Chemistry, The Central Science, Volume 1, Custom For Houston Community College
19th Edition
ISBN: 9781323850206
Author: Lemay, Bursten Brown, Woodward Murphy, Lufaso Stoltzfus
Publisher: Pearson Higher Ed
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Chapter 24, Problem 71E
(a)
Interpretation Introduction
To determine: If the given molecule is a sugar.
(b)
Interpretation Introduction
To determine: The number of chiral carbons present in the given molecule.
(c)
Interpretation Introduction
To determine: The structure of a six-member-ring form of the given molecule.
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Check the box under each a amino acid.
If there are no a amino acids at all, check the "none of them" box under the table.
Note for advanced students: don't assume every amino acid shown must be found in nature.
COO
H3N-C-H
CH2
HO
CH3
NH3 O
CH3-CH
CH2
OH
Onone of them
Explanation
Check
+
H3N
O
0.
O
OH
+
NH3
CH2
CH3-CH
H2N C-COOH
H
O
HIC
+
C=O
H3N-C-O
CH3- - CH
CH2
OH
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Write the systematic name of each organic molecule:
structure
HO-C-CH2-CH3
O
-OH
CH3-CH2-CH2-CH2-CH2-C-OH
CH3
CH3-CH-CH2-C-OH
Explanation
Check
S
name
theres 2 products
Chapter 24 Solutions
Chemistry, The Central Science, Volume 1, Custom For Houston Community College
Ch. 24.2 - Prob. 24.1.1PECh. 24.2 - Prob. 24.1.2PECh. 24.2 - How many hydrogen atoms are in 2, 2-...Ch. 24.2 - Prob. 24.2.2PECh. 24.3 - Prob. 24.3.1PECh. 24.3 - Prob. 24.3.2PECh. 24.3 - Prob. 24.4.1PECh. 24.3 - Prob. 24.4.2PECh. 24.3 - Prob. 24.5.1PECh. 24.3 - Prob. 24.5.2PE
Ch. 24.4 - Prob. 24.6.1PECh. 24.4 - Prob. 24.6.2PECh. 24.7 - Prob. 24.7.1PECh. 24.7 - Practice Exercise 2 Name the dipeptide and give...Ch. 24.7 - How many chiral carbon atoms are there in the...Ch. 24.7 - Prob. 24.8.2PECh. 24 - Prob. 1DECh. 24 - Prob. 1ECh. 24 - Prob. 2ECh. 24 - Prob. 3ECh. 24 - Prob. 4ECh. 24 - Prob. 5ECh. 24 - Prob. 6ECh. 24 - Prob. 7ECh. 24 - Prob. 8ECh. 24 - Prob. 9ECh. 24 - Prob. 10ECh. 24 - Prob. 11ECh. 24 - Prob. 12ECh. 24 - Prob. 13ECh. 24 - Prob. 14ECh. 24 - Prob. 15ECh. 24 - Prob. 16ECh. 24 - Prob. 17ECh. 24 - Prob. 18ECh. 24 - Prob. 19ECh. 24 - Prob. 20ECh. 24 - Prob. 21ECh. 24 - Prob. 22ECh. 24 - Prob. 23ECh. 24 - Prob. 24ECh. 24 - Prob. 25ECh. 24 - Prob. 26ECh. 24 - Prob. 27ECh. 24 - Prob. 28ECh. 24 - Prob. 29ECh. 24 - Prob. 30ECh. 24 - Prob. 31ECh. 24 - Prob. 32ECh. 24 - Prob. 33ECh. 24 - Prob. 34ECh. 24 - Prob. 35ECh. 24 - Prob. 36ECh. 24 - Prob. 37ECh. 24 - Prob. 38ECh. 24 - Prob. 39ECh. 24 - Describe the intermediate that is thought to form...Ch. 24 - Prob. 41ECh. 24 - Prob. 42ECh. 24 - Prob. 43ECh. 24 - Prob. 44ECh. 24 - Prob. 45ECh. 24 - Prob. 46ECh. 24 - Prob. 47ECh. 24 - Prob. 48ECh. 24 - Prob. 49ECh. 24 - Prob. 50ECh. 24 - Prob. 51ECh. 24 - Prob. 52ECh. 24 - Prob. 53ECh. 24 - Prob. 54ECh. 24 - Prob. 55ECh. 24 - Prob. 56ECh. 24 - Prob. 57ECh. 24 - Prob. 58ECh. 24 - Prob. 59ECh. 24 - Prob. 60ECh. 24 - Prob. 61ECh. 24 - Prob. 62ECh. 24 - Prob. 63ECh. 24 - Prob. 64ECh. 24 - Prob. 65ECh. 24 - Prob. 66ECh. 24 - Prob. 67ECh. 24 - Prob. 68ECh. 24 - Prob. 69ECh. 24 - Prob. 70ECh. 24 - Prob. 71ECh. 24 - Prob. 72ECh. 24 - Prob. 73ECh. 24 - Prob. 74ECh. 24 - Prob. 75ECh. 24 - Prob. 76ECh. 24 - Prob. 77ECh. 24 - Prob. 78ECh. 24 - Prob. 79ECh. 24 - Prob. 80ECh. 24 - Prob. 81AECh. 24 - Prob. 82AECh. 24 - Prob. 83AECh. 24 - Prob. 84AECh. 24 - Prob. 85AECh. 24 - Prob. 86AECh. 24 - Prob. 87AECh. 24 - Prob. 88AECh. 24 - Prob. 89AECh. 24 - Prob. 90AECh. 24 - Prob. 91AECh. 24 - Prob. 92AECh. 24 - Prob. 93AECh. 24 - Prob. 94AECh. 24 - Prob. 95IECh. 24 - Prob. 96IECh. 24 - Prob. 97IECh. 24 - Prob. 98IECh. 24 - Prob. 99IECh. 24 - A typical amino acid with one amino group and one...Ch. 24 - Prob. 101IECh. 24 - Prob. 102IE
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