 24 - Prob. 89IP
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