APPLIED CALCULUS-PRINT COMPANION (LL)
6th Edition
ISBN: 9781119275565
Author: Hughes-Hallett
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 2.3, Problem 53P
To determine
(a)
To estimate:
The rate of fat consumption after 3 weeks.
To determine
(b)
To estimate:
The rate of fat consumption after 6 weeks.
To determine
(c)
To estimate:
The rate of fat consumption after 8 weeks.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
3.12 (B). A horizontal beam AB is 4 m
long and of constant flexural rigidity. It is
rigidly built-in at the left-hand end A and simply supported on a non-yielding support
at the right-hand end B. The beam carries Uniformly distributed vertical loading of
18 kN/m over its whole length, together with a vertical downward load of 10KN at
2.5 m from the end A. Sketch the S.F. and B.M. diagrams for the beam, indicating
all main values. Cl. Struct. E.] CS.F. 45,10,376 KN, B.M. 186, +36.15 kNm.7
Qize
f(x)
=
x + 2x2 - 2
x² + 4x²² -
Solve the equation using Newton
Raphson
-b±√√b2-4ac
2a
@4x²-12x+9=0
27 de febrero de 2025
-b±√√b2-4ac
2a
⑥2x²-4x-1=0
a = 4 b=-12
c=9
a = 2
b = 9
c = \
x=-42±√(2-4 (4) (9)
2(4))
X =
(12) ±√44)-(360)
2(108)
x = ±√
X = =±√√²-4(2) (1)
2()
X = ±√
+
X =
X =
+
X₁ =
=
X₁ =
X₁ =
+
X₁ =
=
=
Chapter 2 Solutions
APPLIED CALCULUS-PRINT COMPANION (LL)
Ch. 2.1 - Prob. 1PCh. 2.1 - Prob. 2PCh. 2.1 - Prob. 3PCh. 2.1 - Prob. 4PCh. 2.1 - Prob. 5PCh. 2.1 - Prob. 6PCh. 2.1 - Prob. 7PCh. 2.1 - Prob. 8PCh. 2.1 - Prob. 9PCh. 2.1 - Prob. 10P
Ch. 2.1 - Prob. 11PCh. 2.1 - Prob. 12PCh. 2.1 - Prob. 13PCh. 2.1 - Prob. 14PCh. 2.1 - Prob. 15PCh. 2.1 - Prob. 16PCh. 2.1 - Prob. 17PCh. 2.1 - Prob. 18PCh. 2.1 - Prob. 19PCh. 2.1 - Prob. 20PCh. 2.1 - Prob. 21PCh. 2.1 - Prob. 22PCh. 2.1 - Prob. 23PCh. 2.1 - Prob. 24PCh. 2.1 - Prob. 25PCh. 2.1 - Prob. 26PCh. 2.1 - Prob. 27PCh. 2.1 - Prob. 28PCh. 2.1 - Prob. 29PCh. 2.1 - Prob. 30PCh. 2.1 - Prob. 31PCh. 2.1 - Prob. 32PCh. 2.1 - Prob. 33PCh. 2.1 - Prob. 34PCh. 2.1 - Prob. 35PCh. 2.1 - Prob. 36PCh. 2.1 - Prob. 37PCh. 2.1 - Prob. 38PCh. 2.1 - Prob. 39PCh. 2.1 - Prob. 40PCh. 2.1 - Prob. 41PCh. 2.2 - Prob. 1PCh. 2.2 - Prob. 2PCh. 2.2 - Prob. 3PCh. 2.2 - Prob. 4PCh. 2.2 - Prob. 5PCh. 2.2 - Prob. 6PCh. 2.2 - Prob. 7PCh. 2.2 - Prob. 8PCh. 2.2 - Prob. 9PCh. 2.2 - Prob. 10PCh. 2.2 - Prob. 11PCh. 2.2 - Prob. 12PCh. 2.2 - Prob. 13PCh. 2.2 - Prob. 14PCh. 2.2 - Prob. 15PCh. 2.2 - Prob. 16PCh. 2.2 - Prob. 17PCh. 2.2 - Prob. 18PCh. 2.2 - Prob. 19PCh. 2.2 - Prob. 20PCh. 2.2 - Prob. 21PCh. 2.2 - Prob. 22PCh. 2.2 - Prob. 23PCh. 2.2 - Prob. 24PCh. 2.2 - Prob. 25PCh. 2.2 - Prob. 26PCh. 2.2 - Prob. 27PCh. 2.2 - Prob. 28PCh. 2.2 - Prob. 29PCh. 2.2 - Prob. 30PCh. 2.2 - Prob. 31PCh. 2.2 - Prob. 32PCh. 2.2 - Prob. 33PCh. 2.2 - Prob. 34PCh. 2.2 - Prob. 35PCh. 2.3 - Prob. 1PCh. 2.3 - Prob. 2PCh. 2.3 - Prob. 3PCh. 2.3 - Prob. 4PCh. 2.3 - Prob. 5PCh. 2.3 - Prob. 6PCh. 2.3 - Prob. 7PCh. 2.3 - Prob. 8PCh. 2.3 - Prob. 9PCh. 2.3 - Prob. 10PCh. 2.3 - Prob. 11PCh. 2.3 - Prob. 12PCh. 2.3 - Prob. 13PCh. 2.3 - Prob. 14PCh. 2.3 - Prob. 15PCh. 2.3 - Prob. 16PCh. 2.3 - Prob. 17PCh. 2.3 - Prob. 18PCh. 2.3 - Prob. 19PCh. 2.3 - Prob. 20PCh. 2.3 - Prob. 21PCh. 2.3 - Prob. 22PCh. 2.3 - Prob. 23PCh. 2.3 - Prob. 24PCh. 2.3 - Prob. 25PCh. 2.3 - Prob. 26PCh. 2.3 - Prob. 27PCh. 2.3 - Prob. 28PCh. 2.3 - Prob. 29PCh. 2.3 - Prob. 30PCh. 2.3 - Prob. 31PCh. 2.3 - Prob. 32PCh. 2.3 - Prob. 33PCh. 2.3 - Prob. 34PCh. 2.3 - Prob. 35PCh. 2.3 - Prob. 36PCh. 2.3 - Prob. 37PCh. 2.3 - Prob. 38PCh. 2.3 - Prob. 39PCh. 2.3 - Prob. 40PCh. 2.3 - Prob. 41PCh. 2.3 - Prob. 42PCh. 2.3 - Prob. 43PCh. 2.3 - Prob. 44PCh. 2.3 - Prob. 45PCh. 2.3 - Prob. 46PCh. 2.3 - Prob. 47PCh. 2.3 - Prob. 48PCh. 2.3 - Prob. 49PCh. 2.3 - Prob. 50PCh. 2.3 - Prob. 51PCh. 2.3 - Prob. 52PCh. 2.3 - Prob. 53PCh. 2.3 - Prob. 54PCh. 2.3 - Prob. 55PCh. 2.3 - Prob. 56PCh. 2.3 - Prob. 57PCh. 2.3 - Prob. 58PCh. 2.3 - Prob. 59PCh. 2.3 - Prob. 60PCh. 2.3 - Prob. 61PCh. 2.3 - Prob. 62PCh. 2.3 - Prob. 63PCh. 2.3 - Prob. 64PCh. 2.3 - Prob. 65PCh. 2.3 - Prob. 66PCh. 2.3 - Prob. 67PCh. 2.3 - Prob. 68PCh. 2.3 - Prob. 69PCh. 2.4 - Prob. 1PCh. 2.4 - Prob. 2PCh. 2.4 - Prob. 3PCh. 2.4 - Prob. 4PCh. 2.4 - Prob. 5PCh. 2.4 - Prob. 6PCh. 2.4 - Prob. 7PCh. 2.4 - Prob. 8PCh. 2.4 - Prob. 9PCh. 2.4 - Prob. 10PCh. 2.4 - Prob. 11PCh. 2.4 - Prob. 12PCh. 2.4 - Prob. 13PCh. 2.4 - Prob. 14PCh. 2.4 - Prob. 15PCh. 2.4 - Prob. 16PCh. 2.4 - Prob. 17PCh. 2.4 - Prob. 18PCh. 2.4 - Prob. 19PCh. 2.4 - Prob. 20PCh. 2.4 - Prob. 21PCh. 2.4 - Prob. 22PCh. 2.4 - Prob. 23PCh. 2.4 - Prob. 24PCh. 2.4 - Prob. 25PCh. 2.4 - Prob. 26PCh. 2.4 - Prob. 27PCh. 2.4 - Prob. 28PCh. 2.4 - Prob. 29PCh. 2.4 - Prob. 30PCh. 2.4 - Prob. 31PCh. 2.4 - Prob. 32PCh. 2.4 - Prob. 33PCh. 2.4 - Prob. 34PCh. 2.4 - Prob. 35PCh. 2.4 - Prob. 36PCh. 2.5 - Prob. 1PCh. 2.5 - Prob. 2PCh. 2.5 - Prob. 3PCh. 2.5 - Prob. 4PCh. 2.5 - Prob. 5PCh. 2.5 - Prob. 6PCh. 2.5 - Prob. 7PCh. 2.5 - Prob. 8PCh. 2.5 - Prob. 9PCh. 2.5 - Prob. 10PCh. 2.5 - Prob. 11PCh. 2.5 - Prob. 12PCh. 2.5 - Prob. 13PCh. 2.5 - Prob. 14PCh. 2.5 - Prob. 15PCh. 2.5 - Prob. 16PCh. 2.5 - Prob. 17PCh. 2.5 - Prob. 18PCh. 2.5 - Prob. 19PCh. 2 - Prob. 1SYUCh. 2 - Prob. 2SYUCh. 2 - Prob. 3SYUCh. 2 - Prob. 4SYUCh. 2 - Prob. 5SYUCh. 2 - Prob. 6SYUCh. 2 - Prob. 7SYUCh. 2 - Prob. 8SYUCh. 2 - Prob. 9SYUCh. 2 - Prob. 10SYUCh. 2 - Prob. 11SYUCh. 2 - Prob. 12SYUCh. 2 - Prob. 13SYUCh. 2 - Prob. 14SYUCh. 2 - Prob. 15SYUCh. 2 - Prob. 16SYUCh. 2 - Prob. 17SYUCh. 2 - Prob. 18SYUCh. 2 - Prob. 19SYUCh. 2 - Prob. 20SYUCh. 2 - Prob. 21SYUCh. 2 - Prob. 22SYUCh. 2 - Prob. 23SYUCh. 2 - Prob. 24SYUCh. 2 - Prob. 25SYUCh. 2 - Prob. 26SYUCh. 2 - Prob. 27SYUCh. 2 - Prob. 28SYUCh. 2 - Prob. 29SYUCh. 2 - Prob. 30SYUCh. 2 - Prob. 31SYUCh. 2 - Prob. 32SYUCh. 2 - Prob. 33SYUCh. 2 - Prob. 34SYUCh. 2 - Prob. 35SYUCh. 2 - Prob. 36SYUCh. 2 - Prob. 37SYUCh. 2 - Prob. 38SYUCh. 2 - Prob. 39SYUCh. 2 - Prob. 40SYUCh. 2 - Prob. 41SYUCh. 2 - Prob. 42SYUCh. 2 - Prob. 43SYUCh. 2 - Prob. 44SYUCh. 2 - Prob. 45SYUCh. 2 - Prob. 46SYUCh. 2 - Prob. 47SYUCh. 2 - Prob. 48SYUCh. 2 - Prob. 49SYUCh. 2 - Prob. 50SYUCh. 2 - Prob. 51SYUCh. 2 - Prob. 52SYUCh. 2 - Prob. 53SYUCh. 2 - Prob. 54SYUCh. 2 - Prob. 55SYUCh. 2 - Prob. 1FOTCh. 2 - Prob. 2FOTCh. 2 - Prob. 3FOTCh. 2 - Prob. 4FOTCh. 2 - Prob. 5FOTCh. 2 - Prob. 6FOTCh. 2 - Prob. 7FOTCh. 2 - Prob. 8FOTCh. 2 - Prob. 9FOTCh. 2 - Prob. 10FOTCh. 2 - Prob. 11FOTCh. 2 - Prob. 12FOTCh. 2 - Prob. 13FOTCh. 2 - Prob. 14FOTCh. 2 - Prob. 15FOTCh. 2 - Prob. 16FOTCh. 2 - Prob. 17FOTCh. 2 - Prob. 18FOTCh. 2 - Prob. 19FOTCh. 2 - Prob. 20FOTCh. 2 - Prob. 21FOTCh. 2 - Prob. 22FOTCh. 2 - Prob. 23FOTCh. 2 - Prob. 24FOTCh. 2 - Prob. 25FOTCh. 2 - Prob. 26FOTCh. 2 - Prob. 27FOTCh. 2 - Prob. 28FOTCh. 2 - Prob. 29FOTCh. 2 - Prob. 30FOTCh. 2 - Prob. 31FOTCh. 2 - Prob. 32FOTCh. 2 - Prob. 33FOTCh. 2 - Prob. 34FOTCh. 2 - Prob. 35FOTCh. 2 - Prob. 36FOTCh. 2 - Prob. 37FOTCh. 2 - Prob. 38FOTCh. 2 - Prob. 39FOTCh. 2 - Prob. 40FOTCh. 2 - Prob. 41FOTCh. 2 - Prob. 42FOTCh. 2 - Prob. 43FOT
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.Similar questions
- 3.9 (A/B). A beam ABCDE, with A on the left, is 7 m long and is simply supported at Band E. The lengths of the various portions are AB 1-5m, BC = 1-5m, CD = 1 m and DE : 3 m. There is a uniformly distributed load of 15kN/m between B and a point 2m to the right of B and concentrated loads of 20 KN act at 4 and 0 with one of 50 KN at C. (a) Draw the S.F. diagrams and hence determine the position from A at which the S.F. is zero. (b) Determine the value of the B.M. at this point. (c) Sketch the B.M. diagram approximately to scale, quoting the principal values. [3.32 m, 69.8 KNm, 0, 30, 69.1, 68.1, 0 kNm.]arrow_forward4. Verify that V X (aẢ) = (Va) XẢ + aV X Ả where Ả = xyz(x + y + 2) A and a = 3xy + 4zx by carrying out the detailed differentiations.arrow_forward3. For each of the arrow or quiver graphs shown below, determine analytically V°C and V X Č. From these analytical solutions, identify the extrema (+/-) and plot these points on the arrow graph. (a) C = −✰CosxSiny + ŷSinxCosy -π<ׂу<π Ty (b) C = −xSin2y + ŷCos2y x, y<π -π< (c) C = −xCosx + ŷSiny -π< x, y < πarrow_forward
- 7.10 (B/C). A circular flat plate of diameter 305 mm and thickness 6.35 mm is clamped at the edges and subjected to a Uniform lateral pressure of 345 kN/m². Evaluate: (a) the central deflection, (b) the position and magnitude of the maximum radial stress. C6.1 x 10 m; 149.2 MN/m².] 100 200arrow_forward3.15 (B). A beam ABCD is simply supported at B and C with ABCD=2m; BC 4 m. It carries a point load of 60 KN at the free end A, a Uniformly distributed load of 60 KN/m between B and C and an anticlockwise moment of 80 KN m in the plane of the beam applied at the free end D. Sketch and dimension the S.F. and B.M. diagrams, and determine the position and magnitude of the maximum bending moment. CEL.E.] CS.F. 60, 170, 70KN, B.M. 120, +120.1, +80 kNm, 120.1 kNm at 2.83 m to right of 8.7arrow_forward7.1 (A/B). A Uniform I-section beam has flanges 150 mm wide by 8 mm thick and a web 180 mm wide and 8 mm thick. At a certain section there is a shearing force of 120 KN. Draw a diagram to illustrate the distribution of shear stress across the section as a result of bending. What is the maximum shear stress? [86.7 MN/m².arrow_forward
- 1. Let Ả = −2x + 3y+42, B = - - 7x +lý +22, and C = −1x + 2y + 42. Find (a) Ả X B (b) ẢX B°C c) →→ Ả B X C d) ẢB°C e) ẢX B XC.arrow_forward3.13 (B). A beam ABC, 6 m long, is simply-supported at the left-hand end A and at B I'm from the right-hand end C. The beam is of weight 100 N/metre run. (a) Determine the reactions at A and B. (b) Construct to scales of 20 mm = 1 m and 20 mm = 100 N, the shearing-force diagram for the beam, indicating thereon the principal values. (c) Determine the magnitude and position of the maximum bending moment. (You may, if you so wish, deduce the answers from the shearing force diagram without constructing a full or partial bending-moment diagram.) [C.G.] C240 N, 360 N, 288 Nm, 2.4 m from A.]arrow_forward5. Using parentheses make sense of the expression V · VXVV · Å where Ả = Ã(x, y, z). Is the result a vector or a scaler?arrow_forward
- 3.10 (A/B). A beam ABCDE is simply supported at A and D. It carries the following loading: a distributed load of 30 kN/m between A and B, a concentrated load of 20 KN at B, a concentrated load of 20 KN at C, a concentrated load of 10 KN at E; a distributed load of 60 kN/m between 0 and E. Span AB = 1.5 BC = CD = DE 1 m. Calculate the value of the reactions at A and D and hence draw the S.F. and B.M. diagrams. What are the magnitude and position of the maximum B.M. on the beam? [41.1, 113.9 KN, 28.15 kNm; 1.37 m from A.J m,arrow_forward3.14 (B). A beam ABCD, 6 m long, is simply-supported at the right-hand end and at a point B Im from the left-hand end A. It carries a vertical load of 10 KN at A, a second concentrated load of 20 KN at C, 3 m from D, and a uniformly distributed load of 10 kN/m between C and D. Determine: (a) the values of the reactions at B and 0, (6) the position and magnitude of the maximum bending moment. [33 KN, 27 KN, 2.7 m from D, 36.45k Nm.]arrow_forward3.17 (B). A simply supported beam has a span of 6 m and carries a distributed load which varies in a linea manner from 30 kN/m at one support to 90 kN/m at the other support. Locate the point of maximum bendin moment and calculate the value of this maximum. Sketch the S.F. and B.M. diagrams. [U.L.] [3.25 m from l.h. end; 272 KN m 30. 90arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill
College Algebra (MindTap Course List)AlgebraISBN:9781305652231Author:R. David Gustafson, Jeff HughesPublisher:Cengage Learning
Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:Cengage
Functions and Change: A Modeling Approach to Coll...AlgebraISBN:9781337111348Author:Bruce Crauder, Benny Evans, Alan NoellPublisher:Cengage Learning
Mathematics For Machine TechnologyAdvanced MathISBN:9781337798310Author:Peterson, John.Publisher:Cengage Learning,
Linear Algebra: A Modern IntroductionAlgebraISBN:9781285463247Author:David PoolePublisher:Cengage Learning
Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill
College Algebra (MindTap Course List)
Algebra
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:Cengage Learning
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:9781133382119
Author:Swokowski
Publisher:Cengage
Functions and Change: A Modeling Approach to Coll...
Algebra
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Cengage Learning
Mathematics For Machine Technology
Advanced Math
ISBN:9781337798310
Author:Peterson, John.
Publisher:Cengage Learning,
Linear Algebra: A Modern Introduction
Algebra
ISBN:9781285463247
Author:David Poole
Publisher:Cengage Learning
Continuous Probability Distributions - Basic Introduction; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=QxqxdQ_g2uw;License: Standard YouTube License, CC-BY
Probability Density Function (p.d.f.) Finding k (Part 1) | ExamSolutions; Author: ExamSolutions;https://www.youtube.com/watch?v=RsuS2ehsTDM;License: Standard YouTube License, CC-BY
Find the value of k so that the Function is a Probability Density Function; Author: The Math Sorcerer;https://www.youtube.com/watch?v=QqoCZWrVnbA;License: Standard Youtube License