Concept explainers
(a)
The maximum luminosity that could be produced by accretion onto a black hole of
(a)

Answer to Problem 13Q
Solution:
The maximum luminosity that can be produced due to accretion onto a black hole is
As compared to the luminosity of the Milky Way, the luminosity is
Explanation of Solution
Given data:
The size of the black hole found at the center of the Milky Way is
The luminosity of the Milky Way is
Formula used:
The maximum luminosity that can be radiated by accretion around a black hole is:
Here,
Explanation:
Recall the expression for the maximum luminosity that can be radiated by accretion around a black hole.
Substitute
The ratio of the luminosity of the black hole to the luminosity of the Milky Way will be:
Substitute
Conclusion:
Therefore, the maximum luminosity that can be radiated by accretion around a black hole is
(b)
The observation if the center of our galaxy becomes an active galactic nucleus with the luminosity observed in sub-part (a).
(b)

Answer to Problem 13Q
Solution:
As the
Explanation of Solution
Introduction:
If the luminosity increases, it would create a lot of radiation pressure. Due to this, the surrounding gas will be pushed outward, rather than falling inward and it would blow away the accreting gas.
Explanation:
Refer the value of luminosity from sub-part (a), that is, 4.44 times the luminosity of the Milky Way galaxy. When the Milky Way galaxy became a galactic active nucleus with this luminosity, the balance between the radiation pushing gas fuel outward and gravity pushing the gas inward would become imbalanced.
This would result in an increase of radiation pressure, due to which the surrounding gas is pushed outward rather than falling inward and it would blow away the accreting gas. So, the mass of the center must be quite large to keep pulling in gases.
Conclusion:
Therefore, the increase in luminosity would cause the intensity to increase from the direction of the Milky Way’s center at all wavelengths.
Want to see more full solutions like this?
Chapter 24 Solutions
EBK LOOSE-LEAF VERSION OF UNIVERSE
- Include free body diagramarrow_forward2 Spring 2025 -03 PITT Calculate the acceleration of a skier heading down a 10.0° slope, assuming the coefficient of cold coast at a constant velocity. You can neglect air resistance in both parts. friction for waxed wood on wet snow fly 0.1 (b) Find the angle of the slope down which this skier Given: 9 = ? 8=10° 4=0.1arrow_forwarddry 5. (a) When rebuilding her car's engine, a physics major must exert 300 N of force to insert a c piston into a steel cylinder. What is the normal force between the piston and cyli=030 What force would she have to exert if the steel parts were oiled? k F = 306N 2 =0.03 (arrow_forward
- Include free body diagramarrow_forwardInclude free body diagramarrow_forwardTest 2 МК 02 5. (a) When rebuilding her car's engine, a physics major must exert 300 N of force to insert a dry = 0.03 (15 pts) piston into a steel cylinder. What is the normal force between the piston and cylinder? What force would she have to exert if the steel parts were oiled? Mk Giren F = 306N MK-0.3 UK = 0.03 NF = ?arrow_forward
- 2. A powerful motorcycle can produce an acceleration of 3.50 m/s² while traveling at 90.0 km/h. At that speed the forces resisting motion, including friction and air resistance, total 400 N. (Air resistance is analogous to air friction. It always opposes the motion of an object.) What force does the motorcycle exert backward on the ground to produce its acceleration if the mass of the motorcycle with rider is 245 ke? a = 350 m/s 2arrow_forward2. A powerful motorcycle can produce an acceleration of 3.50 m/s² while traveling at 90.0 km/h. At that speed the forces resisting motion, including friction and air resistance, total 400 N. (Air resistance is analogous to air friction. It always opposes the motion of an object.) What force does the motorcycle exert backward on the ground to produce its acceleration if the mass of the motorcycle with rider is 245 kg? (10 pts) a = 3.50 m/s 2 distance 90 km/h = 3.50m/62 M = 245garrow_forwardUsing Table 17-4, determine the approximate temperature of metal that has formed a dark blue color.arrow_forward
- A positively charged disk has a uniform charge per unit area σ. dq R P x The total electric field at P is given by the following. Ek [2 - x (R² + x2) 1/2 Sketch the electric field lines in a plane perpendicular to the plane of the disk passing through its center.arrow_forwardConsider a closed triangular box resting within a horizontal electric field of magnitude E = 8.02 104 N/C as shown in the figure below. A closed right triangular box with its vertical side on the left and downward slope on the right rests within a horizontal electric field vector E that points from left to right. The box has a height of 10.0 cm and a depth of 30.0 cm. The downward slope of the box makes an angle of 60 degrees with the vertical. (a) Calculate the electric flux through the vertical rectangular surface of the box. kN · m2/C(b) Calculate the electric flux through the slanted surface of the box. kN · m2/C(c) Calculate the electric flux through the entire surface of the box. kN · m2/Carrow_forwardThe figure below shows, at left, a solid disk of radius R = 0.600 m and mass 75.0 kg. Tu Mounted directly to it and coaxial with it is a pulley with a much smaller mass and a radius of r = 0.230 m. The disk and pulley assembly are on a frictionless axle. A belt is wrapped around the pulley and connected to an electric motor as shown on the right. The turning motor gives the disk and pulley a clockwise angular acceleration of 1.67 rad/s². The tension T in the upper (taut) segment of the belt is 145 N. (a) What is the tension (in N) in the lower (slack) segment of the belt? N (b) What If? You replace the belt with a different one (one slightly longer and looser, but still tight enough that it does not sag). You again turn on the motor so that the disk accelerates clockwise. The upper segment of the belt once again has a tension of 145 N, but now the tension in the lower belt is exactly zero. What is the magnitude of the angular acceleration (in rad/s²)? rad/s²arrow_forward
- AstronomyPhysicsISBN:9781938168284Author:Andrew Fraknoi; David Morrison; Sidney C. WolffPublisher:OpenStaxStars and Galaxies (MindTap Course List)PhysicsISBN:9781337399944Author:Michael A. SeedsPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
- Foundations of Astronomy (MindTap Course List)PhysicsISBN:9781337399920Author:Michael A. Seeds, Dana BackmanPublisher:Cengage LearningStars and GalaxiesPhysicsISBN:9781305120785Author:Michael A. Seeds, Dana BackmanPublisher:Cengage Learning





