The compounds with their correct molecular masses should be matched. Also the way odd and even molecular mass of compounds help to identify the compounds should be stated. Concept introduction: Mass spectrometry is an important spectroscopic method to determine the molecular weights and molecular formulas of the compounds. It also can help in the identification of compound or determination of its structure. A mass spectrograph is plotted between the intensity of ions on y-axis and m/z on x axis. Mass spectrometry works as follows: A sample is converted into a gaseous ion by an ionization technique in the mass spectrometer. Then on the basis of mass-to-charge ( m/z ) ratios, gaseous ions are arranged. These ions generate electric current at detector and a mass spectrum is formed.

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Answer 1

Question

Chapter 24, Problem 1Q

Interpretation Introduction

Interpretation:

The compounds with their correct molecular masses should be matched. Also the way odd and even molecular mass of compounds help to identify the compounds should be stated.

Concept introduction:

Mass spectrometry is an important spectroscopic method to determine the molecular weights and molecular formulas of the compounds. It also can help in the identification of compound or determination of its structure.

A mass spectrograph is plotted between the intensity of ions on y-axis and m/z on x axis. Mass spectrometry works as follows:

A sample is converted into a gaseous ion by an ionization technique in the mass spectrometer.

Then on the basis of mass-to-charge (m/z) ratios, gaseous ions are arranged.

These ions generate electric current at detector and a mass spectrum is formed.

Expert Solution & Answer

Explanation of Solution

To assign the molecular weights to compounds the rule of thirteen is utilized in mass spectrometry. Thirteen here is obtained by the addition of the mass of carbon and hydrogen.

Steps to determine the molecular weight through the rule of thirteen is as follows:

m/zvalue is first divided by 13 to obtain the number of carbon present in the compound, then integer obtained in the quotient is the number of carbons.
This integer is added to the reminder to obtain the number of hydrogen present in the compound.
If some heteroatom is present like oxygen or nitrogen then some number of carbon and hydrogens are substracted accordingly to get the appropriate m/z value.
An important rule for the presence of nitrogen is used which states that a compound whose molecular ion contains an even m/z value will contain either no or even nitrogen atoms and if a compound has odd m/z value then the molecular ion contains odd nitrogen atoms.

The molecular weight of azobenzene is 182, pyridine is 79, and ethanol is 46.

Since azobenzene has an even m/z value so it will have even number of nitrogen atom that is 2 and pyridine has an odd m/z value so it will have odd number of nitrogen that is 1. So it is easier to determine the number of nitrogen atom present in the compound by their molecular weights.

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Students have asked these similar questions

You are a forensic scientist. You are investigating a murder involving poison. The victim was poisoned with a compound called di-chlorobenzene, whose formula is C6H4Cl2. Autopsy results show that the victim’s body contained about 27.5 g of the poison, but the actual amount could have been slightly higher due to tissue absorption. The main suspect is his wife, Suzanne, who works as a chemistry professor. Records show that she purchased 15 g of benzene (C6H6) two days before the murder. Benzene is one of the compounds used to make the poison. She claims she was using it to make methyl benzene (C6H5CH3), an innocuous compound, for use in her lab. She shows you the bottle of methyl benzene she claims to have made. It contains 25 g of methyl benzene. To produce di-chlorobenzene, the reaction is: Cl2(g) + C6H6(l) ⟶⟶ C6H4Cl2(l) + H2(g) To produce methyl benzene, the reaction is: CH4(g) + C6H6(l) ⟶⟶ C6H5CH3(l) + H2(g) Use stoichiometry to solve this case. Be sure to show…

You are a forensic scientist. You are investigating a murder involving poison. The victim was poisoned with a compound called di-chlorobenzene, whose formula is C6H4Cl2. Autopsy results show that the victim’s body contained about 27.5 g of the poison, but the actual amount could have been slightly higher due to tissue absorption. The main suspect is his wife, Suzanne, who works as a chemistry professor. Records show that she purchased 15 g of benzene (C6H6) two days before the murder. Benzene is one of the compounds use to make the poison. She claims she was using it to make methyl benzene (C6H5CH3), an innocuous compound, for use in her lab. She shows you the bottle of methyl benzene she claims to have made. It contains 25 g of methyl benzene. To produce di-chlorobenzene, the reaction is: Cl2(g) + C6H6(l) ⟶⟶ C6H4Cl2(l) + H2(g) To produce methyl benzene, the reaction is: CH4(g) + C6H6(l) ⟶⟶ C6H5CH3(l) + H2(g) Use stoichiometry to solve this case. Be sure to show all…

1) Compound 3-chlorobenzoic acid can be prepared from methylbenzene through a two- steps reaction. chemical equations for the reactions ? 2) 2 C12 (g) + 2 H20 (g) = 4 HCI (g) + 02 (g) Ac 2 HCI (g) + 1/2 02 (g) = C12 (g) + H20 (g) Ac' relationship between Ac and Ac' ? 3) Hydrogen iodide, HI decomposes 2HI (g) = H2 (g) + 12 (g) AH < 0 -2.00 atm of HI placed in a glass - allowed to reach equilibrium a) Ap for the reaction if 30.0% of HI decomposes ? b) the concentration of HI(g) will increase, decrease or remain the same when the temperature of reaction is increased ?

Answer 2

Question

Chapter 24, Problem 1Q

Interpretation Introduction

Interpretation:

The compounds with their correct molecular masses should be matched. Also the way odd and even molecular mass of compounds help to identify the compounds should be stated.

Concept introduction:

Mass spectrometry is an important spectroscopic method to determine the molecular weights and molecular formulas of the compounds. It also can help in the identification of compound or determination of its structure.

A mass spectrograph is plotted between the intensity of ions on y-axis and m/z on x axis. Mass spectrometry works as follows:

A sample is converted into a gaseous ion by an ionization technique in the mass spectrometer.

Then on the basis of mass-to-charge (m/z) ratios, gaseous ions are arranged.

These ions generate electric current at detector and a mass spectrum is formed.

Expert Solution & Answer

Explanation of Solution

To assign the molecular weights to compounds the rule of thirteen is utilized in mass spectrometry. Thirteen here is obtained by the addition of the mass of carbon and hydrogen.

Steps to determine the molecular weight through the rule of thirteen is as follows:

m/zvalue is first divided by 13 to obtain the number of carbon present in the compound, then integer obtained in the quotient is the number of carbons.
This integer is added to the reminder to obtain the number of hydrogen present in the compound.
If some heteroatom is present like oxygen or nitrogen then some number of carbon and hydrogens are substracted accordingly to get the appropriate m/z value.
An important rule for the presence of nitrogen is used which states that a compound whose molecular ion contains an even m/z value will contain either no or even nitrogen atoms and if a compound has odd m/z value then the molecular ion contains odd nitrogen atoms.

The molecular weight of azobenzene is 182, pyridine is 79, and ethanol is 46.

Since azobenzene has an even m/z value so it will have even number of nitrogen atom that is 2 and pyridine has an odd m/z value so it will have odd number of nitrogen that is 1. So it is easier to determine the number of nitrogen atom present in the compound by their molecular weights.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 24, Problem 1Q

Interpretation Introduction

Interpretation:

The compounds with their correct molecular masses should be matched. Also the way odd and even molecular mass of compounds help to identify the compounds should be stated.

Concept introduction:

Mass spectrometry is an important spectroscopic method to determine the molecular weights and molecular formulas of the compounds. It also can help in the identification of compound or determination of its structure.

A mass spectrograph is plotted between the intensity of ions on y-axis and m/z on x axis. Mass spectrometry works as follows:

A sample is converted into a gaseous ion by an ionization technique in the mass spectrometer.

Then on the basis of mass-to-charge (m/z) ratios, gaseous ions are arranged.

These ions generate electric current at detector and a mass spectrum is formed.

Expert Solution & Answer

Explanation of Solution

To assign the molecular weights to compounds the rule of thirteen is utilized in mass spectrometry. Thirteen here is obtained by the addition of the mass of carbon and hydrogen.

Steps to determine the molecular weight through the rule of thirteen is as follows:

m/zvalue is first divided by 13 to obtain the number of carbon present in the compound, then integer obtained in the quotient is the number of carbons.
This integer is added to the reminder to obtain the number of hydrogen present in the compound.
If some heteroatom is present like oxygen or nitrogen then some number of carbon and hydrogens are substracted accordingly to get the appropriate m/z value.
An important rule for the presence of nitrogen is used which states that a compound whose molecular ion contains an even m/z value will contain either no or even nitrogen atoms and if a compound has odd m/z value then the molecular ion contains odd nitrogen atoms.

The molecular weight of azobenzene is 182, pyridine is 79, and ethanol is 46.

Since azobenzene has an even m/z value so it will have even number of nitrogen atom that is 2 and pyridine has an odd m/z value so it will have odd number of nitrogen that is 1. So it is easier to determine the number of nitrogen atom present in the compound by their molecular weights.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 24, Problem 1Q

Interpretation Introduction

Interpretation:

The compounds with their correct molecular masses should be matched. Also the way odd and even molecular mass of compounds help to identify the compounds should be stated.

Concept introduction:

Mass spectrometry is an important spectroscopic method to determine the molecular weights and molecular formulas of the compounds. It also can help in the identification of compound or determination of its structure.

A mass spectrograph is plotted between the intensity of ions on y-axis and m/z on x axis. Mass spectrometry works as follows:

A sample is converted into a gaseous ion by an ionization technique in the mass spectrometer.

Then on the basis of mass-to-charge (m/z) ratios, gaseous ions are arranged.

These ions generate electric current at detector and a mass spectrum is formed.

Expert Solution & Answer

Explanation of Solution

To assign the molecular weights to compounds the rule of thirteen is utilized in mass spectrometry. Thirteen here is obtained by the addition of the mass of carbon and hydrogen.

Steps to determine the molecular weight through the rule of thirteen is as follows:

m/zvalue is first divided by 13 to obtain the number of carbon present in the compound, then integer obtained in the quotient is the number of carbons.
This integer is added to the reminder to obtain the number of hydrogen present in the compound.
If some heteroatom is present like oxygen or nitrogen then some number of carbon and hydrogens are substracted accordingly to get the appropriate m/z value.
An important rule for the presence of nitrogen is used which states that a compound whose molecular ion contains an even m/z value will contain either no or even nitrogen atoms and if a compound has odd m/z value then the molecular ion contains odd nitrogen atoms.

The molecular weight of azobenzene is 182, pyridine is 79, and ethanol is 46.

Since azobenzene has an even m/z value so it will have even number of nitrogen atom that is 2 and pyridine has an odd m/z value so it will have odd number of nitrogen that is 1. So it is easier to determine the number of nitrogen atom present in the compound by their molecular weights.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 24, Problem 1Q

Interpretation Introduction

Interpretation:

The compounds with their correct molecular masses should be matched. Also the way odd and even molecular mass of compounds help to identify the compounds should be stated.

Concept introduction:

Mass spectrometry is an important spectroscopic method to determine the molecular weights and molecular formulas of the compounds. It also can help in the identification of compound or determination of its structure.

A mass spectrograph is plotted between the intensity of ions on y-axis and m/z on x axis. Mass spectrometry works as follows:

A sample is converted into a gaseous ion by an ionization technique in the mass spectrometer.

Then on the basis of mass-to-charge (m/z) ratios, gaseous ions are arranged.

These ions generate electric current at detector and a mass spectrum is formed.

Expert Solution & Answer

Explanation of Solution

To assign the molecular weights to compounds the rule of thirteen is utilized in mass spectrometry. Thirteen here is obtained by the addition of the mass of carbon and hydrogen.

Steps to determine the molecular weight through the rule of thirteen is as follows:

m/zvalue is first divided by 13 to obtain the number of carbon present in the compound, then integer obtained in the quotient is the number of carbons.
This integer is added to the reminder to obtain the number of hydrogen present in the compound.
If some heteroatom is present like oxygen or nitrogen then some number of carbon and hydrogens are substracted accordingly to get the appropriate m/z value.
An important rule for the presence of nitrogen is used which states that a compound whose molecular ion contains an even m/z value will contain either no or even nitrogen atoms and if a compound has odd m/z value then the molecular ion contains odd nitrogen atoms.

The molecular weight of azobenzene is 182, pyridine is 79, and ethanol is 46.

Since azobenzene has an even m/z value so it will have even number of nitrogen atom that is 2 and pyridine has an odd m/z value so it will have odd number of nitrogen that is 1. So it is easier to determine the number of nitrogen atom present in the compound by their molecular weights.

Answer 6

Chapter 24, Problem 1Q

Interpretation Introduction

Interpretation:

The compounds with their correct molecular masses should be matched. Also the way odd and even molecular mass of compounds help to identify the compounds should be stated.

Concept introduction:

Mass spectrometry is an important spectroscopic method to determine the molecular weights and molecular formulas of the compounds. It also can help in the identification of compound or determination of its structure.

A mass spectrograph is plotted between the intensity of ions on y-axis and m/z on x axis. Mass spectrometry works as follows:

A sample is converted into a gaseous ion by an ionization technique in the mass spectrometer.

Then on the basis of mass-to-charge (m/z) ratios, gaseous ions are arranged.

These ions generate electric current at detector and a mass spectrum is formed.

Expert Solution & Answer

Explanation of Solution

To assign the molecular weights to compounds the rule of thirteen is utilized in mass spectrometry. Thirteen here is obtained by the addition of the mass of carbon and hydrogen.

Steps to determine the molecular weight through the rule of thirteen is as follows:

m/zvalue is first divided by 13 to obtain the number of carbon present in the compound, then integer obtained in the quotient is the number of carbons.
This integer is added to the reminder to obtain the number of hydrogen present in the compound.
If some heteroatom is present like oxygen or nitrogen then some number of carbon and hydrogens are substracted accordingly to get the appropriate m/z value.
An important rule for the presence of nitrogen is used which states that a compound whose molecular ion contains an even m/z value will contain either no or even nitrogen atoms and if a compound has odd m/z value then the molecular ion contains odd nitrogen atoms.

The molecular weight of azobenzene is 182, pyridine is 79, and ethanol is 46.

Since azobenzene has an even m/z value so it will have even number of nitrogen atom that is 2 and pyridine has an odd m/z value so it will have odd number of nitrogen that is 1. So it is easier to determine the number of nitrogen atom present in the compound by their molecular weights.

Answer 7

Chapter 24, Problem 1Q

Interpretation Introduction

Interpretation:

The compounds with their correct molecular masses should be matched. Also the way odd and even molecular mass of compounds help to identify the compounds should be stated.

Concept introduction:

Mass spectrometry is an important spectroscopic method to determine the molecular weights and molecular formulas of the compounds. It also can help in the identification of compound or determination of its structure.

A mass spectrograph is plotted between the intensity of ions on y-axis and m/z on x axis. Mass spectrometry works as follows:

A sample is converted into a gaseous ion by an ionization technique in the mass spectrometer.

Then on the basis of mass-to-charge (m/z) ratios, gaseous ions are arranged.

These ions generate electric current at detector and a mass spectrum is formed.

Answer 8

Expert Solution & Answer

Explanation of Solution

To assign the molecular weights to compounds the rule of thirteen is utilized in mass spectrometry. Thirteen here is obtained by the addition of the mass of carbon and hydrogen.

Steps to determine the molecular weight through the rule of thirteen is as follows:

m/zvalue is first divided by 13 to obtain the number of carbon present in the compound, then integer obtained in the quotient is the number of carbons.
This integer is added to the reminder to obtain the number of hydrogen present in the compound.
If some heteroatom is present like oxygen or nitrogen then some number of carbon and hydrogens are substracted accordingly to get the appropriate m/z value.
An important rule for the presence of nitrogen is used which states that a compound whose molecular ion contains an even m/z value will contain either no or even nitrogen atoms and if a compound has odd m/z value then the molecular ion contains odd nitrogen atoms.

The molecular weight of azobenzene is 182, pyridine is 79, and ethanol is 46.

Since azobenzene has an even m/z value so it will have even number of nitrogen atom that is 2 and pyridine has an odd m/z value so it will have odd number of nitrogen that is 1. So it is easier to determine the number of nitrogen atom present in the compound by their molecular weights.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Ch. 24 - Prob. 1Q Ch. 24 - Prob. 2Q Ch. 24 - Prob. 3Q Ch. 24 - Prob. 4Q Ch. 24 - Prob. 5Q Ch. 24 - Prob. 6Q Ch. 24 - Prob. 7Q Ch. 24 - Prob. 8Q Ch. 24 - Prob. 9Q

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