To outline the design of the experiment.

Question

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Answer 1

Question

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

Chapter 24, Problem 24.1AYK

a.

To determine

To outline the design of the experiment.

a.

Expert Solution

Explanation of Solution

Given:

The given values are-

n=36P<0.001

Calculation:

Randomly select four groups of fruit flies, then gave each group a different dosage of caffeine (control, 1 mg/ml, 2.5 mg/ml, and 5 mg/ml), then measure the rest time of each fruit fly during a 12-hour dark period.

b.

To determine

To find out which means does this test compare, and also state the null and alternative hypothesis for the test in the setting.

b.

Expert Solution

Explanation of Solution

Given:

The following is the given graph-

EBK PRACTICE OF STATISTICS IN THE LIFE, Chapter 24, Problem 24.1AYK

Calculation:

The ANOVA F test compares the means of the four groups. Let be the mean rest time for the control group, be the mean rest time for group of a dosage of 1 mg/ml, be the mean rest time for group of a dosage of 2.5 mg/ml, and be the mean rest time for group of a dosage of 5 mg/ml. The hypotheses are:

H 0: μ1=μ2=μ3=μ4 .

H a: not all μ1,μ2,μ3 and μ4 are equal

The graph shows that as the dosage of caffeine increases, the rest time decreases. The P-value of the ANOVA F test of P < 0.0001 leads a rejection of the null hypothesis. So at least one of the average rest times of the four groups is different.

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Answer 2

Question

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

Chapter 24, Problem 24.1AYK

a.

To determine

To outline the design of the experiment.

a.

Expert Solution

Explanation of Solution

Given:

The given values are-

n=36P<0.001

Calculation:

Randomly select four groups of fruit flies, then gave each group a different dosage of caffeine (control, 1 mg/ml, 2.5 mg/ml, and 5 mg/ml), then measure the rest time of each fruit fly during a 12-hour dark period.

b.

To determine

To find out which means does this test compare, and also state the null and alternative hypothesis for the test in the setting.

b.

Expert Solution

Explanation of Solution

Given:

The following is the given graph-

EBK PRACTICE OF STATISTICS IN THE LIFE, Chapter 24, Problem 24.1AYK

Calculation:

The ANOVA F test compares the means of the four groups. Let be the mean rest time for the control group, be the mean rest time for group of a dosage of 1 mg/ml, be the mean rest time for group of a dosage of 2.5 mg/ml, and be the mean rest time for group of a dosage of 5 mg/ml. The hypotheses are:

H 0: μ1=μ2=μ3=μ4 .

H a: not all μ1,μ2,μ3 and μ4 are equal

The graph shows that as the dosage of caffeine increases, the rest time decreases. The P-value of the ANOVA F test of P < 0.0001 leads a rejection of the null hypothesis. So at least one of the average rest times of the four groups is different.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

Chapter 24, Problem 24.1AYK

a.

To determine

To outline the design of the experiment.

a.

Expert Solution

Explanation of Solution

Given:

The given values are-

n=36P<0.001

Calculation:

Randomly select four groups of fruit flies, then gave each group a different dosage of caffeine (control, 1 mg/ml, 2.5 mg/ml, and 5 mg/ml), then measure the rest time of each fruit fly during a 12-hour dark period.

b.

To determine

To find out which means does this test compare, and also state the null and alternative hypothesis for the test in the setting.

b.

Expert Solution

Explanation of Solution

Given:

The following is the given graph-

EBK PRACTICE OF STATISTICS IN THE LIFE, Chapter 24, Problem 24.1AYK

Calculation:

The ANOVA F test compares the means of the four groups. Let be the mean rest time for the control group, be the mean rest time for group of a dosage of 1 mg/ml, be the mean rest time for group of a dosage of 2.5 mg/ml, and be the mean rest time for group of a dosage of 5 mg/ml. The hypotheses are:

H 0: μ1=μ2=μ3=μ4 .

H a: not all μ1,μ2,μ3 and μ4 are equal

The graph shows that as the dosage of caffeine increases, the rest time decreases. The P-value of the ANOVA F test of P < 0.0001 leads a rejection of the null hypothesis. So at least one of the average rest times of the four groups is different.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

Chapter 24, Problem 24.1AYK

a.

To determine

To outline the design of the experiment.

a.

Expert Solution

Explanation of Solution

Given:

The given values are-

n=36P<0.001

Calculation:

Randomly select four groups of fruit flies, then gave each group a different dosage of caffeine (control, 1 mg/ml, 2.5 mg/ml, and 5 mg/ml), then measure the rest time of each fruit fly during a 12-hour dark period.

b.

To determine

To find out which means does this test compare, and also state the null and alternative hypothesis for the test in the setting.

b.

Expert Solution

Explanation of Solution

Given:

The following is the given graph-

EBK PRACTICE OF STATISTICS IN THE LIFE, Chapter 24, Problem 24.1AYK

Calculation:

The ANOVA F test compares the means of the four groups. Let be the mean rest time for the control group, be the mean rest time for group of a dosage of 1 mg/ml, be the mean rest time for group of a dosage of 2.5 mg/ml, and be the mean rest time for group of a dosage of 5 mg/ml. The hypotheses are:

H 0: μ1=μ2=μ3=μ4 .

H a: not all μ1,μ2,μ3 and μ4 are equal

The graph shows that as the dosage of caffeine increases, the rest time decreases. The P-value of the ANOVA F test of P < 0.0001 leads a rejection of the null hypothesis. So at least one of the average rest times of the four groups is different.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 24, Problem 24.1AYK

a.

To determine

To outline the design of the experiment.

a.

Expert Solution

Explanation of Solution

Given:

The given values are-

n=36P<0.001

Calculation:

Randomly select four groups of fruit flies, then gave each group a different dosage of caffeine (control, 1 mg/ml, 2.5 mg/ml, and 5 mg/ml), then measure the rest time of each fruit fly during a 12-hour dark period.

b.

To determine

To find out which means does this test compare, and also state the null and alternative hypothesis for the test in the setting.

b.

Expert Solution

Explanation of Solution

Given:

The following is the given graph-

EBK PRACTICE OF STATISTICS IN THE LIFE, Chapter 24, Problem 24.1AYK

Calculation:

The ANOVA F test compares the means of the four groups. Let be the mean rest time for the control group, be the mean rest time for group of a dosage of 1 mg/ml, be the mean rest time for group of a dosage of 2.5 mg/ml, and be the mean rest time for group of a dosage of 5 mg/ml. The hypotheses are:

H 0: μ1=μ2=μ3=μ4 .

H a: not all μ1,μ2,μ3 and μ4 are equal

The graph shows that as the dosage of caffeine increases, the rest time decreases. The P-value of the ANOVA F test of P < 0.0001 leads a rejection of the null hypothesis. So at least one of the average rest times of the four groups is different.

Answer 6

Chapter 24, Problem 24.1AYK

a.

To determine

To outline the design of the experiment.

a.

Expert Solution

Explanation of Solution

Given:

The given values are-

n=36P<0.001

Calculation:

Randomly select four groups of fruit flies, then gave each group a different dosage of caffeine (control, 1 mg/ml, 2.5 mg/ml, and 5 mg/ml), then measure the rest time of each fruit fly during a 12-hour dark period.

Answer 7

Chapter 24, Problem 24.1AYK

a.

To determine

To outline the design of the experiment.

Answer 8

a.

Expert Solution

Explanation of Solution

Given:

The given values are-

n=36P<0.001

Calculation:

Randomly select four groups of fruit flies, then gave each group a different dosage of caffeine (control, 1 mg/ml, 2.5 mg/ml, and 5 mg/ml), then measure the rest time of each fruit fly during a 12-hour dark period.

Answer 9

a.

Expert Solution

Answer 10

a.

Expert Solution

Answer 11

Expert Solution

Answer 12

b.

To determine

To find out which means does this test compare, and also state the null and alternative hypothesis for the test in the setting.

b.

Expert Solution

Explanation of Solution

Given:

The following is the given graph-

EBK PRACTICE OF STATISTICS IN THE LIFE, Chapter 24, Problem 24.1AYK

Calculation:

The ANOVA F test compares the means of the four groups. Let be the mean rest time for the control group, be the mean rest time for group of a dosage of 1 mg/ml, be the mean rest time for group of a dosage of 2.5 mg/ml, and be the mean rest time for group of a dosage of 5 mg/ml. The hypotheses are:

H 0: μ1=μ2=μ3=μ4 .

H a: not all μ1,μ2,μ3 and μ4 are equal

The graph shows that as the dosage of caffeine increases, the rest time decreases. The P-value of the ANOVA F test of P < 0.0001 leads a rejection of the null hypothesis. So at least one of the average rest times of the four groups is different.

Answer 13

b.

To determine

To find out which means does this test compare, and also state the null and alternative hypothesis for the test in the setting.

Answer 14

b.

Expert Solution

Explanation of Solution

Given:

The following is the given graph-

EBK PRACTICE OF STATISTICS IN THE LIFE, Chapter 24, Problem 24.1AYK

Calculation:

The ANOVA F test compares the means of the four groups. Let be the mean rest time for the control group, be the mean rest time for group of a dosage of 1 mg/ml, be the mean rest time for group of a dosage of 2.5 mg/ml, and be the mean rest time for group of a dosage of 5 mg/ml. The hypotheses are:

H 0: μ1=μ2=μ3=μ4 .

H a: not all μ1,μ2,μ3 and μ4 are equal

The graph shows that as the dosage of caffeine increases, the rest time decreases. The P-value of the ANOVA F test of P < 0.0001 leads a rejection of the null hypothesis. So at least one of the average rest times of the four groups is different.