Introduction to Algorithms
3rd Edition
ISBN: 9780262033848
Author: Thomas H. Cormen, Ronald L. Rivest, Charles E. Leiserson, Clifford Stein
Publisher: MIT Press
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Chapter 24.4, Problem 9E
Program Plan Intro
To show that the Bellman-Ford
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Consider the following implementation of a container that will be used in a concurrent environment. The container is supposed to be used like an indexed array, but provide thread-safe access to elements.
struct concurrent_container { // Assume it’s called for any new instance soon before it’s ever used void concurrent_container() { init_mutex(&lock); }
~concurrent_container() { destroy_mutex(&lock); }
// Returns element by its index. int get(int index) { lock.acquire(); if (index < 0 || index >= size) { return -1; }
int result = data[index]; lock.release(); return result; }
// Sets element by its index. void set(int index, int value) { lock.acquire(); if (index < 0 || index >= size) { resize(size); } data[index] = value; lock.release(); }
// Extend maximum capacity of the…
Write a C program using embedded assembler in which you use your own function to multiply by two without using the product.
Tip: Just remember that multiplying by two in binary means shifting the number one place to the left. You can use the sample program from the previous exercise as a basis, which increments a variable. Just replace the INC instruction with SHL.
Chapter 24 Solutions
Introduction to Algorithms
Ch. 24.1 - Prob. 1ECh. 24.1 - Prob. 2ECh. 24.1 - Prob. 3ECh. 24.1 - Prob. 4ECh. 24.1 - Prob. 5ECh. 24.1 - Prob. 6ECh. 24.2 - Prob. 1ECh. 24.2 - Prob. 2ECh. 24.2 - Prob. 3ECh. 24.2 - Prob. 4E
Ch. 24.3 - Prob. 1ECh. 24.3 - Prob. 2ECh. 24.3 - Prob. 3ECh. 24.3 - Prob. 4ECh. 24.3 - Prob. 5ECh. 24.3 - Prob. 6ECh. 24.3 - Prob. 7ECh. 24.3 - Prob. 8ECh. 24.3 - Prob. 9ECh. 24.3 - Prob. 10ECh. 24.4 - Prob. 1ECh. 24.4 - Prob. 2ECh. 24.4 - Prob. 3ECh. 24.4 - Prob. 4ECh. 24.4 - Prob. 5ECh. 24.4 - Prob. 6ECh. 24.4 - Prob. 7ECh. 24.4 - Prob. 8ECh. 24.4 - Prob. 9ECh. 24.4 - Prob. 10ECh. 24.4 - Prob. 11ECh. 24.4 - Prob. 12ECh. 24.5 - Prob. 1ECh. 24.5 - Prob. 2ECh. 24.5 - Prob. 3ECh. 24.5 - Prob. 4ECh. 24.5 - Prob. 5ECh. 24.5 - Prob. 6ECh. 24.5 - Prob. 7ECh. 24.5 - Prob. 8ECh. 24 - Prob. 1PCh. 24 - Prob. 2PCh. 24 - Prob. 3PCh. 24 - Prob. 4PCh. 24 - Prob. 5PCh. 24 - Prob. 6P
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