Interpretation:
The predominant species of glutamic acid in strongly acidic and basic solutions and at its isoelectric point is to be predicted, and the higher isoelectric point of glutamine than that of glutamic acid is to be explained.
Concept introduction:
Amino acids contain both acidic (
In solid state, it exists as dipolar or zwitter ionic state, where
In aqueous state, equilibrium exists between cationic and anionic form. The predominant form depends on the pH and the nature of amino acid.

Answer to Problem 1PP
Solution:
a)
b)
c)
d)
Glutamic acid is a dicarboxylic acid, whereas glutamine with only one carboxyl group has a resemblance with glycine or phenylalanine. Moreover, its isoelectric point exists at a higher
Explanation of Solution
a) Strongly acidic solution
In strongly acidic solution, all amino acids are present as cations. Here,
b) Strongly basic solution
In strongly basic solution, all amino acids are present as anions. The addition of base causes removal of proton from both carboxylic acid groups, resulting in a dianion. The amine group is electrically neutral.
c) At the isoelectric point (pl=3.2)
Each amino acid has a particular intermediate pH at which the concentration of dipolar ion will be maximum, and the concentration of cations and anions will be equal. This point is called isoelectric point and will be different for each amino acid.
d) The isoelectric point of glutamic is consider higher than that of glutamic acid
The structure of glutamine and glutamic acid is as follows:
Glutamine contains only one carboxylic acid group, whereas glutamic acid has two. At isoelectric point, dipolar state exists that is there will be a carboxylate anion and an ammonium group. In order to maintain the dipolar form in glutamic acid, only one carboxylate ion is required. To suppress the ionization of second carboxylic acid, more acid is required than that for glutamine. That is pH of glutamic acid is maintained lower than that of glutamine to achieve isoelectric point. (Isoelectric point is the average of
Hence, isoelectronic point of glutamine is higher than that of glutamic acid.
Want to see more full solutions like this?
Chapter 24 Solutions
ORGANIC CHEMISTRY (LL) W/WILEYPLUS NEXT
- Classify each molecule as optically active or inactive. Determine the configuration at each H соон Chirality center OH 애 He OH H3C Ноос H H COOH A K B.arrow_forwardQ1: Rank the relative nucleophilicity of the following species in ethanol. CH3O¯, CH3OH, CH3COO, CH3COOH, CH3S Q2: Group these solvents into either protic solvents or aprotic solvents. Acetonitrile (CH3CN), H₂O, Acetic acid (CH3COOH), Acetone (CH3COCH3), CH3CH2OH, DMSO (CH3SOCH3), DMF (HCON(CH3)2), CH3OHarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- 10. The main product of the following reaction is [1.1:4',1"-terphenyl]-2'-yl(1h-pyrazol-4- yl)methanone Ph N-H Pharrow_forwardDraw the Fischer projection for a D-aldo-pentose. (aldehyde pentose). How many total stereoisomers are there? Name the sugar you drew. Draw the Fischer projection for a L-keto-hexose. (ketone pentose). How many total stereoisomers are there? Draw the enantiomer.arrow_forwardDraw a structure using wedges and dashes for the following compound: H- Et OH HO- H H- Me OHarrow_forward
- Which of the following molecules are NOT typical carbohydrates? For the molecules that are carbohydrates, label them as an aldose or ketose. HO Он ОН ОН Он ОН но ΤΗ HO ОН HO eve Он он ОН ОН ОН If polyethylene has an average molecular weight of 25,000 g/mol, how many repeat units are present?arrow_forwardDraw the a-anomer cyclized pyranose Haworth projection of the below hexose. Circle the anomeric carbons. Number the carbons on the Fischer and Haworth projections. Assign R and S for each chiral center. HO CHO -H HO -H H- -OH H -OH CH₂OH Draw the ẞ-anomer cyclized furanose Haworth projection for the below hexose. Circle the anomeric carbons. Number the carbons on the Fischer and Haworth projections. HO CHO -H H -OH HO -H H -OH CH₂OHarrow_forwardName the below disaccharide. Circle any hemiacetals. Identify the numbering of glycosidic linkage, and identify it as a or ẞ. OH HO HO OH HO HO HO OHarrow_forward
- What are the monomers used to make the following polymers? F. а. b. с. d. Вецер хочому なarrow_forward1. Propose a reasonable mechanism for the following transformation. I'm looking for curved mechanistic arrows and appropriate formal charges on intermediates. OMe MeO OMe Me2N NMe2 OTBS OH xylenes OMe 'OTBSarrow_forwardWhat is the polymer made from the following monomers? What type of polymerization is used for each? а. ОН H2N но b. ن -NH2 d. H₂N NH2 довarrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage LearningOrganic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning

