
Concept explainers
(a)
Interpretation:
The name and the formula complex ion consist of Cr3+ as the central ion and two NH3 molecules and four Cl- ions as ligands should be determined.
Concept introduction:
The coordination number of any complex is established by the total number of ions or atoms proximately surrounding or nearest to the central atom in a crystal or compound.
The oxidation number of an atom is equivalent to the charge on the ion, e.g. Na+ has the oxidation number of +1 and O2- has -2. In a molecule or compound, it is the sum of the oxidation numbers of its component atoms. The total charge of the ligands is deducted from the overall charge of the coordinate complex.
When any complex is named, the ligands are named foremost, in the alphabetical order, and the metal atom or ion is named afterward. Conversely, in the chemical formula, the metal atom or ion is marked before the ligands.

Answer to Problem 1E
The formula of the complex is
Explanation of Solution
The complex has Cr3+ as the central ion and two NH3 molecules and four Cl- ions as ligands surrounding the central ion.NH3molecules are neutral, and four Cl-ions carry -1 charge each. The oxidation number of the central ion is +3. The net charge of the complex is -1
Therefore, the formula of the complex is
(b)
Interpretation:
The formula and name of a complex which consist of iron(III) with coordination number of 6 and CN- as ligands should be determined.
Concept introduction:
The coordination number of any complex is established by the total number of ions or atoms proximately surrounding or nearest to the central atom in a crystal or compound.
The oxidation number of an atom is equivalent to the charge on the ion, e.g. Na+ has the oxidation number of +1 and O2- has -2. In a molecule or compound, it is the sum of the oxidation numbers of its component atoms. The total charge of the ligands is deducted from the overall charge of the coordinate complex.
When any complex is named, the ligands are named foremost, in the alphabetical order, and the metal atom or ion is named afterward. Conversely, in the chemical formula, the metal atom or ion is marked before the ligands.

Answer to Problem 1E
The formula of the complex is
Explanation of Solution
The complex has Iron as the central ion and six CN- ions as ligands surrounding the central ion.
Therefore, the formula of the complex is
(c)
Interpretation:
The name and the formula of a coordination compound consists of given complex ions: one a complex contain Cr(III) with ethylenediamine (en) having coordination number 6 and second, a complex contain Ni(II) with CN- having coordination number should be determined.
Concept introduction:
The coordination number of any complex is established by the total number of ions or atoms proximately surrounding or nearest to the central atom in a crystal or compound.
The oxidation number of an atom is equivalent to the charge on the ion, e.g. Na+ has the oxidation number of +1 and O2- has -2. In a molecule or compound, it is the sum of the oxidation numbers of its component atoms. The total charge of the ligands is deducted from the overall charge of the coordinate complex.
When any complex is named, the ligands are named foremost, in the alphabetical order, and the metal atom or ion is named afterward. Conversely, in the chemical formula, the metal atom or ion is marked before the ligands.

Answer to Problem 1E
The formula of the complex is
Explanation of Solution
In the first complex, ethylenediamine is a neutral ligand. Thus, for a complex of Cr (III) containing three en the charge from ligands will be0. Combined with a +3-oxidation state metal, this complex will have a charge of +3 and will, therefore, be the cationic part of the double complex is [Cr(en)3]+3.
In the Ni (II) complex, as mentioned above, each CN will contribute a charge of -1 giving the tetracyano complex a charge of -4 from the ligands. This, with the +2 oxidation on nickel gives the complex a net negative charge -2 making it the anionic part of the double compound with the formula [NiCN4]2-.
Therefore, the formula of the complex is
Want to see more full solutions like this?
Chapter 24 Solutions
General Chemistry: Principles and Modern Applications (11th Edition)
- For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. དྲ。 ✗MgBr ? O CI Will the first product that forms in this reaction create a new C-C bond? Yes No • ? Will the first product that forms in this reaction create a new CC bond? Yes No × : ☐ Xarrow_forwardPredict the major products of this organic reaction: OH NaBH4 H ? CH3OH Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. ☐ : Sarrow_forwardPredict the major products of this organic reaction: 1. LIAIHA 2. H₂O ? Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. X : ☐arrow_forward
- For each reaction below, decide if the first stable organic product that forms in solution will create a new C - C bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. NH2 tu ? ? OH Will the first product that forms in this reaction create a new CC bond? Yes No Will the first product that forms in this reaction create a new CC bond? Yes No C $ ©arrow_forwardAs the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C-C bond as its major product: 1. MgCl ? 2. H₂O* If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. This reaction will not make a product with a new CC bond. G marrow_forwardIncluding activity coefficients, find [Hg22+] in saturated Hg2Br2 in 0.00100 M NH4 Ksp Hg2Br2 = 5.6×10-23.arrow_forward
- give example for the following(by equation) a. Converting a water insoluble compound to a soluble one. b. Diazotization reaction form diazonium salt c. coupling reaction of a diazonium salt d. indacator properties of MO e. Diazotization ( diazonium salt of bromobenzene)arrow_forward2-Propanone and ethyllithium are mixed and subsequently acid hydrolyzed. Draw and name the structures of the products.arrow_forward(Methanesulfinyl)methane is reacted with NaH, and then with acetophenone. Draw and name the structures of the products.arrow_forward
- 3-Oxo-butanenitrile and (E)-2-butenal are mixed with sodium ethoxide in ethanol. Draw and name the structures of the products.arrow_forwardWhat is the reason of the following(use equations if possible) a.) In MO preperation through diazotization: Addition of sodium nitrite in acidfied solution in order to form diazonium salt b.) in MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at low pH c.) In MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at pH 4.5 d.) Avoiding not cooling down the reaction mixture when preparing the diazonium salt e.) Cbvcarrow_forwardA 0.552-g sample of an unknown acid was dissolved in water to a total volume of 20.0 mL. This sample was titrated with 0.1103 M KOH. The equivalence point occurred at 29.42 mL base added. The pH of the solution at 10.0 mL base added was 3.72. Determine the molar mass of the acid. Determine the Ka of the acid.arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning





