Chapter 24, Problem 24.125P

Interpretation Introduction

Interpretation:

Binding energy of ${}^{7}Li$ has to be calculated in $\text{eV/nucleus}$ and $\text{kJ/mol}$

Concept Introduction:

Nuclear reaction: A nuclear reaction in which a lighter nucleus fuses together into new stable nuclei or a heavier nucleus split into stable daughter nuclei with the release of large amount of energy.

Nuclear binding energy: It is the energy that requires for the breaking one mole of nuclei of an element to its individual nucleons.

  $\text{Nucleus + nuclear binding energy }\underset{}{\to }\text{ nucleons}$

It can be calculated using the given formulae,

  $\begin{array}{l}\text{Binding energy = }\Delta \text{m}\left(\text{in amu}\right)\times \frac{\text{931}\text{.5 MeV}}{1\text{ amu}}\\ \\ \text{Binding energy},{\text{ E = mc}}^2\end{array}$

Binding Energy per Nucleon can be determined as follows:

  $\text{Binding energy per nucleon = }\frac{\text{Binding energy}}{\text{No}\text{. of nucleons}}$

Unit conversion:

  $\begin{array}{l}1{\text{ MeV = 10}}^6\text{ eV}\\ \\ 1\text{ kJ = }\left(1000\text{ J}\right)\left(\frac{1\text{ eV}}{1.602\times {10}^{-19}\text{ J}}\right)\end{array}$