CALCULUS:GRAPHICAL...,AP ED.-W/ACCESS
5th Edition
ISBN: 9780133314564
Author: Finney
Publisher: SAVVAS L
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Find the slope of the tangent line to the graph of f(x) = 5x at the point (4,80).
а.
b. Find the slope-intercept equation of the tangent line to the graph of f(x) = 5x at the point (4,80).
a. What is the slope of the tangent line?
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b. Complete the slope-intercept equation of the tangent line below.
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I need help solving normal line.
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- Part 2. Math column A to column B by finding the slope of tangent line at any given point and write the letter of your answer on the space provided. Column A Column B A. y = 2x - 7 1. y 4x2- 4x +1 at point (1,1) B. y = x-9 2x-5 _2. y = at point (1,5) 7-2x C. y = * 3. у %3D х +3 at point (4,1) D. y = 2x - 10 4. y = x² - 4 at point (-2,-4) E. y = 2 5. у %3D Зх — 5 at point (-2,3) F. y = 3x - 5 6. y = 4x2 + 2 at point (0,0) G. y = -4x-8 7. y = 2x- 10 at point (4,2) H. y = x+ 3 8. y = x+4 at point (-2,-) X-4 I. y = 5x -9 %3D 9.y x-9 at point (3,1) J. y = 4x- 3 10. y = x2 - 6 at point (1,2)arrow_forwardOnly need parts f. and g. Needed info in first picture. Questions in second picture.arrow_forwardven slope and y-intercept. 8. slope: --: y-intercept: -12 10. slope: -3 : y-intercept:- -intercept form. y 13. (0, 3) 2. 4. 234 5arrow_forward
- Ohm's law states that the voltage drop Vacross an ideal resistor is linearly proportional to the current i flowing through the resistor as V= iR. Where R is the resistance. However, real resistors may not always obey Ohm's law. Suppose that you perform some very precise experiments to measure the voltage drop and the corresponding current for a resistor. The following results suggest a curvilinear relationship rather than the straight line represented by Ohm's law. i -1 - 0.5 - 0.25 0.25 0.5 1 V -637 -96.5 -20.25 20.5 96.5 637 Instead of the typical linear regression method for analyzing such experimental data, fit a curve to the data to quantify the relationship. Compute V for i = 0.1 using Polynomial Interpolation.arrow_forwardOhm's law states that the voltage drop Vacross an ideal resistor is linearly proportional to the current i flowing through the resistor as V= iR. Where R is the resistance. However, real resistors may not always obey Ohm's law. Suppose that you perform some very precise experiments to measure the voltage drop and the corresponding current for a resistor. The following results suggest a curvilinear relationship rather than the straight line represented by Ohm's law. i -1 - 0.5 - 0.25 0.25 0.5 1 V -637 -96.5 -20.25 20.5 96.5 637 Instead of the typical linear regression method for analyzing such experimental data, fit a curve to the data to quantify the relationship. Compute V for i = 0.1 using Newton's Divided Difference Method.arrow_forwardCan you help me number 6. Finding normal.arrow_forward
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