CHEMISTRY >CUSTOM<
CHEMISTRY >CUSTOM<
14th Edition
ISBN: 9781259137815
Author: Julia Burdge
Publisher: McGraw-Hill Education
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Chapter 24, Problem 64QP
Interpretation Introduction

Interpretation:

The amount of sulfur required to produce 48 million tones

of sulphuric acid is to be calculated.

Concept introduction:

The moles of a substance are calculated by the ratio of the mass of the substance to the molar mass of the substance.

Number of moles = Given massMolar mass

The mass of compound can be calculated as: m=n×M

Here, n is the number of moles, m is the mass, and M is the molar mass.

The relationship between tonn and lb can be expressed as:

1tonn=2000lb

To convert tonn to lb, conversion factor is 2000 lb1tonn.

The relationship between lb and grams can be expressed as:

1 lb=453.6g.

To convert lb to grams, conversion factor is 453.6 g1 lb.

Expert Solution & Answer
Check Mark

Answer to Problem 64QP

Solution: 1.4 × 1013 g S

Explanation of Solution

Given information: Volume of D2=2L.

Pressure, P=0.90 atm.

Temperature, T=25oC=298 K.

Abundance of D2=0.015%.

Recovery D2=80%.

Convert tonn

to lb,

Conversion factor is: 2000 lb1tonn

The conversion is as:

48×106tonnsH2SO4×2000 lb1tonn= 96 ×109lb

Convert lb to grams,

Conversion factor is: 453.6 g1 lb

The conversion is as:

96 ×109lb × 453.6 g1 lb=43545.6×109g

The molar mass of sulfuric acid 98 g/mol.

The number of moles of sulfuric acid is calculated as:

Number of moles = Given massMolar mass

n=(43545.6×109g98g/mol)=444.34×109 mol

1 mol  of H2SO4 contains 1 mol  of S.

The number of moles of S in 444.34×109 mol

of H2SO4 is as:

(444.34×109 mol H2SO4 ×1 mol S1 mol H2SO4)=444.34×109 mol S

Now, convert moles to grams,

Mass of 1 mol of sulfur =32 g/mol

The mass of compound can be calculated as: m=n×M

Here, n is the number of moles, m is the mass, and M is the molar mass.

Mass of 444.34×109 mol S =(444.34×109 mol S×32 g/mol )=1.4 × 1013 g S

Conclusion

The amount of sulfur required to produce 48 million tones of sulfuric acid is 1.4×1013g S.

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Chapter 24 Solutions

CHEMISTRY >CUSTOM<

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