COLLEGE PHYSICS LL W/ 6 MONTH ACCESS
COLLEGE PHYSICS LL W/ 6 MONTH ACCESS
2nd Edition
ISBN: 9781319414597
Author: Freedman
Publisher: MAC HIGHER
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Chapter 24, Problem 92QAP
To determine

(a)

The final image of the flower produced by the lens-mirror.

Expert Solution
Check Mark

Answer to Problem 92QAP

The final image is 10.5cm tall and inverted.

Explanation of Solution

Given:

A thin conserving lens ( fA=25cm ) is placed 1.000m from a plane mirror on the same principle axis

A flower ( ho=8.50cm ) is placed in front of the mirror; dO,A=0.450m=45cm

Formula used:

  1fA=1dO,A+1d1,A

Calculation:

  1fA=1dO,A+1d1,A

  1d1,A=1fA1dO,A1d1,A=dO,AfAfAdO,Ad1,A=fAdO,AdO,AfA

  d1,A=(25)(45)(45)(25)d1,A=112520d1,A=56.25cm

Image formed by the mirror:

The image formed by lens is located 56.25cm behind the lens,

  dO,B=10056.25=43.75cm

  1dO,B+1d1,B=1fB1d1,B=1fB1dO,B1d1,B=11dO,Bd1,B=dO,B=43.75cm

The image formed by the mirror is located 43.75cm behind the mirror.

Since d1,B<0, the image is virtual.

Image height:

  mtotal=mAmBmtotal=( d 1,A d O,A)( d 1,B d O,b)mtotal=(56.2545)(43.7543.75)mtotal=1.25×(1)mtotal=1.25h1=mtotal×hoh1=(1.25)(8.40)h1=10.5cm

Conclusion:

The final image is 10.5cm tall and inverted.

To determine

(b)

The final image of the flower produced by the lens-mirror when converging lens is replaced by a diverging lens.

Expert Solution
Check Mark

Answer to Problem 92QAP

The final image is 3cm tall and upright.

Explanation of Solution

Given:

A thin conserving lens ( fA=25cm ) is placed 1.000m from a plane mirror on the same principle axis

A flower ( ho=8.50cm ) is placed in front of the mirror; dO,A=0.450m=45cm

Formula used:

  1fA=1dO,A+1d1,A

Calculation:

Image formed by the lens:

  1fA=1dO,A+1d1,A

  1d1,A=1fA1dO,A1d1,A=dO,AfAfAdO,Ad1,A=fAdO,AdO,AfA

  d1,A=(25)(45)(45)(25)d1,A=112570d1,A=16.07cm

Image formed by the mirror:

The image formed by lens is located 16.07cm behind the lens,

  dO,B=100+16.07=116.07cm

  1dO,B+1d1,B=1fB1d1,B=1fB1dO,B1d1,B=11dO,Bd1,B=dO,B=116.07cm

The image formed by the mirror is located 116.07cm behind the mirror.

Since d1,B<0, the image is virtual.

Image height:

  mtotal=mAmBmtotal=( d 1,A d O,A)( d 1,B d O,b)mtotal=(16.0745)(116.07116.07)mtotal=0.357×(1)mtotal=0.357h1=mtotal×hoh1=(0.357)(8.40)h1=3cm

Conclusion:

The final image is 3cm tall and upright.

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Chapter 24 Solutions

COLLEGE PHYSICS LL W/ 6 MONTH ACCESS

Ch. 24 - Prob. 11QAPCh. 24 - Prob. 12QAPCh. 24 - Prob. 13QAPCh. 24 - Prob. 14QAPCh. 24 - Prob. 15QAPCh. 24 - Prob. 16QAPCh. 24 - Prob. 17QAPCh. 24 - Prob. 18QAPCh. 24 - Prob. 19QAPCh. 24 - Prob. 20QAPCh. 24 - Prob. 21QAPCh. 24 - Prob. 22QAPCh. 24 - Prob. 23QAPCh. 24 - Prob. 24QAPCh. 24 - Prob. 25QAPCh. 24 - Prob. 26QAPCh. 24 - Prob. 27QAPCh. 24 - Prob. 28QAPCh. 24 - Prob. 29QAPCh. 24 - Prob. 30QAPCh. 24 - Prob. 31QAPCh. 24 - Prob. 32QAPCh. 24 - Prob. 33QAPCh. 24 - Prob. 34QAPCh. 24 - Prob. 35QAPCh. 24 - Prob. 36QAPCh. 24 - Prob. 37QAPCh. 24 - Prob. 38QAPCh. 24 - Prob. 39QAPCh. 24 - Prob. 40QAPCh. 24 - Prob. 41QAPCh. 24 - Prob. 42QAPCh. 24 - Prob. 43QAPCh. 24 - Prob. 44QAPCh. 24 - Prob. 45QAPCh. 24 - Prob. 46QAPCh. 24 - Prob. 47QAPCh. 24 - Prob. 48QAPCh. 24 - Prob. 49QAPCh. 24 - Prob. 50QAPCh. 24 - Prob. 51QAPCh. 24 - Prob. 52QAPCh. 24 - Prob. 53QAPCh. 24 - Prob. 54QAPCh. 24 - Prob. 55QAPCh. 24 - Prob. 56QAPCh. 24 - Prob. 57QAPCh. 24 - Prob. 58QAPCh. 24 - Prob. 59QAPCh. 24 - Prob. 60QAPCh. 24 - Prob. 61QAPCh. 24 - Prob. 62QAPCh. 24 - Prob. 63QAPCh. 24 - Prob. 64QAPCh. 24 - Prob. 65QAPCh. 24 - Prob. 66QAPCh. 24 - Prob. 67QAPCh. 24 - Prob. 68QAPCh. 24 - Prob. 69QAPCh. 24 - Prob. 70QAPCh. 24 - Prob. 71QAPCh. 24 - Prob. 72QAPCh. 24 - Prob. 73QAPCh. 24 - Prob. 74QAPCh. 24 - Prob. 75QAPCh. 24 - Prob. 76QAPCh. 24 - Prob. 77QAPCh. 24 - Prob. 78QAPCh. 24 - Prob. 79QAPCh. 24 - Prob. 80QAPCh. 24 - Prob. 81QAPCh. 24 - Prob. 82QAPCh. 24 - Prob. 83QAPCh. 24 - Prob. 84QAPCh. 24 - Prob. 85QAPCh. 24 - Prob. 86QAPCh. 24 - Prob. 87QAPCh. 24 - Prob. 88QAPCh. 24 - Prob. 89QAPCh. 24 - Prob. 90QAPCh. 24 - Prob. 91QAPCh. 24 - Prob. 92QAPCh. 24 - Prob. 93QAPCh. 24 - Prob. 94QAPCh. 24 - Prob. 95QAPCh. 24 - Prob. 96QAPCh. 24 - Prob. 97QAPCh. 24 - Prob. 98QAPCh. 24 - Prob. 99QAPCh. 24 - Prob. 100QAPCh. 24 - Prob. 101QAPCh. 24 - Prob. 102QAPCh. 24 - Prob. 103QAP
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