(a)
Section 1:
To find: The percentage of all attempted field goals made by Seth Fitzgerald.
(a)

Answer to Problem 20E
Solution: The required percentage is 53.33%.
Explanation of Solution
Calculation:
The percentage of field goals made by Seth Fitzgerald can be calculated as a ratio of the number of attempts, which are made by Seth Fitzgerald and total number of all attempted field goals by Seth Fitzgerald in a multiple of 100.
The total number of attempted field goal is calculated as:
The total number of field goals made by Seth Fitzgerald is calculated as:
Therefore, the required percentage is calculated as:
Section 2:
To find: The percentage of all attempted field goals made by Roberto Mantovani.
Solution: The required percentage is 53.84%.
Calculation:
The percentage of field goals made by Roberto Mantovani can be calculated as a ratio of the number of attempts that are made by Roberto Mantovani and total number of all attempted field goals in a multiple of 100.
The total number of attempted field goal is calculated as:
The total number of field goal made by Roberto Mantovani is calculated as:
Therefore, the required percentage is calculated as:
(b)
Section 1:
To find: The percentage of two-point and three-point field goals by Seth Fitzgerald.
(b)
Section 1:

Answer to Problem 20E
Solution: The percentages of two-point and three-point field goals are 55.56% and 50%.
Explanation of Solution
Calculation:
The percentage of two-point and three-point field goals can be calculated as a ratio of the number of attempts that are made by Seth Fitzgerald and the number of two-point and three-point field goals in a multiple of 100.
The total number of two-point attempted field goals by Seth Fitzgerald is calculated as:
The number of two-point field goals made is 5.
Therefore, the percentage of two-point field goals is calculated as:
The number of three-point attempted field goals is calculated as:
The number of three-point field goals made is 3.
Therefore, the percentage of three-point field goals made is calculated as:
Section 2:
To find: The percentage of two-point and three-point field goals by Roberto Mantovani.
Solution: The percentages of two-point and three-point field goals are 55.35% and 20%.
Explanation:
Calculation:
The percentage of two-point and three-point field goals made by Roberto Mantovani can be calculated as a ratio of the number of attempts that are made by Roberto Mantovani and the number of two-point and three-point field goals attempted in a multiple of 100.
The total number of two-point attempted field goals by Roberto Mantovani is calculated as:
The number of two-point field goals made is 62.
Therefore, the percentage of two-point field goals is calculated as:
The number of three-point field goals is calculated as:
The number of three-point field goals made is 1.
Therefore, the percentage of three-point field goals is calculated as:
(c)
To explain: The reason for which the provided statement is correct though its sounds to be impossible.
(c)

Answer to Problem 20E
Solution: As the number of goals made by Robert is more compared to the individual type of goals, the overall percentage is better.
Explanation of Solution
Want to see more full solutions like this?
Chapter 24 Solutions
Statistics: Concepts and Controversies - WebAssign and eBook Access
- The table given shows the length, in feet, of dolphins at an aquarium. 7 15 10 18 18 15 9 22 Are there any outliers in the data? There is an outlier at 22 feet. There is an outlier at 7 feet. There are outliers at 7 and 22 feet. There are no outliers.arrow_forwardStart by summarizing the key events in a clear and persuasive manner on the article Endrikat, J., Guenther, T. W., & Titus, R. (2020). Consequences of Strategic Performance Measurement Systems: A Meta-Analytic Review. Journal of Management Accounting Research?arrow_forwardThe table below was compiled for a middle school from the 2003 English/Language Arts PACT exam. Grade 6 7 8 Below Basic 60 62 76 Basic 87 134 140 Proficient 87 102 100 Advanced 42 24 21 Partition the likelihood ratio test statistic into 6 independent 1 df components. What conclusions can you draw from these components?arrow_forward
- What is the value of the maximum likelihood estimate, θ, of θ based on these data? Justify your answer. What does the value of θ suggest about the value of θ for this biased die compared with the value of θ associated with a fair, unbiased, die?arrow_forwardShow that L′(θ) = Cθ394(1 −2θ)604(395 −2000θ).arrow_forwarda) Let X and Y be independent random variables both with the same mean µ=0. Define a new random variable W = aX +bY, where a and b are constants. (i) Obtain an expression for E(W).arrow_forward
- The table below shows the estimated effects for a logistic regression model with squamous cell esophageal cancer (Y = 1, yes; Y = 0, no) as the response. Smoking status (S) equals 1 for at least one pack per day and 0 otherwise, alcohol consumption (A) equals the average number of alcohoic drinks consumed per day, and race (R) equals 1 for blacks and 0 for whites. Variable Effect (β) P-value Intercept -7.00 <0.01 Alcohol use 0.10 0.03 Smoking 1.20 <0.01 Race 0.30 0.02 Race × smoking 0.20 0.04 Write-out the prediction equation (i.e., the logistic regression model) when R = 0 and again when R = 1. Find the fitted Y S conditional odds ratio in each case. Next, write-out the logistic regression model when S = 0 and again when S = 1. Find the fitted Y R conditional odds ratio in each case.arrow_forwardThe chi-squared goodness-of-fit test can be used to test if data comes from a specific continuous distribution by binning the data to make it categorical. Using the OpenIntro Statistics county_complete dataset, test the hypothesis that the persons_per_household 2019 values come from a normal distribution with mean and standard deviation equal to that variable's mean and standard deviation. Use signficance level a = 0.01. In your solution you should 1. Formulate the hypotheses 2. Fill in this table Range (-⁰⁰, 2.34] (2.34, 2.81] (2.81, 3.27] (3.27,00) Observed 802 Expected 854.2 The first row has been filled in. That should give you a hint for how to calculate the expected frequencies. Remember that the expected frequencies are calculated under the assumption that the null hypothesis is true. FYI, the bounderies for each range were obtained using JASP's drag-and-drop cut function with 8 levels. Then some of the groups were merged. 3. Check any conditions required by the chi-squared…arrow_forwardSuppose that you want to estimate the mean monthly gross income of all households in your local community. You decide to estimate this population parameter by calling 150 randomly selected residents and asking each individual to report the household’s monthly income. Assume that you use the local phone directory as the frame in selecting the households to be included in your sample. What are some possible sources of error that might arise in your effort to estimate the population mean?arrow_forward
- For the distribution shown, match the letter to the measure of central tendency. A B C C Drag each of the letters into the appropriate measure of central tendency. Mean C Median A Mode Barrow_forwardA physician who has a group of 38 female patients aged 18 to 24 on a special diet wishes to estimate the effect of the diet on total serum cholesterol. For this group, their average serum cholesterol is 188.4 (measured in mg/100mL). Suppose that the total serum cholesterol measurements are normally distributed with standard deviation of 40.7. (a) Find a 95% confidence interval of the mean serum cholesterol of patients on the special diet.arrow_forwardThe accompanying data represent the weights (in grams) of a simple random sample of 10 M&M plain candies. Determine the shape of the distribution of weights of M&Ms by drawing a frequency histogram. Find the mean and median. Which measure of central tendency better describes the weight of a plain M&M? Click the icon to view the candy weight data. Draw a frequency histogram. Choose the correct graph below. ○ A. ○ C. Frequency Weight of Plain M and Ms 0.78 0.84 Frequency OONAG 0.78 B. 0.9 0.96 Weight (grams) Weight of Plain M and Ms 0.84 0.9 0.96 Weight (grams) ○ D. Candy Weights 0.85 0.79 0.85 0.89 0.94 0.86 0.91 0.86 0.87 0.87 - Frequency ☑ Frequency 67200 0.78 → Weight of Plain M and Ms 0.9 0.96 0.84 Weight (grams) Weight of Plain M and Ms 0.78 0.84 Weight (grams) 0.9 0.96 →arrow_forward
- MATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th...StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C...StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage Learning
- Elementary Statistics: Picturing the World (7th E...StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. Freeman





