COLLEGE PHYSICS,VOLUME 1
COLLEGE PHYSICS,VOLUME 1
2nd Edition
ISBN: 9781319115104
Author: Freedman
Publisher: MAC HIGHER
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Chapter 24, Problem 48QAP
To determine

(a)

The image distance, height, type and orientation of the image

Expert Solution
Check Mark

Answer to Problem 48QAP

Image distance =10.0cm

Image height =20.0cm

Type of image = Virtual
Orientation of the image = Upright

Explanation of Solution

Given info:

Distance to the object from the mirror = 5.0cm

Radius of the mirror = 20.0cm

Height of the object = 10.0cm

Formula used:

  1f=1p+1q

  f= Focal length
  p= Object distance
  q= Image distance
  f=R2

  R= Radius
  M=qp

  M= Magnification
  M=hiho

  hi= Image height
  ho= Object height

Calculation:

  f=R2=20.0cm2=10.0cm

  1q=1f1p=110.0cm15.0cmq=10.0cm

  hiho=qphi10.0cm=10.0cm5.0cmhi=20.0cm

Conclusion:

Image distance =10.0cm

Image height =20.0cm

Type of image = Virtual
Orientation of the image = Upright

To determine

(b)

The image distance, height, type and orientation of the image

Expert Solution
Check Mark

Answer to Problem 48QAP

Image distance =20.0cm

Image height =10.0cm

Type of image = Real
Orientation of the image = Inverted

Explanation of Solution

Given info:

Distance to the object from the mirror = 20.0cm

Radius of the mirror = 20.0cm

Height of the object = 10.0cm

Formula used:

  1f=1p+1q

  f= Focal length
  p= Object distance
  q= Image distance
  f=R2

  R= Radius
  M=qp

  M= Magnification
  M=hiho

  hi= Image height
  ho= Object height

Calculation:

  f=R2=20.0cm2=10.0cm

  1q=1f1p=110.0cm120.0cmq=20.0cm

  hiho=qphi10.0cm=20.0cm20.0cmhi=10.0cm

Conclusion:

Image distance =20.0cm

Image height =10.0cm

Type of image = Real
Orientation of the image = Inverted

To determine

(c)

The image distance, height, type and orientation of the image

Expert Solution
Check Mark

Answer to Problem 48QAP

Image distance =12.5cm

Image height =0.25cm

Type of image = Real
Orientation of the image = Inverted

Explanation of Solution

Given info:

Distance to the object from the mirror = 50.0cm

Radius of the mirror = 20.0cm

Height of the object = 10.0cm

Formula used:

  1f=1p+1q

  f= Focal length
  p= Object distance
  q= Image distance
  f=R2

  R= Radius
  M=qp

  M= Magnification
  M=hiho

  hi= Image height
  ho= Object height

Calculation:

  f=R2=20.0cm2=10.0cm

  1q=1f1p=110.0cm150.0cmq=12.5cm

  hiho=qphi10.0cm=12.5cm50.0cmhi=0.25cm

Conclusion:

Image distance =12.5cm

Image height =0.25cm

Type of image = Real
Orientation of the image = Inverted

To determine

(d)

The image distance, height, type and orientation of the image

Expert Solution
Check Mark

Answer to Problem 48QAP

Image distance =11.1cm

Image height =1.11cm

Type of image = Real
Orientation of the image = Inverted

Explanation of Solution

Given info:

Distance to the object from the mirror = 100.0cm

Radius of the mirror = 20.0cm

Height of the object = 10.0cm

Formula used:

  1f=1p+1q

  f= Focal length
  p= Object distance
  q= Image distance
  f=R2

  R= Radius
  M=qp

  M= Magnification
  M=hiho

  hi= Image height
  ho= Object height

Calculation:

  f=R2=20.0cm2=10.0cm

  1q=1f1p=110.0cm1100.0cmq=11.1cm

  hiho=qphi10.0cm=11.1cm100.0cmhi=1.11cm

Conclusion:

Image distance =11.1cm

Image height =1.11cm

Type of image = Real
Orientation of the image = Inverted

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Chapter 24 Solutions

COLLEGE PHYSICS,VOLUME 1

Ch. 24 - Prob. 11QAPCh. 24 - Prob. 12QAPCh. 24 - Prob. 13QAPCh. 24 - Prob. 14QAPCh. 24 - Prob. 15QAPCh. 24 - Prob. 16QAPCh. 24 - Prob. 17QAPCh. 24 - Prob. 18QAPCh. 24 - Prob. 19QAPCh. 24 - Prob. 20QAPCh. 24 - Prob. 21QAPCh. 24 - Prob. 22QAPCh. 24 - Prob. 23QAPCh. 24 - Prob. 24QAPCh. 24 - Prob. 25QAPCh. 24 - Prob. 26QAPCh. 24 - Prob. 27QAPCh. 24 - Prob. 28QAPCh. 24 - Prob. 29QAPCh. 24 - Prob. 30QAPCh. 24 - Prob. 31QAPCh. 24 - Prob. 32QAPCh. 24 - Prob. 33QAPCh. 24 - Prob. 34QAPCh. 24 - Prob. 35QAPCh. 24 - Prob. 36QAPCh. 24 - Prob. 37QAPCh. 24 - Prob. 38QAPCh. 24 - Prob. 39QAPCh. 24 - Prob. 40QAPCh. 24 - Prob. 41QAPCh. 24 - Prob. 42QAPCh. 24 - Prob. 43QAPCh. 24 - Prob. 44QAPCh. 24 - Prob. 45QAPCh. 24 - Prob. 46QAPCh. 24 - Prob. 47QAPCh. 24 - Prob. 48QAPCh. 24 - Prob. 49QAPCh. 24 - Prob. 50QAPCh. 24 - Prob. 51QAPCh. 24 - Prob. 52QAPCh. 24 - Prob. 53QAPCh. 24 - Prob. 54QAPCh. 24 - Prob. 55QAPCh. 24 - Prob. 56QAPCh. 24 - Prob. 57QAPCh. 24 - Prob. 58QAPCh. 24 - Prob. 59QAPCh. 24 - Prob. 60QAPCh. 24 - Prob. 61QAPCh. 24 - Prob. 62QAPCh. 24 - Prob. 63QAPCh. 24 - Prob. 64QAPCh. 24 - Prob. 65QAPCh. 24 - Prob. 66QAPCh. 24 - Prob. 67QAPCh. 24 - Prob. 68QAPCh. 24 - Prob. 69QAPCh. 24 - Prob. 70QAPCh. 24 - Prob. 71QAPCh. 24 - Prob. 72QAPCh. 24 - Prob. 73QAPCh. 24 - Prob. 74QAPCh. 24 - Prob. 75QAPCh. 24 - Prob. 76QAPCh. 24 - Prob. 77QAPCh. 24 - Prob. 78QAPCh. 24 - Prob. 79QAPCh. 24 - Prob. 80QAPCh. 24 - Prob. 81QAPCh. 24 - Prob. 82QAPCh. 24 - Prob. 83QAPCh. 24 - Prob. 84QAPCh. 24 - Prob. 85QAPCh. 24 - Prob. 86QAPCh. 24 - Prob. 87QAPCh. 24 - Prob. 88QAPCh. 24 - Prob. 89QAPCh. 24 - Prob. 90QAPCh. 24 - Prob. 91QAPCh. 24 - Prob. 92QAPCh. 24 - Prob. 93QAPCh. 24 - Prob. 94QAPCh. 24 - Prob. 95QAPCh. 24 - Prob. 96QAPCh. 24 - Prob. 97QAPCh. 24 - Prob. 98QAPCh. 24 - Prob. 99QAPCh. 24 - Prob. 100QAPCh. 24 - Prob. 101QAPCh. 24 - Prob. 102QAPCh. 24 - Prob. 103QAP
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