ORGANIC CHEMISTRY MASTERINGCHEM ACCESS
9th Edition
ISBN: 9780137249442
Author: Wade
Publisher: INTER PEAR
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Chapter 24, Problem 24.36SP
Interpretation Introduction
Interpretation: The structure for aspartame is to be determined.
Concept introduction: Aspartame is an artificial sweetener. It is approx 200 times as sweet as sugar and does not have the bitter aftertaste of stevia. So it has 200 times fewer calories. Aspartame is basically calorie-free.
To determine: The structure for aspartame.
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Draw one product of an elimination reaction between the molecules below.
Note: There may be several correct answers. You only need to draw one of them. You do not need to draw any of the side products of the reaction
'O
10
+
x
也
HO
+
义
Click and drag to start
drawing a structure.
What are the angles a and b in the actual molecule of which this is a Lewis structure?
H-
:0:
C=N:
b
Note for advanced students: give the ideal angles, and don't worry about small differences from the ideal that might be caused by the fact that different electron
groups may have slightly different sizes.
a = 0°
b=0
X
A student proposes the transformation below in one step of an organic synthesis. There may be one or more products missing from the right-hand side, but
there are no reagents missing from the left-hand side. There may also be catalysts, small inorganic reagents, and other important reaction conditions missing
from the arrow.
• Is the student's transformation possible? If not, check the box under the drawing area.
• If the student's transformation is possible, then complete the reaction by adding any missing products to the right-hand side, and adding required
catalysts, inorganic reagents, or other important reaction conditions above and below the arrow.
• You do not need to balance the reaction, but be sure every important organic reactant or product is shown.
+
This transformation can't be done in one step.
T
i
Chapter 24 Solutions
ORGANIC CHEMISTRY MASTERINGCHEM ACCESS
Ch. 24.2A - Draw three-dimensional representations of the...Ch. 24.2A - Prob. 24.2PCh. 24.2B - The herbicide glyphosate (Roundup) kills plants by...Ch. 24.4 - Draw the structure of the predominant form of a....Ch. 24.4 - Draw the resonance forms of a protonated guanidino...Ch. 24.4 - Although tryptophan contains a heterocyclic amine,...Ch. 24.4 - Prob. 24.7PCh. 24.4 - Prob. 24.8PCh. 24.5A - Show how the following amino acids might be formed...Ch. 24.5B - Prob. 24.10P
Ch. 24.5C - Prob. 24.11PCh. 24.5C - Show how you would use a Strecker synthesis to...Ch. 24.6 - Suggest how you would separate the free i-ammo...Ch. 24.7A - Propose a mechanism for the acid-catalyzed...Ch. 24.7A - Give equations for the formation and...Ch. 24.7B - Prob. 24.16PCh. 24.7C - Prob. 24.17PCh. 24.8B - Draw the complete structures of the following...Ch. 24.9C - Prob. 24.19PCh. 24.9C - Prob. 24.20PCh. 24.9C - Prob. 24.21PCh. 24.9E - Prob. 24.22PCh. 24.9E - Prob. 24.23PCh. 24.10A - Propose a mechanism for the coupling of acetic...Ch. 24.10B - Show how you would synthesize Leu-Gly-Ala-Val-Phe...Ch. 24.10B - Show how solid-phase peptide synthesis would be...Ch. 24 - a. The isoelectric point (pl) of phenylalanine is...Ch. 24 - Prob. 24.28SPCh. 24 - Prob. 24.29SPCh. 24 - Prob. 24.30SPCh. 24 - Prob. 24.31SPCh. 24 - Suggest a method for the synthesis of the...Ch. 24 - Prob. 24.33SPCh. 24 - Write the complete structures for the following...Ch. 24 - The following structure is drawn in an...Ch. 24 - Prob. 24.36SPCh. 24 - Prob. 24.37SPCh. 24 - Show the steps and intermediates in the synthesis...Ch. 24 - Prob. 24.39SPCh. 24 - Lipoic acid is often found near the active sites...Ch. 24 - Prob. 24.41SPCh. 24 - Prob. 24.42SPCh. 24 - Prob. 24.43SPCh. 24 - Complete hydrolysis of an unknown basic...Ch. 24 - Prob. 24.45SPCh. 24 - Prob. 24.46SPCh. 24 - Prob. 24.47SP
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