Explanation Given info: Diameter of copper wire is .1 mm , current flowing is 100 mA , diameter of glass tube is 1.0 cm , diameter of electron beam is 1.0 mm , density of conduction electron in copper is 1.1 × 10 29 m -3 , charge of negative and positive ions is ± 2 e , density of each ion is 6.1 × 10 23 m -3 , electron density in beam is 2.2 × 10 16 m -3 . Explanation: Write the equation to find the drift speed of electrons in copper tube. v d = I n A q (1) Here, v d is the drift speed I is the current A is the area q is the charge Write expression to calculate the area of the circle. A = π d 2 4 Use π d 2 / 4 for A to rewrite equation (1). v d = I n e ( π d 2 / 4 ) Substitute 100 × 10 − 3 A for I , 1.1 × 10 29 m − 3 for n , 1.6 × 10 -19 C for e , and 10.0 cm for d to find v d . v d = 100 × 10 − 3 A ( 1.1 × 10 29 m − 3 ) ( 1.6 × 10 − 19 C ) ( 1 4 π ) ( 10 × 10 − 2 cm × 1 m 10 2 cm ) 2 = 0.72 mm / s Here the number and charge of positive and negative ions are equal therefore the total current densities are J = n + ( 2 e ) v d + n − ( − 2 e ) − v d = 4 n e v d Here, J is the current density n is the density of the conducting electron Therefore write the equation to find the drift velocity. v d = I 4 n e ( π d 2 / 4 ) (2) Substitute 100 × 10 − 3 A for I , 6

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ISBN: 9780134988566

Author: Wolfson, Richard

Publisher: Pearson Education,

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Chapter 24, Problem 46P

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The drift velocity of the electrons.

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Chapter 24, Problem 45P

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Chapter 24 Solutions

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The drift velocity of the electrons.

Solution Summary: The author explains how to determine the drift velocity of electrons in vacuum tube, copper tube and ions.

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Chapter 24 Solutions