The experiment to prove the hemoglobin a tetramer and not a enormous polypeptide chain is to be determined. Concept Introduction: The mass spectrum of the molecule having polypeptide chain give one large band and the molecule having subunits give small bands. To determine: The experiment to determine that the hemoglobin exists as a tetramer or as a polypeptide chain.

Question

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Answer 1

Question

Chapter 24, Problem 1DE

Interpretation Introduction

Interpretation: The experiment to prove the hemoglobin a tetramer and not a enormous polypeptide chain is to be determined.

Concept Introduction: The mass spectrum of the molecule having polypeptide chain give one large band and the molecule having subunits give small bands.

To determine: The experiment to determine that the hemoglobin exists as a tetramer or as a polypeptide chain.

Expert Solution & Answer

Answer to Problem 1DE

Solution: The mass spectrum of the hemoglobin solution gives two smaller bands which prove that it exists as a tetramer.

Explanation of Solution

The buffer solution of hemoglobin is prepared first. This buffer solution of hemoglobin is taken to obtain the mass spectrum of hemoglobin. The molecules which exist as the smaller subunits give multiple bands on the mass spectra. But the mass spectrum of hemoglobin gives two distinct bands one of alpha subunit and other of beta subunit. This proves that the hemoglobin molecule does not exist as the polypeptide chain but exist in the tetramer form.

Conclusion

The mass spectrum of the hemoglobin solution gives two smaller bands which prove that it exists as a tetramer.

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Answer 2

Question

Chapter 24, Problem 1DE

Interpretation Introduction

Interpretation: The experiment to prove the hemoglobin a tetramer and not a enormous polypeptide chain is to be determined.

Concept Introduction: The mass spectrum of the molecule having polypeptide chain give one large band and the molecule having subunits give small bands.

To determine: The experiment to determine that the hemoglobin exists as a tetramer or as a polypeptide chain.

Expert Solution & Answer

Answer to Problem 1DE

Solution: The mass spectrum of the hemoglobin solution gives two smaller bands which prove that it exists as a tetramer.

Explanation of Solution

The buffer solution of hemoglobin is prepared first. This buffer solution of hemoglobin is taken to obtain the mass spectrum of hemoglobin. The molecules which exist as the smaller subunits give multiple bands on the mass spectra. But the mass spectrum of hemoglobin gives two distinct bands one of alpha subunit and other of beta subunit. This proves that the hemoglobin molecule does not exist as the polypeptide chain but exist in the tetramer form.

Conclusion

The mass spectrum of the hemoglobin solution gives two smaller bands which prove that it exists as a tetramer.

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Answer 3

Question

Chapter 24, Problem 1DE

Interpretation Introduction

Interpretation: The experiment to prove the hemoglobin a tetramer and not a enormous polypeptide chain is to be determined.

Concept Introduction: The mass spectrum of the molecule having polypeptide chain give one large band and the molecule having subunits give small bands.

To determine: The experiment to determine that the hemoglobin exists as a tetramer or as a polypeptide chain.

Expert Solution & Answer

Answer to Problem 1DE

Solution: The mass spectrum of the hemoglobin solution gives two smaller bands which prove that it exists as a tetramer.

Explanation of Solution

The buffer solution of hemoglobin is prepared first. This buffer solution of hemoglobin is taken to obtain the mass spectrum of hemoglobin. The molecules which exist as the smaller subunits give multiple bands on the mass spectra. But the mass spectrum of hemoglobin gives two distinct bands one of alpha subunit and other of beta subunit. This proves that the hemoglobin molecule does not exist as the polypeptide chain but exist in the tetramer form.

Conclusion

The mass spectrum of the hemoglobin solution gives two smaller bands which prove that it exists as a tetramer.

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Answer 4

Question

Chapter 24, Problem 1DE

Interpretation Introduction

Interpretation: The experiment to prove the hemoglobin a tetramer and not a enormous polypeptide chain is to be determined.

Concept Introduction: The mass spectrum of the molecule having polypeptide chain give one large band and the molecule having subunits give small bands.

To determine: The experiment to determine that the hemoglobin exists as a tetramer or as a polypeptide chain.

Expert Solution & Answer

Answer to Problem 1DE

Solution: The mass spectrum of the hemoglobin solution gives two smaller bands which prove that it exists as a tetramer.

Explanation of Solution

The buffer solution of hemoglobin is prepared first. This buffer solution of hemoglobin is taken to obtain the mass spectrum of hemoglobin. The molecules which exist as the smaller subunits give multiple bands on the mass spectra. But the mass spectrum of hemoglobin gives two distinct bands one of alpha subunit and other of beta subunit. This proves that the hemoglobin molecule does not exist as the polypeptide chain but exist in the tetramer form.

Conclusion

The mass spectrum of the hemoglobin solution gives two smaller bands which prove that it exists as a tetramer.

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Answer 5

Chapter 24, Problem 1DE

Interpretation Introduction

Interpretation: The experiment to prove the hemoglobin a tetramer and not a enormous polypeptide chain is to be determined.

Concept Introduction: The mass spectrum of the molecule having polypeptide chain give one large band and the molecule having subunits give small bands.

To determine: The experiment to determine that the hemoglobin exists as a tetramer or as a polypeptide chain.

Expert Solution & Answer

Answer to Problem 1DE

Solution: The mass spectrum of the hemoglobin solution gives two smaller bands which prove that it exists as a tetramer.

Explanation of Solution

The buffer solution of hemoglobin is prepared first. This buffer solution of hemoglobin is taken to obtain the mass spectrum of hemoglobin. The molecules which exist as the smaller subunits give multiple bands on the mass spectra. But the mass spectrum of hemoglobin gives two distinct bands one of alpha subunit and other of beta subunit. This proves that the hemoglobin molecule does not exist as the polypeptide chain but exist in the tetramer form.

Conclusion

The mass spectrum of the hemoglobin solution gives two smaller bands which prove that it exists as a tetramer.

Answer 6

Chapter 24, Problem 1DE

Interpretation Introduction

Interpretation: The experiment to prove the hemoglobin a tetramer and not a enormous polypeptide chain is to be determined.

Concept Introduction: The mass spectrum of the molecule having polypeptide chain give one large band and the molecule having subunits give small bands.

To determine: The experiment to determine that the hemoglobin exists as a tetramer or as a polypeptide chain.

Expert Solution & Answer

Answer to Problem 1DE

Solution: The mass spectrum of the hemoglobin solution gives two smaller bands which prove that it exists as a tetramer.

Explanation of Solution

The buffer solution of hemoglobin is prepared first. This buffer solution of hemoglobin is taken to obtain the mass spectrum of hemoglobin. The molecules which exist as the smaller subunits give multiple bands on the mass spectra. But the mass spectrum of hemoglobin gives two distinct bands one of alpha subunit and other of beta subunit. This proves that the hemoglobin molecule does not exist as the polypeptide chain but exist in the tetramer form.

Conclusion

The mass spectrum of the hemoglobin solution gives two smaller bands which prove that it exists as a tetramer.

Answer 7

Chapter 24, Problem 1DE

Interpretation Introduction

Interpretation: The experiment to prove the hemoglobin a tetramer and not a enormous polypeptide chain is to be determined.

Concept Introduction: The mass spectrum of the molecule having polypeptide chain give one large band and the molecule having subunits give small bands.

To determine: The experiment to determine that the hemoglobin exists as a tetramer or as a polypeptide chain.

Answer 8

Expert Solution & Answer

Answer to Problem 1DE

Solution: The mass spectrum of the hemoglobin solution gives two smaller bands which prove that it exists as a tetramer.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

The buffer solution of hemoglobin is prepared first. This buffer solution of hemoglobin is taken to obtain the mass spectrum of hemoglobin. The molecules which exist as the smaller subunits give multiple bands on the mass spectra. But the mass spectrum of hemoglobin gives two distinct bands one of alpha subunit and other of beta subunit. This proves that the hemoglobin molecule does not exist as the polypeptide chain but exist in the tetramer form.