Explanation Given Information: The provided equation is: 2 5 z − 1 4 = 3 10 z + 1 2 Formula used: To solve a linear equation in one variable follow the steps below: Step 1. First simplify both sides of the linear equation. a) Remove the parentheses. b) Multiply both side of the equation with the common denominator of all the terms to clear fraction and decimal (if any are present). c) Write all the like terms on one side. Step 2. Apply the addition or subtraction property of equality to obtain the variable terms on one side of the equation. Step 3. Apply the addition or subtraction property of equality to obtain the constant terms on the other side of the equation. Step 4. Apply the multiplication or division property of equality to make the coefficient of the variable term equal to 1. Step 5. Check the Answer by substituting the obtained value. The distributive property is a ( b + c ) = a b + a c . Calculation: Consider the provided equation: 2 5 z − 1 4 = 3 10 z + 1 2 The LCD (Least Common Denominator) of 2 5 z , 1 4 , 3 10 z , 1 2 is 20 . So multiply both sides by 20 as: 20 ( 2 5 z − 1 4 ) = 20 ( 3 10 z + 1 2 ) Now apply Distributive Property as: 20 ( 2 5 z ) − 20 ( 1 4 )

6th Edition

ISBN: 9781260673531

Author: Miller, Julie, O'Neill, Molly, Hyde, Nancy

Publisher: McGraw-Hill Education

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Chapter 2.3, Problem 64PE

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To calculate: The solution of the linear equation 25z−14=310z+12.

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Chapter 2.3, Problem 63PE

Chapter 2.3, Problem 65PE

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The solution of the linear equation 2 5 z − 1 4 = 3 10 z + 1 2 .

Solution Summary: The author explains how to solve a linear equation in one variable.

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To calculate: The solution of the linear equation 25z−14=310z+12.

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