Expected weights in the F 1 progeny if genotype AABB is crossed with aabb . Introduction: In the given scenario, it is supposed that plant weight is determined by a pair of alleles at each of two independently assorting loci ( A and a , B and b ) that are additive in their effects. The alleles represented by uppercase letters contribute 4 grams to plant weight, while the alleles represented by lowercase letters contribute 1 gram to plant weight.

Question

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Answer 1

Question

Chapter 24.1, Problem 17AQP

(a)

Summary Introduction

To determine:

Expected weights in the F₁ progeny if genotype AABB is crossed with aabb.

Introduction:

In the given scenario, it is supposed that plant weight is determined by a pair of alleles at each of two independently assorting loci (A and a, B and b) that are additive in their effects. The alleles represented by uppercase letters contribute 4 grams to plant weight, while the alleles represented by lowercase letters contribute 1 gram to plant weight.

(a)

Expert Solution

Explanation of Solution

The cross between AABB and aabb is as follows:

Parents ♂ ♀ AABB × aabb ↓ ↓ Gamates AB ab ↘ ↙ ↓ F1 generation AaBb

F₁ (filial 1) generation is AaBb. Its weight can be determined as weight contributed by A + weight contributed by a + weight contributed by B + weight contributed by b (4 + 1 + 4 + 1). So, the plant weight in F₁ generation would be 10 grams.

(b)

Summary Introduction

To determine:

Expected weights in the F₂ progeny if genotype AABB is crossed with aabb.

Introduction:

In the given scenario, it is supposed that plant weight is determined by a pair of alleles at each of two independently assorting loci (A and a, B and b) that are additive in their effects. The alleles represented by uppercase letters contribute 4 grams to plant weight, while the alleles represented by lowercase letters contribute 1 gram to plant weight.

(b)

Expert Solution

Explanation of Solution

Gametes formed from F₁ generation would be AB, Ab, aB, and ab as follows:

F1 generation AaBb ↓Gamates AB Ab aB ab

F₂ generation is produced when F₁ generation is inter-crossed and their expected plant weights would be as follows:

ABAbaBabABAABB(4+4+4+4= 16g)AABb(4+4+4+1= 13g)AaBB(4+1+4+4= 13g)AaBb(4+1+4+1= 10g)AbAABb(4+4+4+1= 13g)AAbb(4+4+1+1= 10g)AaBb(4+1+4+1= 10g)Aabb(4+1+1+1= 7g)aBAaBB(4+1+4+4= 13g)AaBb(4+1+4+1= 10g)aaBB(1+1+4+4= 10g)aaBb(1+1+4+1= 7g)abAaBb(4+1+4+1= 10g)Aabb(4+1+1+1= 7g)aaBb(1+1+4+1= 7g)aabb(1+1+1+1= 4g)

Highest plant weight in F₂ generation would be of AABB (16 grams) and lowest would be of aabb (4 grams).

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Answer 2

Question

Chapter 24.1, Problem 17AQP

(a)

Summary Introduction

To determine:

Expected weights in the F₁ progeny if genotype AABB is crossed with aabb.

Introduction:

In the given scenario, it is supposed that plant weight is determined by a pair of alleles at each of two independently assorting loci (A and a, B and b) that are additive in their effects. The alleles represented by uppercase letters contribute 4 grams to plant weight, while the alleles represented by lowercase letters contribute 1 gram to plant weight.

(a)

Expert Solution

Explanation of Solution

The cross between AABB and aabb is as follows:

Parents ♂ ♀ AABB × aabb ↓ ↓ Gamates AB ab ↘ ↙ ↓ F1 generation AaBb

F₁ (filial 1) generation is AaBb. Its weight can be determined as weight contributed by A + weight contributed by a + weight contributed by B + weight contributed by b (4 + 1 + 4 + 1). So, the plant weight in F₁ generation would be 10 grams.

(b)

Summary Introduction

To determine:

Expected weights in the F₂ progeny if genotype AABB is crossed with aabb.

Introduction:

In the given scenario, it is supposed that plant weight is determined by a pair of alleles at each of two independently assorting loci (A and a, B and b) that are additive in their effects. The alleles represented by uppercase letters contribute 4 grams to plant weight, while the alleles represented by lowercase letters contribute 1 gram to plant weight.

(b)

Expert Solution

Explanation of Solution

Gametes formed from F₁ generation would be AB, Ab, aB, and ab as follows:

F1 generation AaBb ↓Gamates AB Ab aB ab

F₂ generation is produced when F₁ generation is inter-crossed and their expected plant weights would be as follows:

ABAbaBabABAABB(4+4+4+4= 16g)AABb(4+4+4+1= 13g)AaBB(4+1+4+4= 13g)AaBb(4+1+4+1= 10g)AbAABb(4+4+4+1= 13g)AAbb(4+4+1+1= 10g)AaBb(4+1+4+1= 10g)Aabb(4+1+1+1= 7g)aBAaBB(4+1+4+4= 13g)AaBb(4+1+4+1= 10g)aaBB(1+1+4+4= 10g)aaBb(1+1+4+1= 7g)abAaBb(4+1+4+1= 10g)Aabb(4+1+1+1= 7g)aaBb(1+1+4+1= 7g)aabb(1+1+1+1= 4g)

Highest plant weight in F₂ generation would be of AABB (16 grams) and lowest would be of aabb (4 grams).

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Answer 3

Question

Chapter 24.1, Problem 17AQP

(a)

Summary Introduction

To determine:

Expected weights in the F₁ progeny if genotype AABB is crossed with aabb.

Introduction:

In the given scenario, it is supposed that plant weight is determined by a pair of alleles at each of two independently assorting loci (A and a, B and b) that are additive in their effects. The alleles represented by uppercase letters contribute 4 grams to plant weight, while the alleles represented by lowercase letters contribute 1 gram to plant weight.

(a)

Expert Solution

Explanation of Solution

The cross between AABB and aabb is as follows:

Parents ♂ ♀ AABB × aabb ↓ ↓ Gamates AB ab ↘ ↙ ↓ F1 generation AaBb

F₁ (filial 1) generation is AaBb. Its weight can be determined as weight contributed by A + weight contributed by a + weight contributed by B + weight contributed by b (4 + 1 + 4 + 1). So, the plant weight in F₁ generation would be 10 grams.

(b)

Summary Introduction

To determine:

Expected weights in the F₂ progeny if genotype AABB is crossed with aabb.

Introduction:

In the given scenario, it is supposed that plant weight is determined by a pair of alleles at each of two independently assorting loci (A and a, B and b) that are additive in their effects. The alleles represented by uppercase letters contribute 4 grams to plant weight, while the alleles represented by lowercase letters contribute 1 gram to plant weight.

(b)

Expert Solution

Explanation of Solution

Gametes formed from F₁ generation would be AB, Ab, aB, and ab as follows:

F1 generation AaBb ↓Gamates AB Ab aB ab

F₂ generation is produced when F₁ generation is inter-crossed and their expected plant weights would be as follows:

ABAbaBabABAABB(4+4+4+4= 16g)AABb(4+4+4+1= 13g)AaBB(4+1+4+4= 13g)AaBb(4+1+4+1= 10g)AbAABb(4+4+4+1= 13g)AAbb(4+4+1+1= 10g)AaBb(4+1+4+1= 10g)Aabb(4+1+1+1= 7g)aBAaBB(4+1+4+4= 13g)AaBb(4+1+4+1= 10g)aaBB(1+1+4+4= 10g)aaBb(1+1+4+1= 7g)abAaBb(4+1+4+1= 10g)Aabb(4+1+1+1= 7g)aaBb(1+1+4+1= 7g)aabb(1+1+1+1= 4g)

Highest plant weight in F₂ generation would be of AABB (16 grams) and lowest would be of aabb (4 grams).

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Answer 4

Question

Chapter 24.1, Problem 17AQP

(a)

Summary Introduction

To determine:

Expected weights in the F₁ progeny if genotype AABB is crossed with aabb.

Introduction:

In the given scenario, it is supposed that plant weight is determined by a pair of alleles at each of two independently assorting loci (A and a, B and b) that are additive in their effects. The alleles represented by uppercase letters contribute 4 grams to plant weight, while the alleles represented by lowercase letters contribute 1 gram to plant weight.

(a)

Expert Solution

Explanation of Solution

The cross between AABB and aabb is as follows:

Parents ♂ ♀ AABB × aabb ↓ ↓ Gamates AB ab ↘ ↙ ↓ F1 generation AaBb

F₁ (filial 1) generation is AaBb. Its weight can be determined as weight contributed by A + weight contributed by a + weight contributed by B + weight contributed by b (4 + 1 + 4 + 1). So, the plant weight in F₁ generation would be 10 grams.

(b)

Summary Introduction

To determine:

Expected weights in the F₂ progeny if genotype AABB is crossed with aabb.

Introduction:

In the given scenario, it is supposed that plant weight is determined by a pair of alleles at each of two independently assorting loci (A and a, B and b) that are additive in their effects. The alleles represented by uppercase letters contribute 4 grams to plant weight, while the alleles represented by lowercase letters contribute 1 gram to plant weight.

(b)

Expert Solution

Explanation of Solution

Gametes formed from F₁ generation would be AB, Ab, aB, and ab as follows:

F1 generation AaBb ↓Gamates AB Ab aB ab

F₂ generation is produced when F₁ generation is inter-crossed and their expected plant weights would be as follows:

ABAbaBabABAABB(4+4+4+4= 16g)AABb(4+4+4+1= 13g)AaBB(4+1+4+4= 13g)AaBb(4+1+4+1= 10g)AbAABb(4+4+4+1= 13g)AAbb(4+4+1+1= 10g)AaBb(4+1+4+1= 10g)Aabb(4+1+1+1= 7g)aBAaBB(4+1+4+4= 13g)AaBb(4+1+4+1= 10g)aaBB(1+1+4+4= 10g)aaBb(1+1+4+1= 7g)abAaBb(4+1+4+1= 10g)Aabb(4+1+1+1= 7g)aaBb(1+1+4+1= 7g)aabb(1+1+1+1= 4g)

Highest plant weight in F₂ generation would be of AABB (16 grams) and lowest would be of aabb (4 grams).

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Answer 5

Chapter 24.1, Problem 17AQP

(a)

Summary Introduction

To determine:

Expected weights in the F₁ progeny if genotype AABB is crossed with aabb.

Introduction:

In the given scenario, it is supposed that plant weight is determined by a pair of alleles at each of two independently assorting loci (A and a, B and b) that are additive in their effects. The alleles represented by uppercase letters contribute 4 grams to plant weight, while the alleles represented by lowercase letters contribute 1 gram to plant weight.

(a)

Expert Solution

Explanation of Solution

The cross between AABB and aabb is as follows:

Parents ♂ ♀ AABB × aabb ↓ ↓ Gamates AB ab ↘ ↙ ↓ F1 generation AaBb

F₁ (filial 1) generation is AaBb. Its weight can be determined as weight contributed by A + weight contributed by a + weight contributed by B + weight contributed by b (4 + 1 + 4 + 1). So, the plant weight in F₁ generation would be 10 grams.

(b)

Summary Introduction

To determine:

Expected weights in the F₂ progeny if genotype AABB is crossed with aabb.

Introduction:

In the given scenario, it is supposed that plant weight is determined by a pair of alleles at each of two independently assorting loci (A and a, B and b) that are additive in their effects. The alleles represented by uppercase letters contribute 4 grams to plant weight, while the alleles represented by lowercase letters contribute 1 gram to plant weight.

(b)

Expert Solution

Explanation of Solution

Gametes formed from F₁ generation would be AB, Ab, aB, and ab as follows:

F1 generation AaBb ↓Gamates AB Ab aB ab

F₂ generation is produced when F₁ generation is inter-crossed and their expected plant weights would be as follows:

ABAbaBabABAABB(4+4+4+4= 16g)AABb(4+4+4+1= 13g)AaBB(4+1+4+4= 13g)AaBb(4+1+4+1= 10g)AbAABb(4+4+4+1= 13g)AAbb(4+4+1+1= 10g)AaBb(4+1+4+1= 10g)Aabb(4+1+1+1= 7g)aBAaBB(4+1+4+4= 13g)AaBb(4+1+4+1= 10g)aaBB(1+1+4+4= 10g)aaBb(1+1+4+1= 7g)abAaBb(4+1+4+1= 10g)Aabb(4+1+1+1= 7g)aaBb(1+1+4+1= 7g)aabb(1+1+1+1= 4g)

Highest plant weight in F₂ generation would be of AABB (16 grams) and lowest would be of aabb (4 grams).

Answer 6

Chapter 24.1, Problem 17AQP

(a)

Summary Introduction

To determine:

Expected weights in the F₁ progeny if genotype AABB is crossed with aabb.

Introduction:

In the given scenario, it is supposed that plant weight is determined by a pair of alleles at each of two independently assorting loci (A and a, B and b) that are additive in their effects. The alleles represented by uppercase letters contribute 4 grams to plant weight, while the alleles represented by lowercase letters contribute 1 gram to plant weight.

(a)

Expert Solution

Explanation of Solution

The cross between AABB and aabb is as follows:

Parents ♂ ♀ AABB × aabb ↓ ↓ Gamates AB ab ↘ ↙ ↓ F1 generation AaBb

F₁ (filial 1) generation is AaBb. Its weight can be determined as weight contributed by A + weight contributed by a + weight contributed by B + weight contributed by b (4 + 1 + 4 + 1). So, the plant weight in F₁ generation would be 10 grams.

Answer 7

Chapter 24.1, Problem 17AQP

(a)

Summary Introduction

To determine:

Expected weights in the F₁ progeny if genotype AABB is crossed with aabb.

Introduction:

In the given scenario, it is supposed that plant weight is determined by a pair of alleles at each of two independently assorting loci (A and a, B and b) that are additive in their effects. The alleles represented by uppercase letters contribute 4 grams to plant weight, while the alleles represented by lowercase letters contribute 1 gram to plant weight.

Answer 8

(a)

Expert Solution

Explanation of Solution

The cross between AABB and aabb is as follows:

Parents ♂ ♀ AABB × aabb ↓ ↓ Gamates AB ab ↘ ↙ ↓ F1 generation AaBb

F₁ (filial 1) generation is AaBb. Its weight can be determined as weight contributed by A + weight contributed by a + weight contributed by B + weight contributed by b (4 + 1 + 4 + 1). So, the plant weight in F₁ generation would be 10 grams.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

(b)

Summary Introduction

To determine:

Expected weights in the F₂ progeny if genotype AABB is crossed with aabb.

Introduction:

In the given scenario, it is supposed that plant weight is determined by a pair of alleles at each of two independently assorting loci (A and a, B and b) that are additive in their effects. The alleles represented by uppercase letters contribute 4 grams to plant weight, while the alleles represented by lowercase letters contribute 1 gram to plant weight.

(b)

Expert Solution

Explanation of Solution

Gametes formed from F₁ generation would be AB, Ab, aB, and ab as follows:

F1 generation AaBb ↓Gamates AB Ab aB ab

F₂ generation is produced when F₁ generation is inter-crossed and their expected plant weights would be as follows:

ABAbaBabABAABB(4+4+4+4= 16g)AABb(4+4+4+1= 13g)AaBB(4+1+4+4= 13g)AaBb(4+1+4+1= 10g)AbAABb(4+4+4+1= 13g)AAbb(4+4+1+1= 10g)AaBb(4+1+4+1= 10g)Aabb(4+1+1+1= 7g)aBAaBB(4+1+4+4= 13g)AaBb(4+1+4+1= 10g)aaBB(1+1+4+4= 10g)aaBb(1+1+4+1= 7g)abAaBb(4+1+4+1= 10g)Aabb(4+1+1+1= 7g)aaBb(1+1+4+1= 7g)aabb(1+1+1+1= 4g)

Highest plant weight in F₂ generation would be of AABB (16 grams) and lowest would be of aabb (4 grams).

Answer 13

(b)

Summary Introduction

To determine:

Expected weights in the F₂ progeny if genotype AABB is crossed with aabb.

Introduction:

In the given scenario, it is supposed that plant weight is determined by a pair of alleles at each of two independently assorting loci (A and a, B and b) that are additive in their effects. The alleles represented by uppercase letters contribute 4 grams to plant weight, while the alleles represented by lowercase letters contribute 1 gram to plant weight.

Answer 14

(b)

Expert Solution

Explanation of Solution

Gametes formed from F₁ generation would be AB, Ab, aB, and ab as follows:

F1 generation AaBb ↓Gamates AB Ab aB ab

F₂ generation is produced when F₁ generation is inter-crossed and their expected plant weights would be as follows:

ABAbaBabABAABB(4+4+4+4= 16g)AABb(4+4+4+1= 13g)AaBB(4+1+4+4= 13g)AaBb(4+1+4+1= 10g)AbAABb(4+4+4+1= 13g)AAbb(4+4+1+1= 10g)AaBb(4+1+4+1= 10g)Aabb(4+1+1+1= 7g)aBAaBB(4+1+4+4= 13g)AaBb(4+1+4+1= 10g)aaBB(1+1+4+4= 10g)aaBb(1+1+4+1= 7g)abAaBb(4+1+4+1= 10g)Aabb(4+1+1+1= 7g)aaBb(1+1+4+1= 7g)aabb(1+1+1+1= 4g)