University Physics (14th Edition)
University Physics (14th Edition)
14th Edition
ISBN: 9780133969290
Author: Hugh D. Young, Roger A. Freedman
Publisher: PEARSON
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Chapter 24, Problem Q24.5DQ

In the parallel-plate capacitor of Fig. 24.2, suppose the plates are pulled apart so that the separation d is much larger than the size of the plates, (a) Is it still accurate to say that the electric field between the plates is uniform? Why or why not? (b) In the situation shown in Fig. 24.2, the potential difference between the plates is Vab = Qd/ϵ0A. If the plates are pulled apart as described above, is Vab more or less than this formula would indicate? Explain your reasoning, (c) With the plates pulled apart as described above, is the capacitance more than, less than, or the same as that given by Eq. (24.2)? Explain your reasoning.

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An air-gap parallel-plate capacitor that has a plate area of 1.20 m2 and a separation of 1.40 mm is charged to 90 V. (a) What is the electric field between the plates? kV/m (b) What is the electric energy density between the plates? |mJ/m3 (c) Find the total energy by multiplying your answer from Part (b) by the volume between the plates. (d) Determine the capacitance of this arrangement. nF (e) Calculate the total energy from U = V2CV2, and compare your answer with your result from Part (c).
I only need part D
and direction of the x 10 10. A uniform electric field is established by connecting the plates of a parallel plate capacitor to a 12V battery. If the plates are separated by 0.75 cm, what is the magnitude of the electric field in the capacitor?

Chapter 24 Solutions

University Physics (14th Edition)

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