COLLEGE PHYSICS,VOLUME 1
COLLEGE PHYSICS,VOLUME 1
2nd Edition
ISBN: 9781319115104
Author: Freedman
Publisher: MAC HIGHER
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 24, Problem 48QAP
To determine

(a)

The image distance, height, type and orientation of the image

Expert Solution
Check Mark

Answer to Problem 48QAP

Image distance =10.0cm

Image height =20.0cm

Type of image = Virtual
Orientation of the image = Upright

Explanation of Solution

Given info:

Distance to the object from the mirror = 5.0cm

Radius of the mirror = 20.0cm

Height of the object = 10.0cm

Formula used:

  1f=1p+1q

  f= Focal length
  p= Object distance
  q= Image distance
  f=R2

  R= Radius
  M=qp

  M= Magnification
  M=hiho

  hi= Image height
  ho= Object height

Calculation:

  f=R2=20.0cm2=10.0cm

  1q=1f1p=110.0cm15.0cmq=10.0cm

  hiho=qphi10.0cm=10.0cm5.0cmhi=20.0cm

Conclusion:

Image distance =10.0cm

Image height =20.0cm

Type of image = Virtual
Orientation of the image = Upright

To determine

(b)

The image distance, height, type and orientation of the image

Expert Solution
Check Mark

Answer to Problem 48QAP

Image distance =20.0cm

Image height =10.0cm

Type of image = Real
Orientation of the image = Inverted

Explanation of Solution

Given info:

Distance to the object from the mirror = 20.0cm

Radius of the mirror = 20.0cm

Height of the object = 10.0cm

Formula used:

  1f=1p+1q

  f= Focal length
  p= Object distance
  q= Image distance
  f=R2

  R= Radius
  M=qp

  M= Magnification
  M=hiho

  hi= Image height
  ho= Object height

Calculation:

  f=R2=20.0cm2=10.0cm

  1q=1f1p=110.0cm120.0cmq=20.0cm

  hiho=qphi10.0cm=20.0cm20.0cmhi=10.0cm

Conclusion:

Image distance =20.0cm

Image height =10.0cm

Type of image = Real
Orientation of the image = Inverted

To determine

(c)

The image distance, height, type and orientation of the image

Expert Solution
Check Mark

Answer to Problem 48QAP

Image distance =12.5cm

Image height =0.25cm

Type of image = Real
Orientation of the image = Inverted

Explanation of Solution

Given info:

Distance to the object from the mirror = 50.0cm

Radius of the mirror = 20.0cm

Height of the object = 10.0cm

Formula used:

  1f=1p+1q

  f= Focal length
  p= Object distance
  q= Image distance
  f=R2

  R= Radius
  M=qp

  M= Magnification
  M=hiho

  hi= Image height
  ho= Object height

Calculation:

  f=R2=20.0cm2=10.0cm

  1q=1f1p=110.0cm150.0cmq=12.5cm

  hiho=qphi10.0cm=12.5cm50.0cmhi=0.25cm

Conclusion:

Image distance =12.5cm

Image height =0.25cm

Type of image = Real
Orientation of the image = Inverted

To determine

(d)

The image distance, height, type and orientation of the image

Expert Solution
Check Mark

Answer to Problem 48QAP

Image distance =11.1cm

Image height =1.11cm

Type of image = Real
Orientation of the image = Inverted

Explanation of Solution

Given info:

Distance to the object from the mirror = 100.0cm

Radius of the mirror = 20.0cm

Height of the object = 10.0cm

Formula used:

  1f=1p+1q

  f= Focal length
  p= Object distance
  q= Image distance
  f=R2

  R= Radius
  M=qp

  M= Magnification
  M=hiho

  hi= Image height
  ho= Object height

Calculation:

  f=R2=20.0cm2=10.0cm

  1q=1f1p=110.0cm1100.0cmq=11.1cm

  hiho=qphi10.0cm=11.1cm100.0cmhi=1.11cm

Conclusion:

Image distance =11.1cm

Image height =1.11cm

Type of image = Real
Orientation of the image = Inverted

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
I. Pushing on a File Cabinet Bob has been asked to push a heavy file cabinet down the hall to another office. It's not on rollers, so there is a lot of friction. At time t = 0 seconds, he starts pushing it from rest with increasing force until it starts to move at t = 2 seconds. He pushes the file cabinet down the hall with varying amounts of force. The velocity versus time graph of the cabinet is shown below. A. On the graphs provided below, 1. draw the net force vs. time that would produce this velocity graph; 2. draw the friction force vs. time for this motion; 3. draw the applied force (Fon Cabinet by Bob) VS. time for this motion (the first two seconds of this graph have been drawn for you). Velocity (m/s) Applied Force (N) Friction Force (N) Net Force (N) A -m B -U time (s) D time (s) time (s) time (s)
answer it
Please draw a sketch and a FBD

Chapter 24 Solutions

COLLEGE PHYSICS,VOLUME 1

Ch. 24 - Prob. 11QAPCh. 24 - Prob. 12QAPCh. 24 - Prob. 13QAPCh. 24 - Prob. 14QAPCh. 24 - Prob. 15QAPCh. 24 - Prob. 16QAPCh. 24 - Prob. 17QAPCh. 24 - Prob. 18QAPCh. 24 - Prob. 19QAPCh. 24 - Prob. 20QAPCh. 24 - Prob. 21QAPCh. 24 - Prob. 22QAPCh. 24 - Prob. 23QAPCh. 24 - Prob. 24QAPCh. 24 - Prob. 25QAPCh. 24 - Prob. 26QAPCh. 24 - Prob. 27QAPCh. 24 - Prob. 28QAPCh. 24 - Prob. 29QAPCh. 24 - Prob. 30QAPCh. 24 - Prob. 31QAPCh. 24 - Prob. 32QAPCh. 24 - Prob. 33QAPCh. 24 - Prob. 34QAPCh. 24 - Prob. 35QAPCh. 24 - Prob. 36QAPCh. 24 - Prob. 37QAPCh. 24 - Prob. 38QAPCh. 24 - Prob. 39QAPCh. 24 - Prob. 40QAPCh. 24 - Prob. 41QAPCh. 24 - Prob. 42QAPCh. 24 - Prob. 43QAPCh. 24 - Prob. 44QAPCh. 24 - Prob. 45QAPCh. 24 - Prob. 46QAPCh. 24 - Prob. 47QAPCh. 24 - Prob. 48QAPCh. 24 - Prob. 49QAPCh. 24 - Prob. 50QAPCh. 24 - Prob. 51QAPCh. 24 - Prob. 52QAPCh. 24 - Prob. 53QAPCh. 24 - Prob. 54QAPCh. 24 - Prob. 55QAPCh. 24 - Prob. 56QAPCh. 24 - Prob. 57QAPCh. 24 - Prob. 58QAPCh. 24 - Prob. 59QAPCh. 24 - Prob. 60QAPCh. 24 - Prob. 61QAPCh. 24 - Prob. 62QAPCh. 24 - Prob. 63QAPCh. 24 - Prob. 64QAPCh. 24 - Prob. 65QAPCh. 24 - Prob. 66QAPCh. 24 - Prob. 67QAPCh. 24 - Prob. 68QAPCh. 24 - Prob. 69QAPCh. 24 - Prob. 70QAPCh. 24 - Prob. 71QAPCh. 24 - Prob. 72QAPCh. 24 - Prob. 73QAPCh. 24 - Prob. 74QAPCh. 24 - Prob. 75QAPCh. 24 - Prob. 76QAPCh. 24 - Prob. 77QAPCh. 24 - Prob. 78QAPCh. 24 - Prob. 79QAPCh. 24 - Prob. 80QAPCh. 24 - Prob. 81QAPCh. 24 - Prob. 82QAPCh. 24 - Prob. 83QAPCh. 24 - Prob. 84QAPCh. 24 - Prob. 85QAPCh. 24 - Prob. 86QAPCh. 24 - Prob. 87QAPCh. 24 - Prob. 88QAPCh. 24 - Prob. 89QAPCh. 24 - Prob. 90QAPCh. 24 - Prob. 91QAPCh. 24 - Prob. 92QAPCh. 24 - Prob. 93QAPCh. 24 - Prob. 94QAPCh. 24 - Prob. 95QAPCh. 24 - Prob. 96QAPCh. 24 - Prob. 97QAPCh. 24 - Prob. 98QAPCh. 24 - Prob. 99QAPCh. 24 - Prob. 100QAPCh. 24 - Prob. 101QAPCh. 24 - Prob. 102QAPCh. 24 - Prob. 103QAP
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax
Text book image
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Text book image
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
AP Physics 2 - Geometric Optics: Mirrors and Lenses - Intro Lesson; Author: N. German;https://www.youtube.com/watch?v=unT297HdZC0;License: Standard YouTube License, CC-BY