EBK CHEMISTRY:CENTRAL SCIENCE
14th Edition
ISBN: 9780134554570
Author: Brown
Publisher: PEARSON
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Chapter 24, Problem 94AE
Interpretation Introduction
Interpretation: The binding of a DNA-strand to a complementary RNA strand is to be explained.
Concept introduction: DNA is a
To explain: Whether a DNA-strand can bind to a complementary RNA strand.
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The reaction sequence shown in Scheme 5 demonstrates the synthesis of a
substituted benzene derivative Q.
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NH2
NaNO2, HCI
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HNO3, H2SO4
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0°C
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CHINO₂
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O
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Scheme 5
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(i)
Draw the structure of intermediate O.
[2 marks]
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(ii) Draw the mechanism for the transformation of aniline N to intermediate O.
Spoilage
(b)
[6 marks]
(iii) Identify the reagent X used to convert compound O to the iodinated compound
[tom E
P.
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(iv) Identify the possible structures of compound Q.
[2 marks]
[2 marks]
[shom 2]
(v)
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Draw the mechanism for the transformation of intermediate P to compound Q.
[5 marks]
vi
(vi) Account for the regiochemical outcome observed in the reaction forming
compound Q.
[3 marks]
PROBLEM 4 Solved
Show how 1-butanol can be converted into the following compounds:
a.
PROBLEM 5+
b.
d.
-C=
N
Which alkene is the major product of this dehydration?
OH
H2SO4
heat
Chapter 24 Solutions
EBK CHEMISTRY:CENTRAL SCIENCE
Ch. 24.2 - Prob. 24.1.1PECh. 24.2 - Prob. 24.1.2PECh. 24.2 - How many hydrogen atoms are in 2, 2-...Ch. 24.2 - Prob. 24.2.2PECh. 24.3 - Prob. 24.3.1PECh. 24.3 - Prob. 24.3.2PECh. 24.3 - Prob. 24.4.1PECh. 24.3 - Prob. 24.4.2PECh. 24.3 - Prob. 24.5.1PECh. 24.3 - Prob. 24.5.2PE
Ch. 24.4 - Prob. 24.6.1PECh. 24.4 - Prob. 24.6.2PECh. 24.7 - Prob. 24.7.1PECh. 24.7 - Practice Exercise 2 Name the dipeptide and give...Ch. 24.7 - How many chiral carbon atoms are there in the...Ch. 24.7 - Prob. 24.8.2PECh. 24 - Prob. 1DECh. 24 - Prob. 1ECh. 24 - Prob. 2ECh. 24 - Prob. 3ECh. 24 - Prob. 4ECh. 24 - Prob. 5ECh. 24 - Prob. 6ECh. 24 - Prob. 7ECh. 24 - Prob. 8ECh. 24 - Prob. 9ECh. 24 - Prob. 10ECh. 24 - Prob. 11ECh. 24 - Prob. 12ECh. 24 - Prob. 13ECh. 24 - Prob. 14ECh. 24 - Prob. 15ECh. 24 - Prob. 16ECh. 24 - Prob. 17ECh. 24 - Prob. 18ECh. 24 - Prob. 19ECh. 24 - Prob. 20ECh. 24 - Prob. 21ECh. 24 - Prob. 22ECh. 24 - Prob. 23ECh. 24 - Prob. 24ECh. 24 - Prob. 25ECh. 24 - Prob. 26ECh. 24 - Prob. 27ECh. 24 - Prob. 28ECh. 24 - Prob. 29ECh. 24 - Prob. 30ECh. 24 - Prob. 31ECh. 24 - Prob. 32ECh. 24 - Prob. 33ECh. 24 - Prob. 34ECh. 24 - Prob. 35ECh. 24 - Prob. 36ECh. 24 - Prob. 37ECh. 24 - Prob. 38ECh. 24 - Prob. 39ECh. 24 - Describe the intermediate that is thought to form...Ch. 24 - Prob. 41ECh. 24 - Prob. 42ECh. 24 - Prob. 43ECh. 24 - Prob. 44ECh. 24 - Prob. 45ECh. 24 - Prob. 46ECh. 24 - Prob. 47ECh. 24 - Prob. 48ECh. 24 - Prob. 49ECh. 24 - Prob. 50ECh. 24 - Prob. 51ECh. 24 - Prob. 52ECh. 24 - Prob. 53ECh. 24 - Prob. 54ECh. 24 - Prob. 55ECh. 24 - Prob. 56ECh. 24 - Prob. 57ECh. 24 - Prob. 58ECh. 24 - Prob. 59ECh. 24 - Prob. 60ECh. 24 - Prob. 61ECh. 24 - Prob. 62ECh. 24 - Prob. 63ECh. 24 - Prob. 64ECh. 24 - Prob. 65ECh. 24 - Prob. 66ECh. 24 - Prob. 67ECh. 24 - Prob. 68ECh. 24 - Prob. 69ECh. 24 - Prob. 70ECh. 24 - Prob. 71ECh. 24 - Prob. 72ECh. 24 - Prob. 73ECh. 24 - Prob. 74ECh. 24 - Prob. 75ECh. 24 - Prob. 76ECh. 24 - Prob. 77ECh. 24 - Prob. 78ECh. 24 - Prob. 79ECh. 24 - Prob. 80ECh. 24 - Prob. 81AECh. 24 - Prob. 82AECh. 24 - Prob. 83AECh. 24 - Prob. 84AECh. 24 - Prob. 85AECh. 24 - Prob. 86AECh. 24 - Prob. 87AECh. 24 - Prob. 88AECh. 24 - Prob. 89AECh. 24 - Prob. 90AECh. 24 - Prob. 91AECh. 24 - Prob. 92AECh. 24 - Prob. 93AECh. 24 - Prob. 94AECh. 24 - Prob. 95IECh. 24 - Prob. 96IECh. 24 - Prob. 97IECh. 24 - Prob. 98IECh. 24 - Prob. 99IECh. 24 - A typical amino acid with one amino group and one...Ch. 24 - Prob. 101IECh. 24 - Prob. 102IE
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Nucleic acids - DNA and RNA structure; Author: MEDSimplified;https://www.youtube.com/watch?v=0lZRAShqft0;License: Standard YouTube License, CC-BY